i have row style set to NODE in my view.
I need to access "title" field of every node and modify it's, say, color and print it.
Then I need to print content.
How do I loop through the nodes and access fields inside each node? I just do not know how to count total number of nodes, and how to access each field in the node.
Thanks!
Instead of trying to loop through the nodes, you are almost certainly better off switching to a Row style of Fields and using (or overriding) the the per field templates that views provides.
That said, if all you really need to do is color a field, you can do that in CSS with the existing classes that Views adds by default.
You can edit directly the node-NODETYPE.tpl.php, adding your html before and after the title.
Your javascript function can then check whether the node is being printed within the appropriate view or not.
Related
I have a view in Drupal 7 with results including a field of date and another with price, I need to sort the results by means of these two fields when I click on the appropriate link (not button or dropbox radio), but the trick is I need add the different sort filter into two separate blocks, because each block will have a different per user context.
Besides the filters should be links. Any idea how to work this?
You can have different displays for all order variations and then use appropriate one depending on parameter passed with link. Of course, you can't just use block view, but create your custom block which will embed correct view depending on that parameter.
Other way would be altering view query. In you module add hook function for altering view and inside you should detect your view, check for parameter and alter order value.
You can create two block displays for the same view, each of them sorting the results with a different criteria. Once both blocks are created, enable them in the same theme region and establish the URLs in which each module should be displayed. This configuration can be set using the block configuration form.
I am using views 3 and drupal 7. I have a view setup where it will return all related articles based on the keywords which works perfectly.
The problem is that I don't want the article that I'm on to show up in the results. Is there a way to hide specific nodes from displaying? For instance, lets say I have nodes: 43908 and 43909 that I don't want to show up in the view.
I've added a filter criteria (not contextual filter) to remove these nodes, but is it possible to combine node ID's into one filter? So if I wanted to show all but 43908 and 43909 how would I do that? I've tried to add them as 43908+43909 but that didn't seem to work.
You can use the regular expression option for the nid filter. So for the nid you mention you would do:
[^43908|^43909]
This filters out nodes with nid 43908 and 43909.
As for the scenario you describe, I think a better approach would be to add a separate field to your content type, e.g. field_in_progress, a tick box only visible when editing. Then you can add a filter on that field for the view.
This article may help. It involves excluding the current node from a list view.
I'm having some problems creating a view for a node within my website.
The content has a path of 'content/%' where % is the title of the node.
What I tried to do is to create a page view in the Views2 module, but to no avail.
When I attempt to preview with the name of one of my nodes, nothing appears, and when I visit the node live, it renders text to the screen without any formatting.
Here are some of the settings from my View...please let me know if I should provide any extra information!
Page Settings
Path: content/%
Arguments
Node:Title
Title: %1
Action to take if argument is not present: Provide default argument
Default argument type: Node ID from URL
Edit
I will describe the behavior I'm expecting to see...
I have a list of nodes in my website in a view....that shows up without any issue.
What I would like to do is click on the node and go to that node's page, which is basically an expanded view of a single item from my list.
I thought what I could do is clone my list view and then add an argument to trim the scope from a list to a single item, but this isn't working too well. What is the proper method for styling a single node?
Edit:
Based on your edit, you've already used Views to create a list of nodes, and now you want to be able to click on one and get to the node page.
If you just want the default node output, you shouldn't have to do anything else. Don't try to use a View to override default node rendering; Drupal will print it out by default.
If you want to theme your node uniquely (beyond what moving the fields around and changing display settings in the UI allows you to do), then you should look at custom template files and theming. Resource here: http://drupal.org/theme-guide
You can change the default node.tpl.php file if you want to change how all nodes are displayed, or you can copy that file and rename it to node-name_of_custom_type.tpl.php to uniquely theme a custom content type you've created, but I'd suggest reading up on the Drupal theme system before making those changes.
End of edit
When you want to assign a path to a Views Page display, you shouldn't model it after any existing paths (e.g. node paths, as you mention). It should be something unique to avoid path alias conflicts. So for example:
my-path/%
Now, if you're just looking to embed a view inside of your node (and you want to pass along the node id as the argument), you're half-way there. Your Arguments setting, based on your description, is correct. However, you don't need a page display.
