Partial ASP.NET MVC View submit - asp.net

Question

I'm new in ASP.NET MVC so the question could appear 'stupid', sorry.
I have a Partial View inside my Home view.
The Partial View submit a form calling an Action Method inside the HomeController.
It works fine with server validation, the problem is that after the post only the Partial View is rendered.
How can I render the entire Home view after post?
About the code:
Inside PartialView I have a form:
<% using (Html.BeginForm("Request", "Home")) { %>
Request is a ActionResult defined inside my HomeController.
[HttpPost]
public ActionResult Request(RequestModel model)
{
if (ModelState.IsValid)
{
// Saving data .....
}
else
{
// Show Server Validation Errors
return View();
}
}
At this time, after the post, the ascx shows the server validation erros but only the PartialView ascx code is rendered.
The Url looks like this after the post:
http://xxxxxxxxxxx/Home/Request
What I want is showing the entire Home view with the ascx inside showing server validation errors.

Answer 1

Try to do a partial submit using jQuery:
<script type="text/javascript">
$(document).ready(function () {
$("input[type=submit]").live("click", function () {
var f = $("input[type=submit]").parents("form");
var action = f.attr("action");
var serializedForm = f.serialize();
$.ajax({
type: 'POST',
url: action,
data: serializedForm,
success: function (data, textStatus, request) {
if (!data == "") {
// redisplay partial view
$("#formDiv").html(data);
}
else {
// do whatever on sucess
}
}
});
return false;
});
});
</script>
Assuming your view/ascx/HTML is something like this:
<div id="formDiv">
<% Html.RenderAction("Request"); %>
</div>

Answer 2

Change return type also:
[HttpPost]
public PartialViewResult Request(RequestModel model)
{
if (ModelState.IsValid)
{
// Saving data .....
}
else
{
// Show Server Validation Errors
return PartialView();
}
}

Answer 3

I was facing same issue in code, so I just made a small modification in my code and it worked.
Instead of returning the same view, I used
return Redirect(Request.Referrer)
Earlier:
return View();