Im using this function so far:
bool MSSQL::checkSettings()
{
QString settingsFile = "someDir/setup.ini";
QString fileName(settingsFile);
QFile file(fileName);
if(QFileInfo::exists(fileName)) {
return true;
}
else {
qDebug() << "Error: No INI File Found on path:" << settingsFile;
return false;
}
}
which works fine.
However when I wish to use an online ini file which is reachable (because can be opened via browser link), then its a false, for example if i use:
QString settingsFile = "http://localhost/something/setup.ini";
which QT should be able to read, then it doesnt work...
any ideas?
I dont see where you are using QSettings at all. You are using QFile, which is representation of a local file.
To your question:
QSettings does not able to read/write setting from URL. You have to download it manually before instantiating QSettings, See QNetworkAccessManager.
Or you may try to make your own settings provider, by using: QSettings::registerFormat() static function.
I have a resources folder/package in the root of my project, I "don't" want to load a certain File. If I wanted to load a certain File, I would use class.getResourceAsStream and I would be fine!! What I actually want to do is to load a "Folder" within the resources folder, loop on the Files inside that Folder and get a Stream to each file and read in the content... Assume that the File names are not determined before runtime... What should I do? Is there a way to get a list of the files inside a Folder in your jar File?
Notice that the Jar file with the resources is the same jar file from which the code is being run...
Finally, I found the solution:
final String path = "sample/folder";
final File jarFile = new File(getClass().getProtectionDomain().getCodeSource().getLocation().getPath());
if(jarFile.isFile()) { // Run with JAR file
final JarFile jar = new JarFile(jarFile);
final Enumeration<JarEntry> entries = jar.entries(); //gives ALL entries in jar
while(entries.hasMoreElements()) {
final String name = entries.nextElement().getName();
if (name.startsWith(path + "/")) { //filter according to the path
System.out.println(name);
}
}
jar.close();
} else { // Run with IDE
final URL url = Launcher.class.getResource("/" + path);
if (url != null) {
try {
final File apps = new File(url.toURI());
for (File app : apps.listFiles()) {
System.out.println(app);
}
} catch (URISyntaxException ex) {
// never happens
}
}
}
The second block just work when you run the application on IDE (not with jar file), You can remove it if you don't like that.
Try the following.
Make the resource path "<PathRelativeToThisClassFile>/<ResourceDirectory>" E.g. if your class path is com.abc.package.MyClass and your resoure files are within src/com/abc/package/resources/:
URL url = MyClass.class.getResource("resources/");
if (url == null) {
// error - missing folder
} else {
File dir = new File(url.toURI());
for (File nextFile : dir.listFiles()) {
// Do something with nextFile
}
}
You can also use
URL url = MyClass.class.getResource("/com/abc/package/resources/");
The following code returns the wanted "folder" as Path regardless of if it is inside a jar or not.
private Path getFolderPath() throws URISyntaxException, IOException {
URI uri = getClass().getClassLoader().getResource("folder").toURI();
if ("jar".equals(uri.getScheme())) {
FileSystem fileSystem = FileSystems.newFileSystem(uri, Collections.emptyMap(), null);
return fileSystem.getPath("path/to/folder/inside/jar");
} else {
return Paths.get(uri);
}
}
Requires java 7+.
I know this is many years ago . But just for other people come across this topic.
What you could do is to use getResourceAsStream() method with the directory path, and the input Stream will have all the files name from that dir. After that you can concat the dir path with each file name and call getResourceAsStream for each file in a loop.
I had the same problem at hands while i was attempting to load some hadoop configurations from resources packed in the jar... on both the IDE and on jar (release version).
I found java.nio.file.DirectoryStream to work the best to iterate over directory contents over both local filesystem and jar.
String fooFolder = "/foo/folder";
....
ClassLoader classLoader = foofClass.class.getClassLoader();
try {
uri = classLoader.getResource(fooFolder).toURI();
} catch (URISyntaxException e) {
throw new FooException(e.getMessage());
} catch (NullPointerException e){
throw new FooException(e.getMessage());
}
if(uri == null){
throw new FooException("something is wrong directory or files missing");
}
/** i want to know if i am inside the jar or working on the IDE*/
if(uri.getScheme().contains("jar")){
/** jar case */
try{
URL jar = FooClass.class.getProtectionDomain().getCodeSource().getLocation();
//jar.toString() begins with file:
//i want to trim it out...
