Using OpenXML to insert a datatable into excel - asp.net

Question

I have a datatable that - depending on the user selection - will generate a dynamic datatable with any number of rows and columns. I'm currently using OpenXml to manipulate said spreadsheet. How would I go about inserting a datatable?
Thanks
Stu

Answer 1

I found some code which I was able to modify to suit my needs. Hope someone finds this useful.
public void ExportDataTable(System.Data.DataTable exportData, SheetData sheetData)
{
//add column names to the first row
Row header = new Row();
header.RowIndex = (UInt32)42;
SheetData sheetData2 = new SheetData();
foreach (DataColumn column in exportData.Columns)
{
Cell headerCell = createTextCell(exportData.Columns.IndexOf(column) + 1, Convert.ToInt32(header.RowIndex.Value), column.ColumnName);
header.AppendChild(headerCell);
}
sheetData.AppendChild(header);
//loop through each data row
DataRow contentRow;
int startRow = 43;
for (int i = 0; i < exportData.Rows.Count; i++)
{
contentRow = exportData.Rows[i];
sheetData.AppendChild(createContentRow(contentRow, i + startRow));
}
}
private Cell createTextCell(int columnIndex, int rowIndex, object cellValue)
{
Cell cell = new Cell();
cell.DataType = CellValues.InlineString;
cell.CellReference = getColumnName(columnIndex) + rowIndex;
InlineString inlineString = new InlineString();
Text t = new Text();
t.Text = cellValue.ToString();
inlineString.AppendChild(t);
cell.AppendChild(inlineString);
return cell;
}
private Row createContentRow(DataRow dataRow, int rowIndex)
{
Row row = new Row
{
RowIndex = (UInt32)rowIndex
};
for (int i = 0; i < dataRow.Table.Columns.Count; i++)
{
Cell dataCell = createTextCell(i + 1, rowIndex, dataRow[i]);
row.AppendChild(dataCell);
}
return row;
}
private string getColumnName(int columnIndex)
{
int dividend = columnIndex;
string columnName = String.Empty;
int modifier;
while (dividend > 0)
{
modifier = (dividend - 1) % 26;
columnName = Convert.ToChar(65 + modifier).ToString() + columnName;
dividend = (int)((dividend - modifier) / 26);
}
return columnName;
}