Need first day of last month and Last day of next month from current date in Asp.Net
Eg : Current date 02/12/2019
first day of last month = 01/11/2019
Last day of next month = 31/01/2020
var myDate = DateTime.Now;
var firstDateOfLastMonth = myDate.AddMonths(-1);
firstDateOfLastMonth = firstDateOfLastMonth.AddDays(-firstDateOfLastMonth.Day + 1);
var lastDayOfNextMonth = myDate.AddMonths(1);
lastDayOfNextMonth = new DateTime(lastDayOfNextMonth.Year, lastDayOfNextMonth.Month, DateTime.DaysInMonth(lastDayOfNextMonth.Year, lastDayOfNextMonth.Month));
You may have to refer DataTime C# for more info
please try below line of code:
DateTime lastMonthdate = DateTime.Now.AddMonths(-1);
var lastMonth = new DateTime(lastMonthdate.Year, lastMonthdate.Month, 1);
var lastDayOfNextMonth = lastMonth.AddYears(1).AddMonths(1).AddDays(-1);
I have a date returned by a json, it is in the following variable as string:
val dateEvent = "2019-12-28 21:00:00"
The calculation I need is to know how many days hours minutes are left with the current date.
I have found some solutions but these use as input "2019-12-28" and I have my format with the time included.
java.time
Since Java 9 you can do (sorry that I can write only Java code):
DateTimeFormatter jsonFormatter = DateTimeFormatter.ofPattern("u-M-d H:mm:ss");
String dateEvent = "2019-12-28 21:00:00";
Instant eventTime = LocalDateTime.parse(dateEvent, jsonFormatter)
.atOffset(ZoneOffset.UTC)
.toInstant();
Duration timeLeft = Duration.between(Instant.now(), eventTime);
System.out.format("%d days %d hours %d minutes%n",
timeLeft.toDays(), timeLeft.toHoursPart(), timeLeft.toMinutesPart());
When I ran the code just now, the output was:
145 days 4 hours 19 minutes
In Java 6, 7 and 8 the formatting of the duration is a bit more wordy, search for how.
Avoid SimpleDateFormat and friends
The SimpleDateFormat and Date classes used in the other answer are poorly designed and long outdated. In my most honest opinion no one should use them in 2019. java.time, the modern Java date and time API, is so much nicer to work with.
Use the following function:
fun counterTime(eventtime: String): String {
var day = 0
var hh = 0
var mm = 0
try {
val dateFormat = SimpleDateFormat("yyyy-MM-dd HH:mm:ss")
val eventDate = dateFormat.parse(eventtime)
val cDate = Date()
val timeDiff = eventDate.time - cDate.time
day = TimeUnit.MILLISECONDS.toDays(timeDiff).toInt()
hh = (TimeUnit.MILLISECONDS.toHours(timeDiff) - TimeUnit.DAYS.toHours(day.toLong())).toInt()
mm =
(TimeUnit.MILLISECONDS.toMinutes(timeDiff) - TimeUnit.HOURS.toMinutes(TimeUnit.MILLISECONDS.toHours(timeDiff))).toInt()
} catch (e: ParseException) {
e.printStackTrace()
}
return if (day == 0) {
"$hh hour $mm min"
} else if (hh == 0) {
"$mm min"
} else {
"$day days $hh hour $mm min"
}
}
counterTime(2019-08-27 20:00:00)
This returns 24 days 6 hour 57 min
Note: The event date should always be a future date to the current date.
in flutter we can get current month using this
var now = new DateTime.now();
var formatter = new DateFormat('MM');
String month = formatter.format(now);
But how to get the last month date? Especially if current date is January (01). we can't get the right month when we use operand minus (-) , like month - 1.
You can just use
var prevMonth = new DateTime(date.year, date.month - 1, date.day);
with
var date = new DateTime(2018, 1, 13);
you get
2017-12-13
It's usually a good idea to convert to UTC and then back to local date/time before doing date calculations to avoid issues with daylight saving and time zones.
We can calculate both first day of the month and the last day of the month:
DateTime firstDayCurrentMonth = DateTime.utc(DateTime.now().year, DateTime.now().month, 1);
DateTime lastDayCurrentMonth = DateTime.utc(DateTime.now().year, DateTime.now().month + 1).subtract(Duration(days: 1));
DateTime.utc takes in integer values as parameters: int year, int month, int day and so on.
Try this package, Jiffy, it used momentjs syntax. See below
Jiffy().subtract(months: 1);
Where Jiffy() returns date now. You can also do the following, the same result
var now = DateTime.now();
Jiffy(now).subtract(months: 1);
We can use the subtract method to get past month date.
DateTime pastMonth = DateTime.now().subtract(Duration(days: 30));
Dates are pretty hard to calculate. There is an open proposal to add support for adding years and months here https://github.com/dart-lang/sdk/issues/27245.
There is a semantic problem with adding months and years in that "a
month" and "a year" isn't a specific amount of time. Years vary by one
day, months by up to three days. Adding "one month" to the 30th of
January is ambiguous. We can do it, we just have to pick some
arbitrary day between the 27th of February and the 2nd of March.
