Reflection? How do I do it? - math

This is over my head, can someone explain it to me better? http://mathworld.wolfram.com/Reflection.html
I'm making a 2d breakout fighting game, so I need the ball to be able to reflect when it hits a wall, paddle, or enemy (or a enemy hits it).
all their formula's are like: x_1^'-x_0=v-2(v·n^^)n^^.
And I can't fallow that. (What does ' mean or x_0? or ^^?)

The formula for reflection is easier to understand if you think to the geometric meaning of the operation of "dot product".
The dot product between two 3d vectors is mathematically defined as
<a, b> = ax*bx + ay*by + az*bz
but it has a nice geometric interpretation
The dot product between a and b is the length
of the projection of a over b taken with
a negative sign if the two vectors are pointing in
opposite directions, multiplied by the length of b.
Something that is immediately obvious using this definition and that it's not evident if you only look at the formula is for example that the dot product of two vectors doesn't change if the coordinate system is rotated, that the dot product of two perpendicular vectors is 0 (the length of the projection is clearly zero in this case) or that the dot product of a vector by itself is the square of its length.
Something that is instead less obvious using the geometric interpretation is that the dot product is commutative, i.e. that <a, b> = <b, a> (fact that is clear considering the formula).
An important point to consider is also that if the length of b is 1 then the dot product <a, b> is simply the length of the projection of a over b (taken with the proper sign).
Given this interpretation the formula for computing the reflection over a plane is quite easy to understand:
To compute the reflected vector r, given a vector a and a plane with normal n you just need to use the formula:
r = a - 2<a, n> n
the height h in the figure is in this case just <a, n> (note that n is assumed to be of unit length) and so it should be clear that you need to move twice that height in the direction of the normal.
If you consider the proper dot product signs you should see that the formula applies also when the incident vector a and the plane normal n are facing in the same direction.

The prime (') indicates the second form of a number/point/structure. In this case, x₁' refers to the reflected form of x₁.
The subscript (0) shows various states of the same. In this case, x₀ is the point of reflection.
The caret notation (^) shows that something is a vector. In this case, n̂ is the normal vector.

Is this just about the equation formatting? Because I see nicely formatted equations, not the LaTeX-style markup appearing in your question. So step 1: try viewing the page in a different web browser and see if it looks clearer.
More substantively, I'd recommend a different kind of resource. Fundamentally, you're looking at collisions, which are normally better treated in a physics text than a math text. Any introductory physics textbook will have a chapter on collisions, which should be directly applicable to your game.

Related

Why do we need to have absolute values of V(number of Vertices) and E(Number of Edges) in upper bound of various Graph algorithms

I have been reading through the Graph Algorithms recently and saw the notation for various upper bounds of graph algorithms is of the form O(|V| + |E|). especially in DFS/BFS search algorithms where linear time is achieved with above upper bound.
I have seen both the notations interchangeably used, i.e. O(V+E) as well. as far as I understand "|" bar notation is used for absolute values in math world. if V = # of vertices and E = # of Edges, how can they be negative numbers, such that we have need to get the absolute values before computing the linear function. Please help.
|X| refers to the cardinality (size) of X when X is a set.
O(V+E) is technically incorrect, assuming that V and E refer to sets of vertices and edges. This is because the value inside O( ) should be quantitative, rather than abstract sets of objects that have an ambiguous operator applied to them. |V| + |E| is well-defined to be one number plus another, whereas V + E could mean a lot of things.
However, in informal scenarios (e.g. conversing over the internet and in person), many people (including me) still say O(V+E), because the cardinality of the sets is implied. I like to type fast and adding in 4 pipe characters just to be technically correct is unnecessary.
But if you need to be technically correct, i.e. you're in a formal environment, or e.g. you're writing your computer science dissertation, it's best to go with O(|V|+|E|).
In this case, the vertical bars || denote the cardinality or number of elements of a set (i.e. |E| represents the count of elements in the set E).
http://en.wikipedia.org/wiki/Cardinality

