Suppose the structure:
/foo/bar/
--file1
--file2
--file3
--folder1
--file4
--folder2
--file5
I want to run the unix zip utility, compressing the bar folder and all of it's files and subfolders, from foo folder, but not have the bar folder inside the zip, using only command line.
If I try to use the -j argument, it doesn't create the bar folder inside the zip as I want, but doesn't create folder1 and folder2. Doing -rj doesn't work.
(I know I can enter inside bar and do zip -r bar.zip . I want to know if it's possible to accomplish what $/foo/bar/ zip -r bar.zip . but doing it from $/foo).
You have to do cd /foo/bar then zip -r bar.zip ., however, you can group them with parentheses to run in a subshell:
# instead of: cd /foo/bar; zip -r bar.zip; cd -
( cd /foo/bar; zip -r bar.zip . )
The enclosed (paren-grouped) commands are run in a subshell and cd within it won't affect the outer shell session.
See sh manual.
Compound Commands
A compound command is one of the following:
(list) list is executed in a subshell environment (see COMMAND EXECUTION ENVIRONMENT below).
Variable assignments and builtin commands that affect the shell's environment do not remain in effect after the command completes.
The return status is the exit status of list.
zip doesn't have a -C (change directory) command like tar does
you can do:
cd folder1 && zip -r ../bar.zip *
from within a command line shell
or you can use bsdtar which is a version of tar from libarchive that can create zips
bsdtar cf bar.zip --format zip -C folder1 .
(this creates a folder called ./ -- not sure a way around that)
I can't speak for the OP's reasoning. I was looking for this solution as well.
I am in the middle of coding a program that creates an .ods by building the internal xml files and zipping them together. They must be in the root dir of the archive, or you get an error when you try and run OOo.
I'm sure there is a dozen other ways to do this:
create a blank .ods file in OOo named blank.ods, extract to dir named blank, then try running:
cd blank && zip -r ../blank.ods *
The way I wrote mine, the shell closes after one command, so I don't need to navigate back to the original directory, if you do simply add && cd .. to the command line:
cd blank && zip -r ../blank.ods * && cd ..
Related
Using any of the standard Robot libraries, is it possible to recursively copy the contents of a directory to an existing destination directory?
Basically, I'm looking for the equivalent of the following shell command: cp -r foo/. bar (note the trailing dot)
I tried Copy Directory but this creates a directory foo inside bar (as documented) and it doesn't stop doing that even when supplying the trailing dot. Copy Files chokes when it encounters a directory.
Is there anything I overlooked? Or do I need to just call cp -r myself?
As I only need this to work on Linux, I ended up implementing a custom keyword calling cp -r. If this is ever needed cross-platform, then I'll follow the suggestions to directly implement it in Python.
Copy Directory Contents
[Documentation] Recursively copies the contents of the source directory into the destination.
[Arguments] ${source} ${destination}
Directory Should Exist ${source}
Directory Should Exist ${destination}
${result} = Run Process cp -r ${source}/. ${destination}/
Should Be Equal As Integers ${result.rc} 0
I was trying to create some folders from a text file (arbo.txt which contains a list of directories) using:
xargs --verbose -d\n mkdir -p < /applis/arbo.txt
I guess the -d\n is not correct since I got other folders than those in arbo.txt file.
The problem is that now I'm not able to drop these folders, I tried:
rm f
rm -rf f
There are no errors, but the folder is not dropped (I can see it using ls), and when I try:
cd f
I get:
-ksh: cd: f: [No such file or directory]
Edit:
using ls I can see that the folder name is: f?.
How can I drop this folder?
Thanks
Try to use:
> xargs -n1 mkdir -p < dirs.txt
Otherwise, help out with some info on f:
> ls -l f
> file f
If what appears as f contains unprintable characters, using the file name expansion of the shell may save you the trouble to figure them out exactly. Be careful not to delete other important files that match the same name pattern!
rm -rf f*
In you command it add the ? to the folder name f. You can use the below to delete the file.
rm -rf f\?
UPDATE:-
rm -rf '<file name >'
The file name is,
All the contents in the arbo.txt file without any change.
Because your command creates only one folder with the name as all the contents in the arbo.txt file including the new line also. after that it add the ? to before each new line.
To get the folder name as easily, you can type starting name of the folder name and give tab. it give the full name of the folder.
I have a file (reviews_dataset.tar.gz) that contains many files which contains data. I am required to extract the files in this archive and then perform some basic commands on the file. So far I have created a directory named (CW) and found a command tar zxvf fileNameHere.tgz but when I run this it of course cannot find my file as I have not "downloaded it" into my directory yet? How do I get this file into my directory so that I can then extract it? Sorry if this is poorly worded I am extremely new to this.
You must either run the command from the directory your file exists in, or provide a relative or absolute path to the file. Let's do the latter:
cd /home/jsmith
mkdir cw
cd cw
tar zxvf /home/jsmith/Downloads/fileNameHere.tgz
You should use the command with the options preceded by dash like this:
tar -zxvf filename.tar.gz
If you want to specify the directory to save all the files use -C:
tar -zxf filename.tar.gz -C /root/Desktop/folder
I need to execute a short script that just renames a few files (mv).
The script is in about 50 folders, each folder is named and currently I'm executing them from the shell and moving to the next folder using:
bash rename && cd ../folder01
Then pressing up and changing the last digit(s).
Is there a way to execute the script in all folders in one line?
Sure, use a for loop:
for f in folder*; do (cd "$f" && bash rename) ; done
I want to copy a complete directory content from /home/private_html/userx/ into the /home/private_html/usery/, the problem is that the directory userx contains few symlinks, and when using the cp it just skip them (skip occurs, if symlinks directs into a file, in case if it points into the directory, it just copy WHOLE directory instead...).
The command I was using looks following:
# cp -iprv /home/private_html/userx/ /home/private_html/usery/
Has anyone a solution to copy the directory "just as it is" into other place?
On FreeBSD, cp doesn't have an -r option. It does have -R, which should do what you want:
-R If source_file designates a directory, cp copies the directory and
the entire subtree connected at that point. If the source_file
ends in a /, the contents of the directory are copied rather than
the directory itself. This option also causes symbolic links to be
copied, rather than indirected through, and for cp to create spe‐
cial files rather than copying them as normal files. Created
directories have the same mode as the corresponding source direc‐
tory, unmodified by the process' umask.
Roland is right about the -R flag. You could also use a pair of tar-processes, which would make your command a little bit more system-independent:
tar -C /home/private_html/userx/ -cpf - . | tar -C /home/private_html/usery/ -epf -