Using Drupal 6.x I have created two content types: Person and Event. Event has a custom field called Attendees (of type: Node Reference; unlimited number of values to person). When viewing a specific person how does one show all their events?
I have created a view (Personal Events) and added a block display. I enabled the block to show for content type Person. How should the view be defined? Or is there a better way?
Modules installed: CCK; Node Relationships; Views
I think one of these modules might be of help to you:
Reverse Node Reference
NodeReferrer
I have an answer to my own question. However, there maybe better answers... I can only hope.
Created content block (Personal Events)
Added this code to the body of the block. This code passes the node id argument to a view
<?php
if ( arg(0) == 'node' && is_numeric(arg(1)) && ! arg(2) ) {
$node = node_load(arg(1));
$args = array($node->nid );
$view = views_get_view('PersonalEvents');
print $view->preview('default', $args);
}
?>
Added this code to the Pages of the block [by selecting: Show if the following PHP code returns TRUE (PHP-mode, experts only)]... this drives the block to only appear person content.
<?php
//Read URL
$path=$_GET['q'];
//If URL is node page
if ( strpos($path,'node')===0){
//Parse URL to get nid
$links=explode("/",$_GET['q']);
$nid=$links[1];
//Load node
$node=node_load($nid);
//Display block only if node is of certain content type
if($node->type=='person'){
return TRUE;
}
}
return FALSE;
?>
Then created view with:
Style: Table
Relationship Content: Attendees (field_attendees); requires this relationship (checked); and Delta set to ALL.
Argument: Node: Nid; Relationship: Attendees; Hide view / Page not found (404) [selected]
Fields... simply selected Node Title and Date (for now)
Filter: Node Type = Event
Anyone have a better way?
Related
How can I hide content in a post or page after it has received a certain amount of views I have set using a shortcode in WordPress?
Let's say I make a post. I enclose some content in the shortcode. I set the content to be shown for just 500 views. Then once the post reaches 500 views, the content should disappear from the post or page.
I have tried so many other plugins but couldn't find any solutions to this. wp-limit-post-views plugin also didn't solve my problem. I need help on this.
You could try something like that:
function hide_contents_function($atts, $content) {
$attributes = shortcode_atts(
array(
'count' => 500
),
$atts
);
// Get the max counts for the current post from the DB.
// You could use either an options if the counter is global, or the post meta.
// For this example I am using options, but it's up to you the implementation
$total_count = get_option('total_count', 0);
// Alternative way using post meta to get the counter per page/post
$total_count = get_post_meta(get_the_ID(), 'post_view_count', true);
if ( ! $total_count ) {
$total_count = 0;
}
// If the count loaded from the DB is bigger than the count
// property value then return nothing.
if ( $total_count > (int)$attributes['count'] ) {
return '';
}
return do_shortcode($content);
}
add_shortcode('hide_contents', 'hide_contents_function');
The above code, will register a short code that accepts an attribute allowing you to control how many views you want to have before you hide the contents.
In this example I used a single value from options table, but you are free to use any method you like to count the total views of a single post.
To use this short code you can do something like that:
[hide_contents count="345"]I will be hidden after 345 views.[/hide_contents]
Note that if you have installed any cache system, your content will not be hidden if the page is cached! That's not a problem of the short code, but the problem will occur because of the cache.
Finally, remember to update the counter of the views on each post refresh :)
I am looking for some advice on how I might fetch an array with a list of links to node types the currently logged in user is allowed to create.
My client wants these links to populate a custom dropdown list which sits on the user profile page.
Just in case I don't manage to talk him out of it, I would like some technique/information to go on.
You will have to create a custom module. If you are creating your own module, this short snippet will give you an array ($types) with the links to content types the logged in user can create (D6). If the user cannot create any content types it will show a message:
<?php
$types = array();
foreach (node_get_types('types', NULL, TRUE) as $type) {
if (node_access('create', $type->type)) {
$types[$type->type] = l($type->name, 'node/add/' . str_replace('_', '-', $type->type));
}
}
if (count($types) == 0) {
drupal_set_message('You cannot create any content types!', 'warning');
}
?>
I'm trying to allow users to update head titles and meta descriptions for each page. I thought that an easy way to achieve this would be to add a field to the 'Basic page' content type for the page title, then check if that field is not empty in html.tpl.php and if it is not, override $head_title with this user-defined value.