Here are a couple of options:
Quick 'n' Dirty: Create a block display (which doesn't need a path) and stick the block in a region on the node page (I've used the content_bottom region) to "embed" it in your node
Powerful, Flexible: Use the views_embed_view function (api docs here) inside your node (the body or a CCK field, just make sure to use the "PHP filter" input format)
If you use views_embed_view, you have the flexibility of sticking your Views results wherever you like, and you don't even need to create a Views page or block display, because that function can just use the "Default" display.
Note: If you export your View and save the export code on a site like pastebin or drupalbin, folks here can import the View and see it directly to help answer your question in full detail.
Okay, got it. :)
Using Node: Title as an argument is pretty tricky: with the default settings, the argument must match the title exactly. So, if you wanted to match on "Test value", your path would need to look like content/Test%20value (note the caps).
This will get you the node you want. You said you have default argument set to Node ID from URL; that really doesn't apply for Node: Title arguments. What it does is attempt to find a numeric Node ID and use that as the argument, which will never validate on a Node: Title unless the node's title happens to match the node's ID.
If you just want to display all the nodes if there isn't a title argument present, select Display all values as the action to take if an argument is not present. If you want to display all nodes if the title argument is invalid (like a typo or something), make sure Display all values is set in the Validator field group for the action to take if the argument does not validate.
Because of the exact match restriction on node titles, it's generally not a good idea to use Node: Title as the argument. Instead, consider using "content/NID", where NID is the Node ID of the row's node, as the link in the original view Then, instead of the Node: Title argument in your view, use the Node: ID argument. This should make it less error-prone.
I'm using "Search" exposed filter in Views (DRupal):
It works great, however I would like to ignore a specific node, if it is possible, and always display it, regardless the filter options.
how can I do that ? Is possible to specify the Search filter for only a specific content type ?
thanks
Here's what to do:
Add a new display to your view that is an attachment view. In the attachment, override all of your other filters etc and set up the view so that it just loads the single node that you want. Attach this view to the top or bottom of your search view as required.
In your search view, add an argument of node id and hard code a default argument that is the id of the node you display in the attachment. Exclude this argument from the view.
Finbarr's answer is pretty solid. The one thing its missing is the answer to whether you can exclude a specific content type from the search view... yes, you can.
On the display that is your search view, add a Node: Type filter and select "Is not one of" and the content type you want to exclude.
After only a few weeks of working with Drupal I've come up with a recurring problem, which I don't really have an optimal solution to, so I'm hoping that someone here might be able to give some best practice pointers.
What I have is a region inside my node.tpl.php, which is populated with blocks that display content from two different CCK fields of the type node_reference. This works fine when displaying a single node. The problem appears when I need to use a view.
For example, lets say I have a news listing, and a single news item view. When I display the single news item I can use the news node node_reference field to reference whatever material I would like to have in my sidebar, but when on the news listing view I would like to reference nodes separately. What would be the best practice to solve this?
I'm having a few ideas, but none seem like the logical choice, how would you do?
My understanding of your problem is that you don't want the blocks to display on the view page and you want the block information displayed inline with the node.
The first part is easy, you can modify the block visibility settings to not show up on the path where you have the view.
The second part will depend on how you set up your view. If you are using fields you can simply add fields for the node_reference and they should display. If you are using a node view, you will have to override the template and create a template which displays the node reference field.
If you want further explanation please comment and I can clarify
After reading my question I realize that it was explained pretty badly, so I'll try again, and also tell how I solved it.
The Problem
On normal "pages" (when displaying only a single node), I have a sidebar that shows something similar to banners, which are either random, or I can select one or many that should always be displayed on the sidebar. This is solved easily when displaying a single node, using a CCK node_reference field. The problem is when using a View that displays multiple nodes, for example a news listing-
The Solution
In my case I could solve this by creating additional fields on my default Page content-type. These fields were called view, display and arguments. In my tpl.php I then embedded the news listing view inside a page, lets call it News. This way I gained great flexibility, and also helps the News page to know where it is located in menu structure.
Final comments
I have yet to discover if there are any drawbacks or dangers in doing this way, but if there are, feel free to share them with me :)
I tend to want to create my own modules, which create blocks and reference the database directly. Then I put the blocks inside of panels, this seems to be more flexible for me than using views and cck fields etc ...