I want to display 3 different rollover image on mouse hover over of 3 different<a> element. For this i have use following mechanism but this doesn't solve any purpose. this is as follows:-
#item1 a {
position: absolute;
background-image:url("../images/step1_without_rollover.gif");
}
#item1 a:hover
{
position: absolute;
background-image:url("images/step1_rollover.gif");
}
#item2 a{
position: absolute;
background-image:url("../images/step2_without_rollover.gif");
}
#item2 a:hover {
position: absolute;
background-image:url("../images/step2_rollover.gif");
}
#item3 a{
position: absolute;
background-image:url("../images/step3_without_rollover.gif");
}
#item a:hover {
position: absolute;
background-image:url("../images/step3_rollover.gif");
}
NOTE: i have only begining knowledge of CSS. it is registration process classified into 3 steps.
Thanks !!
you have some unnecessary css codes there. See the code below. It hopefully does what you want. Try cleaning up your css codes a little before you post. that being said, I still dont understand why you need 3 image rollovers though..hope this helps
#item1
{
position: absolute;
top: 492px;left :190px;width:400px; height:140px;
}
#item1 a {
background-image:url("images/image1.gif");
}
#item1 a:hover
{
background-image:url("images/image2.gif");
}
I'm not sure what are you asking in the question, anyway remember that you cannot have more than one ID in the same HTML element, or the same ID in more than a HTML element. IDs must be unique.
EDIT
As much as I know, achieving 3 different background-image changes to the same element using only a :hover state is not possible using only CSS. You need JavaScript to give the element or its parents different classes when you want the image to change.
html
<div id="items">
Item 1
Item 2
Item 3
</div>
css
#items
{
position:absolute;
top:490px;
left:190px;
width:400px;
height:50px;
}
#items a.item1
{
position:absolute;
display:block;
height:50px;
width: 400px;
top: 490px;
left:242px;
background:url("../images/step1_without_rollover.gif");
}
#items a.item1:hover
{
background:url("../images/step1_rollover.gif");
}
#items a.item2
{
position:absolute;
display:block;
height:50px;
width: 400px;
top: 490px;
left:242px; /* don't forget to change your left value */
background:url("../images/step2_without_rollover.gif");
}
#items a.item2:hover
{
background:url("../images/step2_rollover.gif");
}
#items a.item3
{
position:absolute;
display:block;
height:50px;
width: 400px;
top: 490px;
left:242px; /* don't forget to change your left value */
background:url("../images/step3_without_rollover.gif");
}
#items a.item3:hover
{
background:url("../images/step3_rollover.gif");
}
Ok. I think I understand your point better now. So you have all the 3 steps on the same page. This means that you cannot have the same id 3 times on the page. You can do something like this though:
Edit
So you have three different pages. This means that you can use item1 id on all the different pages. But your stylesheet will still need to understand which page it is. You could wrap the item1 div around another div that has a different classname and then style it accordingly. If you go this way then this is what you will need to do:
HTML for Page 1:
<form class="page1" ...>
<div id="item1">
Step 1
.....
</div>
</form>
HTML for Page 2:
<form class="page2" ...>
<div id="item1">
Step 2
.....
</div>
</form>
HTML for Page 3:
<form class="page3" ...>
<div id="item1">
Step 3
.....
</div>
</form>
And your stylesheet will look as follows:
#item1
{
position: absolute;
top: 492px;left :190px;width:400px; height:140px;
}
.page1 #item1 a {
background-image: url("images/image1.gif");
}
.page1 #item1 a:hover
{
background-image:url("images/image1_hover.gif");
}
.page2 #item1 a {
background-image:url("images/image2.gif");
}
.page2 #item1 a:hover
{
background-image:url("images/image2_hover.gif");
}
.page3 #item1 a {
background-image:url("images/image3.gif");
}
.page3 #item1 a:hover
{
background-image:url("images/image3_hover.gif");
}
Or there is another way where you can use JavaScript to analyse the page and then change the background image based on that.
Related
I m having problem with css of a tooltip. Tooltip belongs to an input field and if an other checkbox is checked, this tooltip needs to be placed correctly on the input field. so the check box is :
<input type="checkbox" id="telefonBox" />
and the input field which tooltip needs to be placed :
<input type="text" class="form-control tooltip-berater" id="agentName"/>
What i tried is
input[id=telefonBox]:checked + .tooltip-berater + .tooltip > .tooltip-inner {top: 875px !important; left: 30px; max-width:300px;}
(Basically i m trying to write: if a checkbox with this id checked, then do some stuff in this css classes)
But doesnt function at all. What am i missing?
If both inputs are children of the same div, but not directly next to each other (in the HTML markup) then you need to use ~ operator instead of +.
