I want to convert and restrict the DateTime to 12 hours format.
Right now the output is: 02-01-2022 18:30 PM
But I want to convert into: 02/01/2022 06:30 PM +00:00.
DateTime.Now.ToString("MM/dd/yyyy hh:mm tt")
Add tt at last for AM/PM
string CustomDateFormat = DateTime.Now.ToString("MM/dd/yyyy hh:mm tt +00:00");
or
string CustomDateFormat = DateTime.Now.ToString("MM/dd/yyyy hh:mm tt") + "+00:00";
where hh is for 12 hours format and tt for AM/PM as in this documentation.
I have users entering a date and a time zone (e.g. "America/Los Angeles") for that date and I'd like to convert that to UTC but to do that I need the utc offset for the time on that date.
I can easily convert a date to the offset for the time zone if I already know the UTC date but I need the other way around...
The utc offset can change depending on the date due to daylight saving so I need a way to enter a date and a timezone and get back the offset from UTC using that.
Knowing the most recent switch from PST to PDT On march 11 at 2AM I tried using
var tzOffset = moment.tz("3/11/2018 3:00 AM", "America/Los_Angeles").utcOffset();
document.write('utc offset is : ' + tzOffset + '<br/>') ;
but that gives 480 when the correct answer is 420
I can get the correct answer 420 if I use parseZone like so:
var tzOffset2 = moment.parseZone("3/11/2018 3:00 AM -07:00").utcOffset();
document.write('utc offset2 is : ' + tzOffset2 + '<br/>') ;
but that means I need to already know the -7 offset that I'm trying to find...
So how do I find the utcOffset for a specific date/time like "3/11/2018 3:00 AM" and timezone like "America/Los_Angeles"? Thanks
Your input is not in a ISO 8601 or RFC 2822 format recognized by moment(String), so you have to specify the format as second parameter using moment(String, String) (please note that, as docs states: The moment.tz constructor takes all the same arguments as the moment constructor, but uses the last argument as a time zone identifier.)
Your code could be like the following:
var tzOffset = moment.tz("3/11/2018 3:00 AM", "D/M/YYYY h:mm A", "America/Los_Angeles").utcOffset();
document.write('utc offset is : ' + tzOffset + '<br/>') ;
<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.22.1/moment.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/moment-timezone/0.5.14/moment-timezone-with-data-2012-2022.min.js"></script>
I have two columns in an access 2010 database with some calculated field:
time_from time_until calculated_field(time_until-time_from)
10:45 15:00 4:15
13:15 16:00 2:45
11:10 16:00 4:50
08:00 15:00 7:00
08:00 23:00 15:00
Now so far, it is good: calculated field did its job to tell me total hours and mins...
now, I need a sum of a calculated field....
I put in an expression builder: =Sum([time_until]-[time_from])
I guess total sum should give me 33:50... but it gives me some 9:50. why is this happening? Is there a way to fix this?
update:
when I put like this:
=Format(Sum([vrijeme_do]-[vrijeme_od])*24)
I get a decimal point number... which I suppose is correct....
for example, 25hrs and 30mins is shown as 25,5
but, how do I format this 25,5 to look like 25:30?
As #Arvo mentioned in his comment, this is a formatting problem. Your expected result for the sum of calculated_field is 33:50. However that sum is a Date/Time value, and since the number of hours is greater than 24, the day portion of the Date/Time is advanced by 1 and the remainder 9:50 is displayed as the time. Apparently your total is formatted to display only the time portion; the day portion is not displayed.
But the actual Date/Time value for the sum of calculated_field is #12/31/1899 09:50#. You can use a custom function to display that value in your desired format:
? duration_hhnn(#12/31/1899 09:50#)
33:50
This is the function:
Public Function duration_hhnn(ByVal pInput As Date) As String
Dim lngDays As Long
Dim lngMinutes As Long
Dim lngHours As Long
Dim strReturn As String
lngDays = Int(pInput)
lngHours = Hour(pInput)
lngMinutes = Minute(pInput)
lngHours = lngHours + (lngDays * 24)
strReturn = lngHours & ":" & Format(lngMinutes, "00")
duration_hhnn = strReturn
End Function
Note the function returns a string value so you can't do further date arithmetic on it directly.
Similar to the answer from #HansUp, it can be done without VBA code like so
Format(24 * Int(SUM(elapsed_time)) + Hour(SUM(elapsed_time)), "0") & ":" & Format(SUM(elapsed_time), "Nn")
I guess you are trying to show the total in a text box? the correct expression would be =SUM([calculated_field_name]).
I am working on a calendar application and I want to display the date such as: mm/dd/yy. The reason for this is because on mobile devices some of my dates are getting recognized as phone numbers when it is in mm/dd/yyyy. I couldn't find a VBScript function to accomplish this so I tried it with the following code:
listyear = Year(strlistdate)
listyearabbr = Right(listyear, 2)
strlistdate = Replace(strlistdate, listyear, listyearabbr)
Where strlistdate is the initial date returned from the database. I then display the date using Response.write("<td>" &FormatDateTime(strlistdate,2)&"</td>")
This didn't work and I was wondering if someone could give me a few pointers on how to achieve this.