Support Vector Machine Geometrical Intuition

Hi,
I have a big difficult trying to understand why in the equation of the hyperplane of support vector machine there is a 1 after >=?? w.x + b >= 1 <==(why this 1??) I know that could be something about the intersection point on y axes but I cannot relate that to the support vector and to its meaning of classification.
Can anyone please explain me why the equation has that 1(-1) ?
Thank you.
The 1 is just an algebraic simplification, which comes in handy in the later optimization.
First, notice, that all three hyperplanes can be denotes as
w'x+b= 0
w'x+b=+A
w'x+b=-A
If we would fix the norm of the normal w, ||w||=1, then the above would have one solution with some arbitrary A depending on the data, lets call our solution v and c (values of optimal w and b respectively). But if we let w to have any norm, then we can easily see, that if we put
w'x+b= 0
w'x+b=+1
w'x+b=-1
then there is one unique w which satisfies these equations, and it is given by w=v/A, b=c/A, because
(v/A)'x+(b/A)= 0 (when v'x+b=0) // for the middle hyperplane
(v/A)'x+(b/A)=+1 (when v'x+b=+A) // for the positive hyperplane
(v/A)'x+(b/A)=-1 (when v'x+b=-A) // for the negative hyperplane
In other words - we assume that these "supporting vectors" satisfy w'x+b=+/-1 equation for future simplification, and we can do it, because for any solution satisfing v'x+c=+/-A there is a solution for our equation (with different norm of w)
So once we have these simplifications our optimization problem simplifies to the minimization of the norm of ||w|| (maximization of the size of the margin, which now can be expressed as `2/||w||). If we would stay with the "normal" equation with (not fixed!) A value, then the maximization of the margin would be in one more "dimension" - we would have to look through w,b,A to find the triple which maximizes it (as the "restrictions" would be in the form of y(w'x+b)>A). Now, we just search through w and b (and in the dual formulation - just through alpha but this is the whole new story).
This step is not required. You can build SVM without it, but this makes thing simplier - the Ockham's razor rule.
This boundary is called "margin" and must be maximized then you have to minimize ||w||.
The aim of SVM is to find a hyperplane able to maximize the distances between the two groups.
However there are infinite solutions ( see figure: move the optimal hyperplane along the perpendicualr vector) and we need to fix at least the boundaries: the +1 or -1 is a common convention to avoid these infinite solutions.
Formally you have to optimize r ||w|| and we set a bounadry condition r ||w|| = 1.

Difference between a vector in maths and programming

Maybe this question is better suited in the math section of the site but I guess stackoverflow is suited too. In mathematics, a vector has a position and a direction, but in programming, a vector is usually defined as:
Vector v (3, 1, 5);
Where is the direction and magnitude? For me, this is a point, not a vector... So what gives? Probably I am not getting something so if anybody can explain this to me it would be very appreciated.
If we are working in cartesian coordinates, and assume (0,0,0) to be the origin, then a point p=(3,1,5) can be written as
where i, j and k are the unit vectors in the x, y and z directions. For convenience sake, the unit vectors are dropped from programming constructs.
The magnitude of the vector is
and its direction cosines are
respectively, both of which can be done programmatically. You can also take dot products and cross-products, which I'm sure you know about. So the usage is consistent between programming and mathematics. The difference in notations is mostly because of convenience.
However as Tomas pointed out, in programming, it is also common to define a vector of strings or objects, which really have no mathematical meaning. You can consider such vectors to be a one dimensional array or a list of items that can be accessed or manipulated easily by indexing.
In mathematics, it is easy to represent a vector by a point - just say that the "base" of the vector is implied to be the origin. Thus, a mathematical point for all practical purposes is also a representation of a mathematical vector, and the vector in your example has the magnitude sqrt(3^2 + 1^2 + 5^2) = 6 and the direction (1/2, 1/6, 5/6) (a normalized vector from the origin).
However, a vector in programming usually has no geometrical use, which means you really aren't interested in things like magnitude or direction. A vector in programming is rather just an ordered list of items. Important here is that the items need not be numbers - it can be anything handled by the language in question! Thus, ("Hello", "little", "world") is also a vector in programming, although it (obviously) has no vector interpretation in the mathematical sense.
Practically speaking (!):
A vector in mathematics is only a direction without a position (actually something more general, but to stay in your terminology). In programming you often use vectors for points. You can think of your vector as the vector pointing from the origin (0,0,0) to the point (3,1,5), called the location vector of the point. Consult texts on analytical and affine geometry for more insight.
A Vector in computer science is an "one dimensional" data structure (array) (can be thought as direction) with an usually dynamic size (length/magnitude). For that reason it is called as vector. But it's an array at least.
A vector also means a set of coordinates. This is how it is used in programming. Just as a set of numbers. You might want to represent position vectors, velocity vectors, momentum vectors, force vectors with a vector object, or you may wish to represent it any way that suits you.
Many times vector quantities may be represented by 4 coordinates instead of 3 (see homogeneous coordinates in computer graphics) so a physical vector is represented by a computer vector with 4 elements. Alternatively you can store direction and magnitude separately, or encode them with 3, 4 or more coordinates.
I guess what I am getting to, is that computer languages are designed to represent physical models, but abstract data containers that the programmer use as tools for his/hers modeling.
Vector in math is an element of n-dimensional space over some field(e.g. real/complex number, functions, string). It may have infinite dimension, e.g. functional space L^2. I don't remember infite-dimensional vectors were used in programming (infinite vectors are not vectors with non-limited length, but vector with infite number of elements)
The most rigorous statement is that a mathematical vector is a first-order tensor that transforms from one coordinate system to another according to tensor transformation rules. The physical idea to keep in mind is that vectors have both magnitude and direction.
Programming vectors are data structures that need not transform according to any rules and may or may not have a notion of a coordinate system as reference. If you happen to use a vector data structure to hold numbers, they may conform to the mathematical definition. But if you have a vector of objects, it's unlikely that they have anything to do with coordinate transformations.