+ works like:
<div class="parent">
<div class="first"></div>
<div class="second></div>
</div
.first + .second {
// do stuff with second
}
~ works like:
<div class="parent">
<div class="first"></div>
<div class="inbetween"></div>
<div class="second"></div>
</div
.first ~ .second {
// you can still do stuff with second
}
There is no selector which would help you in other cases possible in your HTML markup, especially:
When .second div is placed earlier than .first
When .second div has different parent from .first
In those cases you will need to use JavaScript to select and change your element's CSS.
Heres a fiddle i made that changes colour of input box: https://jsfiddle.net/8we5u1vs/
Is that the kind of thing you want? Obviously its much simpler than what you're talking about. You havnt added much code so hard to tell, could you show code or fiddle for an example of the tooltip?
input[id=telefonBox]:checked + .tooltip-berater {
background-color:red;
}
You can try this way, but text input is still available via tab key.
div {
display: inline-block;
position: relative;
line-height: 1.25em;
border: 1px solid;
background: white;
}
input[type=text] {
border: 1px solid white;
line-height: inherit;
}
span {
position: absolute;
left: 0;
top: 0;
right: 0;
bottom: 0;
text-align: center;
display: none;
border: 1px solid white;
background: white;
}
input[type=checkbox]:checked + div span {
display: block;
}
<input type=checkbox>
<div>
<input type=text>
<span>N/A</span>
</div>
I have some pseudo code like this:
<div class="container">
<div class="hiddenatfirst">
<img>
<img>
<img>
</div>
</div>
and css like so:
.hiddenatfirst{
display:none;
}
.container:hover .hiddenatfirst{
display:block;
}
.hiddenatfirst:hover{
display:block;
}
The problem is - I have a design website and a lot of visitors have the pinterst extension installed. When someone hovers over the pin-it button that gets added to the images inside the .hiddenatfirst div the div gets hidden again.
I don't want to remove the pin-it buttons from the images but I don't want them to get in the way of the :hover events.
Any ideas?
Apologies for the pseudo-code, the real code is pretty messy and in staging! Hopefully this explains what I need.
Thanks
PS - if you look at the .third-level-menu in the navigation here you'll see it in action (note you'll need the pinterest chrome extension installed)
http://smith-hoyt.myshopify.com/?preview_theme_id=12397927
PPS - this is a crappy GIF but I think shows what's happening too:
http://recordit.co/anNtu8W1Vo
PPPS - you can see the pin-it button that pinterest adds to each image in this image: https://twitter.com/tomcritchlow/status/573920066124836864/photo/1
Most probably the problem is that 'Pin it' button is absolutely positioned on top of the image, but it's not the container's child, so hover on it hides the image like on the following sample:
.container {
display: block;
width: 500px;
height: 315px;
background-color: gray;
}
.hiddenatfirst {
display: none;
}
#pinit {
position: absolute;
top: 32px;
left: 32px;
}
.container:hover .hiddenatfirst {
display: block;
}
.hiddenatfirst:hover {
display: block;
}
<div class="container">
<div class="hiddenatfirst">
<img src='https://dq1eylutsoz4u.cloudfront.net/2014/10/sf-cat.jpg' />
</div>
</div>
<img id='pinit' src='http://www.brandaiddesignco.com/insights/PinIt.png' />
What you can do is using JavaScript or jQuery find all the 'Pin it' buttons and move them to the appropriate containers with the positions recalculation, so the result HTML will be like the following:
.container {
display: block;
width: 500px;
height: 315px;
background-color: gray;
}
.hiddenatfirst {
display: none;
}
#pinit {
position: absolute;
top: 32px;
left: 32px;
}
.container:hover .hiddenatfirst {
display: block;
}
.hiddenatfirst:hover {
display: block;
}
<div class="container">
<div class="hiddenatfirst">
<img src='https://dq1eylutsoz4u.cloudfront.net/2014/10/sf-cat.jpg' />
<img id='pinit' src='http://www.brandaiddesignco.com/insights/PinIt.png' />
</div>
</div>
Rather than use the javascript solution above, since these images are small and in the navigation I found a way to remove the pin-it button, simply add to each image:
nopin="nopin"
As per the documentation here:
https://developers.pinterest.com/on_hover_pin_it_buttons/
I have this html code and style "this is just an example":
<div id="mn" style="margin-top:200px;">
<div class="first">1</div>
<div class="second">2</div>
<div class="third">3</div>
<div class="fourth">4</div>
</div>
<style type="text/css">
#mn, #mn div { display:inline-block; vertical-align:middle; }
#mn div { width:350px; margin:5px; /* float:left Comment */ }
div.first { height:5px; background-color:Red; }
div.second { height:120px; background-color:#999 }
div.third { height:50px; background-color:Yellow }
div.fourth { height:180px; background-color:#ccc }
</style>
The problem is, the element on left "the yellow and red ones" have a big space or bottom margin between these.
