Regular expression to match 'R33' and 'r34E' [closed] - asp.net

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I am looking for a regular expression that matches R33 and r34E. I tried (R|r)[0-9]{2}+[A-Z]{1} but got an error.

/[rR][0-9]{2}[A-Z]?/

It is an invalid Regular Expression. If you want to have 2 or more digits, {2}+ won't work, you should use {2,}.
(R|r)[0-9]{2,}[A-Z]?

[0-9]{2}+
That plus sign looks wrong. If you take that out:
(R|r)[0-9]{2}[A-Z]?
Appears to do what you want (upper- or lowercase R, two digits, optionally any uppercase letter).

Try ^(R|r)[0-9]{2}$|^(R|r)[0-9]{2}[A-Z]{1}$

Your regex is invalid.
You can use {2} or + on an expression, but not both.

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How to add parentheses between numbers? I know how to add dashes, are they doing the same way? [closed]

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how to add parentheses between numbers? I know how to add dashes, are they doing the same way? like 123456789 to (123)456789 in R programming?
sub("(\\d{3})", "(\\1)", 123456789)
[1] "(123)456789"

Can I use Grep or Grepl to return instances of two capital letters together in text? [closed]

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I'm interested to pull out instances where initials are used in my text data, as they are almost always two capital letters, is there a simple way to look for this text pattern using Grep in R?
If we need to match two upper case letters from the start (^) of the string, use grepl on the column concerned to return a logical expression within subset to subset the rows
subset(df1, grepl("^[A-Z]{2}", col1))

In R, is there a way to use regular expressions or something similar to extract the first and last character of an email string? [closed]

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Currently in R, with data.table, I have the following column:
jamesmann#yahoo.com
bill.free#yahoo.com
computer.trader#yahoo.com
j*****n#gmail.com
which are factors. I would like to parse the above so that I can get the first and last letters of the username before the # symbol.
So for the above I'd like to get:
jn
be
cr
jn
I deal with some asterisked usernames so I added it in too. Is there a simple way to do this? Any thoughts would be greatly appreciated.
Match the following pattern to the strings and replace it with the capture groups:
sub("(.).*(.)#.*", "\\1\\2", s)
## [1] "jn" "be" "cr" "jn"
Note
The input strings in reproducible form is:
s <- c("jamesmann#yahoo.com", "bill.free#yahoo.com", "computer.trader#yahoo.com",
"j*****n#gmail.com")

Specific code from SAS to R [closed]

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I am trying to write this (SAS) comand in R. x is a variable with this specific format: j61915035t
x1 = trim(upcase(substr(x,1,1)));
I really appreciate what you are doing in this site!
You want to remove leading/trailing blanks from a character string that is the uppercase first letter of the string x. So this should do it.
library(stringr)
x1 = str_trim(str_to_upper(str_sub(x,1,1)))

Does Postfix recipient_delimiter take multiple characters? [closed]

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According to this documentation, there is nothing stating if the delimiter can be multiple characters or a string. Can someone confirm if it is possible to use a string as the delimiter? Perhaps something like "-----"?
http://www.postfix.org/postconf.5.html#recipient_delimiter
After reading the source code it looks like that variable eventually gets used as an int. So the delimiter can only be a single character.
However, since Postfix 2.11, there can be multiple delimiters:
When the recipient_delimiter set contains multiple characters (Postfix 2.11 and later), a user name or .forward file name is separated from its extension by the first character that matches the recipient_delimiter set.
Source: http://www.postfix.org/postconf.5.html#recipient_delimiter

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