However, it appears that the $node variable is not available in html.tpl.php. Can anyone suggest a way for me to make this data available in this template file, or alternatively, alter $head_title before it is sent to html.tpl.php? Thanks for reading.
Taken in part from this thread that I found: http://drupal.org/node/1041768...
In your template.php, you can do the following:
function yourtheme_preprocess_html(&$variables) {
// If on an individual node page, add the node type to body classes.
if ($node = menu_get_object()) {
$variables['head_title'] = $node-> // find your cck field here
}
}
Bit messy, but would work:
if(arg(0) == 'node' && !empty(arg(1))) {
$node = node_load(arg(1));
}
However, you might prefer http://drupal.org/project/metatags_quick (an interrim module until the full http://drupal.org/project/metatags is finished).
I made a customized template called node-mynode.tpl.php
Whenever a node of type mynode is requested, then node-mynode.tpl.php
is automatically used.
However, now user wants to see a specific menu block in this case.
Question:
How can I assign a block to a specific content type?
Hint: I have started to look at URL aliases with Pathauto.
I suspect one solution may lie in this direction.
In Drupal 6, you can configure the visibility settings of blocks. Click on the 'configure' link next to your block in the administrator backend and follow these steps -
1) Select the 'Show if the following PHP code returns TRUE (PHP-mode, experts only)' option under the 'Page specific visibility settings' tab.
2) Enter the following PHP code which checks the node type of the current node and returns TRUE accordingly -
<?php
if( arg(0) != 'node' || !is_numeric(arg(1)) )
{ return FALSE;
}
//load a fully-populated Drupal node object
$temp_node = node_load(arg(1));
if( $temp_node->type == 'mynode' ) //check the node type
{ return TRUE; //display block
}
?>
This should work....
you can use the context module
Give all of your mynode type nodes an automatic alias that starts with /mynode and use the page specific visibility settings for the block, showing only on the pages that start with /mynode/*.
I have a Drupal 6.14 site with Views module. I have a view and on the primary links I put a link to the view.
There is a way to hide the link in the primary menu only if the view is empty?
You could probably do this either via a theme or module implementation of preprocess_page (THEMENAME_preprocess_page(&$vars) or MODULENAME_preprocess_page(&$vars)), but mac above is correct in that views are not known to be empty or not until they are run, so there will be a performance hit.
Within the function, you should have access to the structured primary links array, so you can run the view:
$view = views_get_view('view_name');
// Swap out 'default' for a different display as needed. Also, $args are arguments, and can be left out if not applicable.
$output = $view->preview('default', $args);
if (empty($view->result)) {
// The view has no results, alter the primary links here to remove the link in question.
}
I am ready to be contradicted any moment as I never implemented anything like that, however I am under the impression that since views are essentially queries against the DB, you can't actually know if a view is empty until you actually invoke it.
Consider that - given you are speaking about primary links (shown on nearly every page of your site) this might be a serious performance hit, depending on the complexity of the view and on its "cacheability".
You should also consider whether the content of that view can be changed by other users browsing the site at the same time that "our" user: should the view become populated after "our" user has loaded the page, "our" user won't ever know.
As on how to achieve what you want, please see the accepted answer.
HTH!
I override views_embed_view() to only provide output if there is content, and then call my override from the theme layer:
function mymodule_embed_view($name, $display_id = 'default') {
// handle any add'l args (this hook supports optional params)
$args = func_get_args();
array_shift($args);
if (count($args)) {
array_shift($args);
}
$view = views_get_view($name);
$output = $view->preview($display,$args);
if ($view->result) {
return $output;
}
}
Then in the template file:
<?php
$view = mymodule_embed_view('view_name');
if (strlen($view) > 0) {
print $view;
}
?>