Function for returning a list of points on a Bezier curve at equal arclength

Someone somewhere has had to solve this problem. I can find many a great website explaining this problem and how to solve it. While I'm sure they are well written and make sense to math whizzes, that isn't me. And while I might understand in a vague sort of way, I do not understand how to turn that math into a function that I can use.
So I beg of you, if you have a function that can do this, in any language, (sure even fortran or heck 6502 assembler) - please help me out.
prefer an analytical to iterative solution
EDIT: Meant to specify that its a cubic bezier I'm trying to work with.
What you're asking for is the inverse of the arc length function. So, given a curve B, you want a function Linv(len) that returns a t between 0 and 1 such that the arc length of the curve between 0 and t is len.
If you had this function your problem is really easy to solve. Let B(0) be the first point. To find the next point, you'd simply compute B(Linv(w)) where w is the "equal arclength" that you refer to. To get the next point, just evaluate B(Linv(2*w)) and so on, until Linv(n*w) becomes greater than 1.
I've had to deal with this problem recently. I've come up with, or come across a few solutions, none of which are satisfactory to me (but maybe they will be for you).
Now, this is a bit complicated, so let me just give you the link to the source code first:
http://icedtea.classpath.org/~dlila/webrevs/perfWebrev/webrev/raw_files/new/src/share/classes/sun/java2d/pisces/Dasher.java. What you want is in the LengthIterator class. You shouldn't have to look at any other parts of the file. There are a bunch of methods that are defined in another file. To get to them just cut out everything from /raw_files/ to the end of the URL. This is how you use it. Initialize the object on a curve. Then to get the parameter of a point with arc length L from the beginning of the curve just call next(L) (to get the actual point just evaluate your curve at this parameter, using deCasteljau's algorithm, or zneak's suggestion). Every subsequent call of next(x) moves you a distance of x along the curve compared to your last position. next returns a negative number when you run out of curve.
Explanation of code: so, I needed a t value such that B(0) to B(t) would have length LEN (where LEN is known). I simply flattened the curve. So, just subdivide the curve recursively until each curve is close enough to a line (you can test for this by comparing the length of the control polygon to the length of the line joining the end points). You can compute the length of this sub-curve as (controlPolyLength + endPointsSegmentLen)/2. Add all these lengths to an accumulator, and stop the recursion when the accumulator value is >= LEN. Now, call the last subcurve C and let [t0, t1] be its domain. You know that the t you want is t0 <= t < t1, and you know the length from B(0) to B(t0) - call this value L0t0. So, now you need to find a t such that C(0) to C(t) has length LEN-L0t0. This is exactly the problem we started with, but on a smaller scale. We could use recursion, but that would be horribly slow, so instead we just use the fact that C is a very flat curve. We pretend C is a line, and compute the point at t using P=C(0)+((LEN-L0t0)/length(C))*(C(1)-C(0)). This point doesn't actually lie on the curve because it is on the line C(0)->C(1), but it's very close to the point we want. So, we just solve Bx(t)=Px and By(t)=Py. This is just finding cubic roots, which has a closed source solution, but I just used Newton's method. Now we have the t we want, and we can just compute C(t), which is the actual point.
I should mention that a few months ago I skimmed through a paper that had another solution to this that found an approximation to the natural parameterization of the curve. The author has posted a link to it here: Equidistant points across Bezier curves

