grep - put part of string into variable - unix

I'm using swfdump to be able to get the ID number of an audio file. Here is what I'm using:
swfdump -D /Users/home/folder/file.swf | grep -i mp3
That is outputting:
[00e] 28999 DEFINESOUND defines id 0006 (MP3 22Khz 16Bit mono)
What I need is the id #..in this case it is 0006. i want that number in a variable. Anyone know how to do this?


the_id=`swfdump -D /Users/home/folder/file.swf | grep -i mp3 | cut -d' ' -f6`


var=$(swfdump -D /Users/home/folder/file.swf | sed '/MP3/s/.*id //;s/ (.*//')
or Bash
$ s=$(swfdump -D /Users/home/folder/file.swf)
$ var=${s/(MP3*}
$ echo $var
0006

Related

While loop skips the first line in output

I'm using the below command in Terminal on a Mac to read a file of email addresses and convert them to a MD5 hash.
tr -d " " < em.txt | tr '[:upper:]' '[:lower:]' | while read line; do
(echo -n $line | md5); done | awk '{print $1}' > hashes1.txt
This produces a file of hashes that are 1 row shorter than the original input file. But I can't figure out why.
This code does a few things, below.
Converts an email address to all lower case
Converts the email address to a MD5 Hash
Outputs a list of new email addresses to a hashes1.txt file
Thanks in advance!

Your tr command is wrong : it should be :
tr -d " " < em.txt |
tr '[[:upper:]]' '[[:lower:]]' |
while IFS= read -r line; do
echo -n "$line" | md5 | awk '{print $1}' >> hashes1.txt
done
or
while IFS= read -r line; do
echo -n "$line" | md5 | awk '{print $1}' >> hashes1.txt
done < <(tr -d " " < em.txt | tr '[[:upper:]]' '[[:lower:]]')
Changed the file feeding place too.
And ensure your file don't have strange characters with
od -c file
if yes, install dos2unix, then :
dos2unix file
or using perl :
perl -i -pe 's/\r//g' file

Considering quotes and few special characters in string

I want to execute the below command in remote servers..
find /usr/nsh/NSH/Transactions/log -name "bldeploy-*" -and -printf
'%T#:%p\n' | sort -V | sed -r 's/^[^:]+://'|xargs egrep -i
"VANTAGE_CORE-APP"|tail -1|cut -d '"' -f2
how can i put this single command in string???
I have trying this way but its not working.
Dim str as string = "-above command-"
Can anyone let me know, how can place this whole command in one string considering all quotes.
Thanks for your help.

Since this looks like VB.NET, you simply need to escape the double quotes (" --> "").
Like so:
Dim str as string = "find /usr/nsh/NSH/Transactions/log -name ""bldeploy-*"" -and -printf '%T#:%p\n' | sort -V | sed -r 's/^[^:]+://'|xargs egrep -i ""VANTAGE_CORE-APP""|tail -1|cut -d '""' -f2"

Using sed to enclose matches in double quotes

I'm trying to extract headers from emails and create a JSON fragment from them. I'm using sed to pull out the keys and values, but it's failing to put the trailing quote on each of the lines:
$ cat email1 | grep -i -e "^subject:" -e "^from:" -e "^to:" | \
sed -n 's/\^([^:]*\):[ ]*\(.*\)$/"\1":"\2"/gp'
"From":"Blah Blech <blah.blech#blahblech.com>
"To":"foo#bar.com
"Subject":"Yeah
I don't understand why the replacement pattern isn't working.

awk to the rescue!
$ awk -F": *" -vOFS=":" -vq="\"" 'tolower($0)~/^from|to|subject/
{print q$1q,q$2q}' email1
which combines cat or grep steps as well.

Stripping the carriage returns as #tripleee suggested fixed the issue with sed (using ctrl-v ctrl-m to capture the literal carriage return):
$ cat email1 | tr -d '^M' | grep -i -e "^subject:" -e "^from:" -e "^to:" | \
sed -n 's/^\([^:]*\):[ ]*\(.*\)$/"\1":"\2"/gp'
"From":"Blah Blech <blah.blech#blahblech.com>"
"To":"foo#bar.com"
"Subject":"Yeah"

Find word count using wc and assign to a variable

i want the word count wc -w value be assigned to a variable
i've tried something like this, but i'm getting error, what is wrong?
winget="this is the first line"
wdCount=$winget | wc -w
echo $wdCount

You need to $(...) to assign the result:
wdCount=$(echo $winget | wc -w)
Or you could also avoid echo by using here-document:
wdCount=$(wc -w <<<$winget)

You can pass word count without the filename using the following:
num_of_lines=$(< "$file" wc -w)
See https://unix.stackexchange.com/a/126999/320461

You can use this to store the word count in variable:
word_count=$(wc -w filename.txt | awk -F ' ' '{print $1}'

How do I Get the distinct List of Special Characters from a File using GREP or SED?

I have a file which contains about 30000 Records delimited by '|'. I need to get a distinct list of special characters only from the file.
For Eg:
123|fasdf|%df&|pap,came|!
234|%^&asdf|34|'":|
My output should be:
|%&,!^'":
Any help would be greatly appreciated.
Thanks,
Velraj.

grep -o '[|%&,!^":]' input | sort -u
You have to list all your special characters inside brackets.
This will return each unique special character on its own line. If you really need a string with these characters you have to remove newlines afterwards, e.g.:
grep -o '[|%&,!^":]' input | sort -u | tr -d '\n'
UPDATE:
If you need to remove all characters which are not from 'a-zA-Z0-9' set then you can use this one:
grep -o '[^a-zA-Z0-9]' input | sort -u | tr -d '\n'

echo "123|fasdf|%df&|pap,came|! 234|%^&asdf|34|'\":|" \
| { tr -d '[[:alnum:]]'; printf "\n"; } \
| sed 's/\(.\)/\1_/g' \
| awk -v 'RS=_' '{print $0}' \
| sort -u \
| awk '{printf $0}END{printf "\n"}'
output
!"%&',:^||
You can replace the first line echo .... with cat fileName

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