I need delete this big margin or spacing and use just 5px in all element.
I created a script with jquery that take the List and move them to a divs, something like that:
<div id="mn_left"></div>
<div id="mn_right"></div>
<div id="mn" style="margin-top:200px;">
<div class="first">1</div>
<div class="second">2</div>
<div class="third">3</div>
<div class="fourth">4</div>
</div>
$(document).ready(function () {
$("div", "#mn").each(function (e, value) {
if ($("#mn_left").height() <= $("#mn_right").height()) {
$("#mn_left").append(value.outerHTML);
}
else {
$("#mn_right").append(value.outerHTML);
}
});
});
The script works fine, but I want to do it without scripts.
Edit...
I mistook, I changed the li by divs... But it's exactly the same. The Html Looks Like that:
http://postimg.org/image/dh6dwdjc1/
What I really want is this
http://postimg.org/image/otnkrwhep/
First off, here is your code properly set up using list markup, since you said it's a list:
HTML:
<ul id="mn">
<li class="first">1</li>
<li class="second">2</li>
<li class="third">3</li>
<li class="fourth">4</li>
</ul>
CSS:
#mn {padding:0; margin:0;}
#mn, #mn li { display:inline-block; vertical-align:middle; }
#mn li { width:350px; margin:5px; }
li.first { height:5px; background-color:Red; }
li.second { height:120px; background-color:#999 }
li.third { height:50px; background-color:Yellow }
li.fourth { height:180px; background-color:#ccc }
(JSFiddle Link 1)
Then, remove the margin from #mn li:
#mn li { width:350px; /* margin:5px; */ }
(JSFiddle Link2 )
You'll see the list items are flush now, except the first item, where the line height is taller than the item height. To fix that first one, give the list items an overflow:hidden; and change the display from inline-block to just block.
#mn, #mn li { display:block; vertical-align:middle; }
#mn li { width:350px; overflow: hidden;}
(JSFiddle Link 3)
That should be it for you, unless I've misunderstood.
Now that I understand what you're trying to do...
One way to do that is to create a class for the items that will be in the second colum:
#mn .col2 { position: absolute; left: 355px; top:0; margin-top: 0;}
JSFiddle Example. (PS, You need #mn{position:relative;} for the above to work.)
The problem with this is that if you have more than one item in the second column, you'll have to give the second (and third, fourth, etc) items a custom top position so that they line up properly.
This seems like a perfect place to use Javascript instead of CSS. And that's coming from a proponent of "always use CSS whenever you can!"
How about this? Using floats instead of absolute positioning.
#mn {width: 720px;}
#mn div { width:350px; float:left; margin:5px; }
#mn div.second {float:right;}
div.first { height:5px; background-color:Red; }
div.second { height:120px; background-color:#999; }
div.third { height:50px; background-color:Yellow }
div.fourth { height:180px; background-color:#ccc }
Floated all to left.
Added a new CSS rule for the containing div of
#mn. The width is equal to the width of each child div plus it's
margins, so ( 5px + 350px + 5px ) = ( 360px x 2 ) = 720px.
Added new CSS declaration for the second div.
I'm trying to make a checkerboard pattern using nth-child, but it isn't working the way I expected it to.
In the example below, I want to set every other p at opposite sides of the div to create a checkerboard pattern. The p are set to width:50%;, and the div is set at width:100%.
I've set up a jsfiddle to demonstrate:
HTML
<div id='check'>
<p>Odd</p>
</div>
<div id='check'>
<p>Even</p>
</div>
CSS
#check {
float:left;
width: 100%;
}
#check p {
width: 50%;
background: #DDD;
}
#check p:nth-child(odd) {
float:right;
}
Can someone make me see how to make this work?
You need to keep all the p elements together in a single div, as the nth-child is based off the parent container. Here is a modified fiddle.. It uses this code:
HTML
<div id ='check'>
<p>Odd</p>
<p>Even</p>
<p>Odd</p>
<p>Even</p>
</div>
CSS
#check {
float:left;
width: 100%;
}
#check p {
width: 50%;
background: #DDD;
clear:both;
}
#check p:nth-child(odd) {
float:right;
}
#check p:nth-child(even) {
float:left
}
Can't have 2 elements using the same id. I believe you want to switch to using classes.