Path jarFile = Paths.get(jar.toString().substring("file:".length()));
FileSystem fs = FileSystems.newFileSystem(jarFile, null);
DirectoryStream<Path> directoryStream = Files.newDirectoryStream(fs.getPath(fooFolder));
for(Path p: directoryStream){
InputStream is = FooClass.class.getResourceAsStream(p.toString()) ;
performFooOverInputStream(is);
/** your logic here **/
}
}catch(IOException e) {
throw new FooException(e.getMessage());
}
}
else{
/** IDE case */
Path path = Paths.get(uri);
try {
DirectoryStream<Path> directoryStream = Files.newDirectoryStream(path);
for(Path p : directoryStream){
InputStream is = new FileInputStream(p.toFile());
performFooOverInputStream(is);
}
} catch (IOException _e) {
throw new FooException(_e.getMessage());
}
}
Another solution, you can do it using ResourceLoader like this:
import org.springframework.core.io.Resource;
import org.apache.commons.io.FileUtils;
#Autowire
private ResourceLoader resourceLoader;
...
Resource resource = resourceLoader.getResource("classpath:/path/to/you/dir");
File file = resource.getFile();
Iterator<File> fi = FileUtils.iterateFiles(file, null, true);
while(fi.hasNext()) {
load(fi.next())
}
If you are using Spring you can use org.springframework.core.io.support.PathMatchingResourcePatternResolver and deal with Resource objects rather than files. This works when running inside and outside of a Jar file.
PathMatchingResourcePatternResolver r = new PathMatchingResourcePatternResolver();
Resource[] resources = r.getResources("/myfolder/*");
Then you can access the data using getInputStream and the filename from getFilename.
Note that it will still fail if you try to use the getFile while running from a Jar.
As the other answers point out, once the resources are inside a jar file, things get really ugly. In our case, this solution:
https://stackoverflow.com/a/13227570/516188
works very well in the tests (since when the tests are run the code is not packed in a jar file), but doesn't work when the app actually runs normally. So what I've done is... I hardcode the list of the files in the app, but I have a test which reads the actual list from disk (can do it since that works in tests) and fails if the actual list doesn't match with the list the app returns.
That way I have simple code in my app (no tricks), and I'm sure I didn't forget to add a new entry in the list thanks to the test.
Below code gets .yaml files from a custom resource directory.
ClassLoader classLoader = this.getClass().getClassLoader();
URI uri = classLoader.getResource(directoryPath).toURI();
if("jar".equalsIgnoreCase(uri.getScheme())){
Pattern pattern = Pattern.compile("^.+" +"/classes/" + directoryPath + "/.+.yaml$");
log.debug("pattern {} ", pattern.pattern());
ApplicationHome home = new ApplicationHome(SomeApplication.class);
JarFile file = new JarFile(home.getSource());
Enumeration<JarEntry> jarEntries = file.entries() ;
while(jarEntries.hasMoreElements()){
JarEntry entry = jarEntries.nextElement();
Matcher matcher = pattern.matcher(entry.getName());
if(matcher.find()){
InputStream in =
file.getInputStream(entry);
//work on the stream
}
}
}else{
//When Spring boot application executed through Non-Jar strategy like through IDE or as a War.
String path = uri.getPath();
File[] files = new File(path).listFiles();
for(File file: files){
if(file != null){
try {
InputStream is = new FileInputStream(file);
//work on stream
} catch (Exception e) {
log.error("Exception while parsing file yaml file {} : {} " , file.getAbsolutePath(), e.getMessage());
}
}else{
log.warn("File Object is null while parsing yaml file");
}
}
}
Took me 2-3 days to get this working, in order to have the same url that work for both Jar or in local, the url (or path) needs to be a relative path from the repository root.
..meaning, the location of your file or folder from your src folder.
could be "/main/resources/your-folder/" or "/client/notes/somefile.md"
Whatever it is, in order for your JAR file to find it, the url must be a relative path from the repository root.
it must be "src/main/resources/your-folder/" or "src/client/notes/somefile.md"
Now you get the drill, and luckily for Intellij Idea users, you can get the correct path with a right-click on the folder or file -> copy Path/Reference.. -> Path From Repository Root (this is it)
Last, paste it and do your thing.
Simple ... use OSGi. In OSGi you can iterate over your Bundle's entries with findEntries and findPaths.