That's why we haven't added month and year to Duration - they do not
describe durations.
You can use the below code to add months in a arbitrary fashion (I presume its not completely accurate. Taken from the issue)
const _daysInMonth = const [0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31];
bool isLeapYear(int value) =>
value % 400 == 0 || (value % 4 == 0 && value % 100 != 0);
int daysInMonth(int year, int month) {
var result = _daysInMonth[month];
if (month == 2 && isLeapYear(year)) result++;
return result;
}
DateTime addMonths(DateTime dt, int value) {
var r = value % 12;
var q = (value - r) ~/ 12;
var newYear = dt.year + q;
var newMonth = dt.month + r;
if (newMonth > 12) {
newYear++;
newMonth -= 12;
}
var newDay = min(dt.day, daysInMonth(newYear, newMonth));
if (dt.isUtc) {
return new DateTime.utc(
newYear,
newMonth,
newDay,
dt.hour,
dt.minute,
dt.second,
dt.millisecond,
dt.microsecond);
} else {
return new DateTime(
newYear,
newMonth,
newDay,
dt.hour,
dt.minute,
dt.second,
dt.millisecond,
dt.microsecond);
}
}
To get a set starting point at the start of a month, you can use DateTime along with the Jiffy package.
DateTime firstOfPreviousMonth
= DateTime.parse(
Jiffy().startOf(Units.MONTH)
.subtract(months: 1)
.format('yyyy-MM-dd'). //--> Jan 1 '2021-01-01 00:00:00.000'
);
var fifthOfMonth
= firstOfPreviousMonth.add(Duration(days: 4)); //--> Jan 5 '2021-01-05 00:00:00.000'
or
DateTime endOfPreviousMonth
= DateTime.parse(
Jiffy().endOf(Units.MONTH)
.subtract(months: 2)
.format('yyyy-MM-dd'). //--> Dec 30 '2020-12-31 00:00:00.000'
// endOf always goes to 30th
);
var previousMonth
= endOfPreviousMonth.add(Duration(days: 2)); //--> Jan 1 '2021-01-01 00:00:00.000'
DateFormat('MMMM yyyy')
.format(DateTime(DateTime.now().year, DateTime.now().month - 2)),
List<DateTime> newList = [];
DateFormat format = DateFormat("yyyy-MM-dd");
for (var i = 0; i < recents.length; i++) {
newList.add(format.parse(recents[i]['date'].toString()));
}
newList.sort(((a, b) => a.compareTo(b)));
var total = 0;
for (var i = 0; i < newList.length; i++) {
if (DateTime.now().difference(newList[i]).inDays < 30) {
print(newList[i]);
total++;
}
}
print(total);
You can use this to fetch the last 30 days.
In addition to Günter Zöchbauer Answer
var now = new DateTime.now();
String g = ('${now.year}/ ${now.month}/ ${now.day}');
print(g);
I am using Asp:calendar. I need to find the day of week of the date selected.
For example for the month of February,2014 if 27th is selected it should give value as 4th Thursday. Please help in this
You can get the Day Of Week through DateTime.DayOfWeek property. like:
DayOfWeek daOfWeek = youCalendar.SelectedDate.DayOfWeek;
To calculate the occurrence of the day in that particular month, Create a new DateTime starting from 1st of the month, Loop through to SelectedDate check for DayOfWeek equals to SelectedDate.DayOfWeek and increment a counter.
DateTime selecteDate = yourCalendar.SelectedDate;
DateTime startDate = new DateTime(selecteDate.Year, selecteDate.Month, 1);
int counter = 0;
while (startDate <= selecteDate)
{
if (startDate.DayOfWeek == selecteDate.DayOfWeek)
counter++;
startDate = startDate.AddDays(1);
}
I want to populate the weeks in a dropdown list when selecting month like
when I select
January
Then it will show only the weeks which starts from monday like
1st week:
Monday(02/01/2012)
2nd week:
Monday(09/01/2012)
3rd week:
Monday(16/01/2012)
4th week:
Monday(23/01/2012)
5th week:
Monday(30/01/2012)
So it sounds like you need to find the first Monday in the week, then just keep adding one week until you're not in the same month any more:
using System;
using System.Collections.Generic;
class Test
{
static void Main(string[] args)
{
foreach (DateTime date in GetMondays(2012, 1))
{
Console.WriteLine(date);
}
}
static IEnumerable<DateTime> GetMondays(int year, int month)
{
DateTime startOfMonth = new DateTime(year, month, 1);
// Get to the first Monday
int daysToMonday = DayOfWeek.Monday - startOfMonth.DayOfWeek;
// Now make sure it's non-negative...
int daysToNextMonday = (daysToMonday + 7) % 7;
// Add it to the start of the month to get to the first Monday
DateTime firstMonday = startOfMonth.AddDays(daysToNextMonday);
// Now yield and iterate until we're done
for (DateTime date = firstMonday;
date.Month == month;
date = date.AddDays(7))
{
yield return date;
}
}
}
(You could add the dates to a list and return that instead if you wanted... it doesn't make much difference really.)
simply parse everything from the starting date of the month to the ending date of the month.
checking DayOfWeek for every day and print out the results