As a programmer how would you explain imaginary numbers?

As a programmer I think it is my job to be good at math but I am having trouble getting my head round imaginary numbers. I have tried google and wikipedia with no luck so I am hoping a programmer can explain in to me, give me an example of a number squared that is <= 0, some example usage etc...
I guess this blog entry is one good explanation:
The key word is rotation (as opposed to direction for negative numbers, which are as stranger as imaginary number when you think of them: less than nothing ?)
Like negative numbers modeling flipping, imaginary numbers can model anything that rotates between two dimensions “X” and “Y”. Or anything with a cyclic, circular relationship
Problem: not only am I a programmer, I am a mathematician.
Solution: plow ahead anyway.
There's nothing really magical to complex numbers. The idea behind their inception is that there's something wrong with real numbers. If you've got an equation x^2 + 4, this is never zero, whereas x^2 - 2 is zero twice. So mathematicians got really angry and wanted there to always be zeroes with polynomials of degree at least one (wanted an "algebraically closed" field), and created some arbitrary number j such that j = sqrt(-1). All the rules sort of fall into place from there (though they are more accurately reorganized differently-- specifically, you formally can't actually say "hey this number is the square root of negative one"). If there's that number j, you can get multiples of j. And you can add real numbers to j, so then you've got complex numbers. The operations with complex numbers are similar to operations with binomials (deliberately so).
The real problem with complexes isn't in all this, but in the fact that you can't define a system whereby you can get the ordinary rules for less-than and greater-than. So really, you get to where you don't define it at all. It doesn't make sense in a two-dimensional space. So in all honesty, I can't actually answer "give me an exaple of a number squared that is <= 0", though "j" makes sense if you treat its square as a real number instead of a complex number.
As for uses, well, I personally used them most when working with fractals. The idea behind the mandelbrot fractal is that it's a way of graphing z = z^2 + c and its divergence along the real-imaginary axes.
You might also ask why do negative numbers exist? They exist because you want to represent solutions to certain equations like: x + 5 = 0. The same thing applies for imaginary numbers, you want to compactly represent solutions to equations of the form: x^2 + 1 = 0.
Here's one way I've seen them being used in practice. In EE you are often dealing with functions that are sine waves, or that can be decomposed into sine waves. (See for example Fourier Series).
Therefore, you will often see solutions to equations of the form:
f(t) = A*cos(wt)
Furthermore, often you want to represent functions that are shifted by some phase from this function. A 90 degree phase shift will give you a sin function.
g(t) = B*sin(wt)
You can get any arbitrary phase shift by combining these two functions (called inphase and quadrature components).
h(t) = Acos(wt) + iB*sin(wt)
The key here is that in a linear system: if f(t) and g(t) solve an equation, h(t) will also solve the same equation. So, now we have a generic solution to the equation h(t).
The nice thing about h(t) is that it can be written compactly as
h(t) = Cexp(wt+theta)
Using the fact that exp(iw) = cos(w)+i*sin(w).
There is really nothing extraordinarily deep about any of this. It is merely exploiting a mathematical identity to compactly represent a common solution to a wide variety of equations.
Well, for the programmer:
class complex {
public:
double real;
double imaginary;
complex(double a_real) : real(a_real), imaginary(0.0) { }
complex(double a_real, double a_imaginary) : real(a_real), imaginary(a_imaginary) { }
complex operator+(const complex &other) {
return complex(
real + other.real,
imaginary + other.imaginary);
}
complex operator*(const complex &other) {
return complex(
real*other.real - imaginary*other.imaginary,
real*other.imaginary + imaginary*other.real);
}
bool operator==(const complex &other) {
return (real == other.real) && (imaginary == other.imaginary);
}
};
That's basically all there is. Complex numbers are just pairs of real numbers, for which special overloads of +, * and == get defined. And these operations really just get defined like this. Then it turns out that these pairs of numbers with these operations fit in nicely with the rest of mathematics, so they get a special name.