Created a fiddle to demonstrate http://jsfiddle.net/wE6e4/
#checkerboard {
width: 500px;
}
.check {
float:left;
width: 100px;
height: 100px;
}
.check:nth-child(odd) {
background: #DDD;
}
.check:nth-child(even) {
background: #fff;
}
First, you're using an ID multiple times - ID's should be unique. Besides that, the line
#check p:nth-child(odd) means that you want to set the given rules for every odd p child of #check, which is not what you want. You want to make every odd .check (I took the liberty to change the ID's to a class). So you should put them in a container and say:
#cont .check:nth-child(odd) {
float:right;
}
Here's the fiddle:
http://jsfiddle.net/Wbnks/
If you're trying to minimize your CSS, you can try something like this:
HTML:
<div class="checkerboard">
<p>1</p>
<p>2</p>
<p>3</p>
<p>4</p>
<p>5</p>
<p>6</p>
<p>7</p>
<p>8</p>
<p>9</p>
<p>10</p>
</div>
CSS:
.checkerboard p {
float: left;
width: 50%;
}
.checkerboard p:nth-child(4n-2), .checkerboard p:nth-child(4n-1) {
background-color: #999;
}
http://jsfiddle.net/L9ng7/5/
I have a vertically displayed navigation menu. I would like a bullet point to appear to the left of the page currently being viewed. I've read a little bit about using background changes applied to li to indicate page, but I don't know how to apply that to using bullets.. Any ideas?
<nav>
<ul>
<li>home</li>
<li>about</li>
<li>lookbook</li>
<li>services</li>
<li>contact</li>
<li>blog</li>
</ul>
</nav>
nav {
position: fixed;
right: 13%;
top: 65%;
}
nav ul li {
text-align: right;
}
http://jsfiddle.net/jtRws/
Update
Live examples of all proposed solutions
Working with AMC it was determined that a JavaScript solution would work better given the requirements. All content would appear on one page so the CSS solutions would not work based on my findings. I proposed the simple jQuery code to show a bullet when the link was clicked.
jQuery
$(window).load(function(event) {
$('a').click(function() {
$('#Nav li').removeClass();
$(this).parent().addClass("current");
});
});
CSS
#navcontainer3 ul {
width: 200px;
list-style-type:disc;
}
#navcontainer3 ul li {
color: #ccc;
float:right;
clear:right;
}
#navcontainer3 ul li.current {
color: #000;
}
This page contains examples of all the solutions but you'll find the jQuery solution alone at this link: http://jsfiddle.net/jtRws/10/.
Interesting problem. Obviously, there are JavaScript solutions, but it looks like you want a pure CSS solution.
Solution 0
Hide the other list item bullets by setting the list style color to the background color.
All pages will have the same navigation HTML but each page's <body> will have an id unique for that page. For example: <body id="home">, <body id="products">, etc. Then, using some clever CSS, the current page will obtain the specific styling definition (last def below).
#navcontainer0 ul {
width: 200px;
list-style-type:disc;
}
#navcontainer0 ul li {
color: #fff;
float:right;
clear:right;
}
body#home #homenav0,
body#products #prodnav0 {
color: #000;
}
Solution 1
Use background to show and hide the bullet image. Based on this article I used the following code. The article explains the technique in greater detail. Below you'll find the same code as the live example.
CSS
#navcontainer ul {
width: 200px;
padding:0;
margin:0;
text-align:right;
}
#navcontainer ul li a:hover {
color: #930;
background: #f5d7b4;
}
body#home a#homenav,
body#products a#prodnav,
body#faq a#faqnav,
body#contact a#connav {
background:url(bullet.gif) 0 50% no-repeat no-repeat;
padding-left:15px;
}
Products Page
<body id="products">
<div id="navcontainer">
<ul id="navlist">
<li><a id="homenav" href="index.html">Home</a></li>
<li><a id="prodnav" href="products.html" >Products</a></li>
</ul>
</div>
</body>
I assume you're using anchors to navigate through page sections, so the only way I can think of right now is using javascript(jQuery).
I've updated your code example: http://tinyurl.com/a6ypyuz
In addition to #earthdesigner answer, if you don't want to add jquery then use this javascript instead:
http://jsfiddle.net/7uxcg/31/
window.onload = function() {
// var nav = document.getElementById('nav');
var nav = document.getElementsByTagName('NAV')[0].children[0];
for(c in nav.children) {
var li = nav.children[c];
if(li.nodeName == 'LI') {
li.onclick = function() {
changeClass(this.children[0].hash);
}
}
}
function changeClass(cur) {
var nav = document.getElementsByTagName('NAV')[0].children[0];
for(c in nav.children) {
var li = nav.children[c];
if(li.nodeName == 'LI' && li.children[0].hash == cur)
li.className = 'active';
else
li.className = ''
}
}
};
I understand that you want bullets only to current page. So first of all we're goind to eliminate normal bullets.
ul {list-style-type:none;}
Than i saw that you use id's for content divs on every page. Combining that with atribute selector here's an example of what you could do:
#home li a[href='#home']:before, #about li a[href='#about']:before {
content:"•";pointer-events:none; text-decoration:none;
}