Inside my jar file I had a folder called Upload, this folder had three other text files inside it and I needed to have an exactly the same folder and files outside of the jar file, I used the code below:
URL inputUrl = getClass().getResource("/upload/blabla1.txt");
File dest1 = new File("upload/blabla1.txt");
FileUtils.copyURLToFile(inputUrl, dest1);
URL inputUrl2 = getClass().getResource("/upload/blabla2.txt");
File dest2 = new File("upload/blabla2.txt");
FileUtils.copyURLToFile(inputUrl2, dest2);
URL inputUrl3 = getClass().getResource("/upload/blabla3.txt");
File dest3 = new File("upload/Bblabla3.txt");
FileUtils.copyURLToFile(inputUrl3, dest3);
I have a problem with writing to file, the problem is :
If I write the directory ":/Files/Scores.txt" it won't write anything but it reads from same directory.
But if I used this directory "D:/TicTacToe/TicTacToe/Scores.txt" it writes and reads but i will give the game to my instructor and the path won't be same and the file won't open, any ideas ?!
My write code:
void Write ( QString file)
{
QFile sfile(file);
if(!sfile.open(QFile::ReadOnly |QFile::Text))
{
return;
}
QTextStream in(&sfile);
QString lscores =sfile.readAll() ;
sfile.close();
if(!sfile.open(QFile::WriteOnly |QFile::Text))
{
return;
}
lscores=" "+Xscore+"\t"+" "+Oscore+"\n"+lscores;
QTextStream out(&sfile);
out <<lscores;
sfile.close();
}
Resource files (the ones you put in .qrc file) are read only, as MrEricSir mentioned. If you want to have some configuration/score file with your app you can for example use QApplication::applicationDirPath()
QString settingsFile = QApplication::applicationDirPath() % QLatin1Literal("/scores.txt");
This way you will have always absolute path to the file inside your app directory.
You can also use QDesktopServices::storageLocation with QDesktopServices::DataLocation parameter to obtain data location for your application.
In downloading files using the following codes, it surprised me that it succeeded in downloading .jpg .txt files BUT .dgn format file return IO Error #2038
Could somebody give me any advice? Thanks in advance.
protected function init(event:FlexEvent):void
{
fileRef = new FileReference();
fileRef.addEventListener(Event.COMPLETE, doEvent);
fileRef.addEventListener(HTTPStatusEvent.HTTP_STATUS, doEvent);
fileRef.addEventListener(IOErrorEvent.IO_ERROR, doEvent);
fileRef.addEventListener(SecurityErrorEvent.SECURITY_ERROR, doEvent);
}
private function doEvent(evt:Event):void
{
var fr:FileReference = evt.currentTarget as FileReference;
switch (evt.type)
{
case "complete":
Alert.show("File : " + fr.name + " download succeed");
break;
default :
Alert.show("Error occur during downloading !!!");
break;
}
protected function downLoadLICMap(event:MouseEvent):void
{
urlReq = new URLRequest("http://svygis/viewphoto/ceddphoto/20130916 raw/1se19d.dgn");
fileRef.download(urlReq);
}
I suspect Flex is not at fault here. It would rather be a server setting issue.
Have you tried opening that URL directly in the browser? You probably will not be able to download the file like that either.
If that's the case, you only need to configure a mime type for the .dgn extension on your web server.
I'll ONLY recieve an "Error #3000: Illegal path name" if I try to open a file which is placed inside the app-folder of the air. If the file is somewhere else outside of the app-folder it works.
private var file:File = File.documentsDirectory;
public function download():void{
var pdfFilter:FileFilter = new FileFilter("PDF Files", "*.pdf");
file.browseForOpen("Open", [pdfFilter]);
file.addEventListener(Event.SELECT, fileSelected);
}
private function fileSelected(e:Event):void
{
var destination:File = File.applicationDirectory
destination = destination.resolvePath("test.pdf");
/*
//This works, also if the file to copy is placed inside the appfolder
file.copyTo(destination, true);
*/
/*This Throws me an Error #3000, but ONLY if the file is located in
the App folder*/
file.openWithDefaultApplication();
}
When i try to get the same file and copy it to another place it's doing fine.
Why that? Something special to do if i wanna open files which are inside the appfolder?
It also don't work in debug mode - bin-debug.
Regards, Temo
After reading the document a few times i saw that this is not possible (it's not a bug, it's a feature!?!)
Opening files with the default system application
You cannot use the openWithDefaultApplication() method with files located in the application directory.
So I do this instead:
file.copyTo(tempFile);
tempFile.openWithDefaultApplication();
Not so nice, but it works.