They are not so much numbers like in "counting", but more like in "can be manipulated with +, -, *, ... and don't cause problems when mixed with 'conventional' numbers". They are important because they fill the holes left by real numbers, like that there's no number that has a square of -1. Now you have complex(0, 1) * complex(0, 1) == -1.0 which is a helpful notation, since you don't have to treat negative numbers specially anymore in these cases. (And, as it turns out, basically all other special cases are not needed anymore, when you use complex numbers)
If the question is "Do imaginary numbers exist?" or "How do imaginary numbers exist?" then it is not a question for a programmer. It might not even be a question for a mathematician, but rather a metaphysician or philosopher of mathematics, although a mathematician may feel the need to justify their existence in the field. It's useful to begin with a discussion of how numbers exist at all (quite a few mathematicians who have approached this question are Platonists, fyi). Some insist that imaginary numbers (as the early Whitehead did) are a practical convenience. But then, if imaginary numbers are merely a practical convenience, what does that say about mathematics? You can't just explain away imaginary numbers as a mere practical tool or a pair of real numbers without having to account for both pairs and the general consequences of them being "practical". Others insist in the existence of imaginary numbers, arguing that their non-existence would undermine physical theories that make heavy use of them (QM is knee-deep in complex Hilbert spaces). The problem is beyond the scope of this website, I believe.
If your question is much more down to earth e.g. how does one express imaginary numbers in software, then the answer above (a pair of reals, along with defined operations of them) is it.
I don't want to turn this site into math overflow, but for those who are interested: Check out "An Imaginary Tale: The Story of sqrt(-1)" by Paul J. Nahin. It talks about all the history and various applications of imaginary numbers in a fun and exciting way. That book is what made me decide to pursue a degree in mathematics when I read it 7 years ago (and I was thinking art). Great read!!
The main point is that you add numbers which you define to be solutions to quadratic equations like x2= -1. Name one solution to that equation i, the computation rules for i then follow from that equation.
This is similar to defining negative numbers as the solution of equations like 2 + x = 1 when you only knew positive numbers, or fractions as solutions to equations like 2x = 1 when you only knew integers.
It might be easiest to stop trying to understand how a number can be a square root of a negative number, and just carry on with the assumption that it is.
So (using the i as the square root of -1):
(3+5i)*(2-i)
= (3+5i)*2 + (3+5i)*(-i)
= 6 + 10i -3i - 5i * i
= 6 + (10 -3)*i - 5 * (-1)
= 6 + 7i + 5
= 11 + 7i
works according to the standard rules of maths (remembering that i squared equals -1 on line four).
An imaginary number is a real number multiplied by the imaginary unit i. i is defined as:
i == sqrt(-1)
So:
i * i == -1
Using this definition you can obtain the square root of a negative number like this:
sqrt(-3)
== sqrt(3 * -1)
== sqrt(3 * i * i) // Replace '-1' with 'i squared'
== sqrt(3) * i // Square root of 'i squared' is 'i' so move it out of sqrt()
And your final answer is the real number sqrt(3) multiplied by the imaginary unit i.
A short answer: Real numbers are one-dimensional, imaginary numbers add a second dimension to the equation and some weird stuff happens if you multiply...
If you're interested in finding a simple application and if you're familiar with matrices,
it's sometimes useful to use complex numbers to transform a perfectly real matrice into a triangular one in the complex space, and it makes computation on it a bit easier.
The result is of course perfectly real.
Great answers so far (really like Devin's!)
One more point:
One of the first uses of complex numbers (although they were not called that way at the time) was as an intermediate step in solving equations of the 3rd degree.
link
Again, this is purely an instrument that is used to answer real problems with real numbers having physical meaning.
In electrical engineering, the impedance Z of an inductor is jwL, where w = 2*pi*f (frequency) and j (sqrt(-1))means it leads by 90 degrees, while for a capacitor Z = 1/jwc = -j/wc which is -90deg/wc so that it lags a simple resistor by 90 deg.

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