Thanks
I don't think that this is a good approach, because you'll end up returning the same date format for all locales, but you could do this:
response.write(Month(strlistdate) & "/" & Day(strlistdate) & "/" & Right(Year(strlistdate),2))
Anytime you use FormatDateTime, it will create a year based on the definition stored on the server. If the server can be set to mm/dd/yy, then you can get the output you want without doing any of the above.
Also, look into the format function. You should be able to do this:
response.write(Format(strlistdate, "m/dd/y")
You could try this idea. I haven't used date formatting for years. Instead I construct the date field like so...
strDay = Day(Date)
strMonth = Month(Date)
strYear = Year(Date)
strHours = Hour(Now)
strMins = Minute(Now)
strSecs = Second(Now())
if len(strMonth) = 1 then
strMonth = "0" & strMonth
end if
if len(strDay) = 1 then
strDay = "0" & strDay
end if
if len(strHours) = 1 then
strHours = "0" & strHours
end if
if len(strMins) = 1 then
strMins = "0" & strMins
end if
if len(strSecs) = 1 then
strSecs = "0" & strSecs
end if
strDateAdded = strYear & "-" & strMonth & "-" & strDay
strDateAddedTime = strDateAdded & " " & strHours & ":" & strMins
Using this method you have complete control over the order and even when running your web app in different time zones, you still maintain DD/MM format... or whatever order you want such as MM-DD-YY (by reordering and trimming the year). Personally I prefer YYYY-MM-DD because sorting by ASC and DESC is a lot easier to work with, ie: easier to read because all rows will have the same number of characters like:
2013-04-01 03:15
2013-04-09 10:15
2013-04-22 07:15
2013-04-23 10:15
2013-04-23 10:60
2013-10-25 12:01
2013-10-25 12:59
Instead of:
2013-4-1 3:15
2013-4-9 10:15
2013-4-22 7:15
2013-4-23 10:15
2013-4-23 10:60
2013-10-25 12:1
2013-1-25 12:59
I have a tab delimited file where each record has a timestamp field in 12-hour format:
mm/dd/yyyy hh:mm:ss [AM|PM].
I need to quickly convert these fields to 24-hour time:
mm/dd/yyyy HH:mm:ss.
What would be the best way to do this? I'm running on a Windows platform, but I have access to sed, awk, perl, python, and tcl in addition to the usual Windows tools.
Using Perl and hand-crafted regexes instead of facilities like strptime:
#!/bin/perl -w
while (<>)
{
# for date times that don't use leading zeroes, use this regex instead:
# (?:\d{1,2}/\d{1,2}/\d{4} )(\d{1,2})(?::\d\d:\d\d) (AM|PM)
while (m%(?:\d\d/\d\d/\d{4} )(\d\d)(?::\d\d:\d\d) (AM|PM)%)
{
my $hh = $1;
$hh -= 12 if ($2 eq 'AM' && $hh == 12);
$hh += 12 if ($2 eq 'PM' && $hh != 12);
$hh = sprintf "%02d", $hh;
# for date times that don't use leading zeroes, use this regex instead:
# (\d{1,2}/\d{1,2}/\d{4} )(\d{1,2})(:\d\d:\d\d) (?:AM|PM)
s%(\d\d/\d\d/\d{4} )(\d\d)(:\d\d:\d\d) (?:AM|PM)%$1$hh$3%;
}
print;
}
That's very fussy - but also converts possibly multiple timestamps per line.
Note that the transformation for AM/PM to 24-hour is not trivial.
12:01 AM --> 00:01
12:01 PM --> 12:01
01:30 AM --> 01:30
01:30 PM --> 13:30
Now tested:
perl ampm-24hr.pl <<!
12/24/2005 12:01:00 AM
09/22/1999 12:00:00 PM
12/12/2005 01:15:00 PM
01/01/2009 01:56:45 AM
12/30/2009 10:00:00 PM
12/30/2009 10:00:00 AM
!
12/24/2005 00:01:00
09/22/1999 12:00:00
12/12/2005 13:15:00
01/01/2009 01:56:45
12/30/2009 22:00:00
12/30/2009 10:00:00
Added:
In What is a Simple Way to Convert Between an AM/PM Time and 24 hour Time in JavaScript, an alternative algorithm is provided for the conversion:
$hh = ($1 % 12) + (($2 eq 'AM') ? 0 : 12);
Just one test...probably neater.
It is a 1-line thing in python:
time.strftime('%H:%M:%S', time.strptime(x, '%I:%M %p'))
Example:
>>> time.strftime('%H:%M:%S', time.strptime('08:01 AM', '%I:%M %p'))
'08:01:00'
>>> time.strftime('%H:%M:%S', time.strptime('12:01 AM', '%I:%M %p'))
'00:01:00'
Use Pythons datetime module someway like this:
import datetime
infile = open('input.txt')
outfile = open('output.txt', 'w')
for line in infile.readlines():
d = datetime.strptime(line, "input format string")
outfile.write(d.strftime("output format string")
Untested code with no error checking. Also it reads the entire input file in memory before starting.
(I know there is plenty of room for improvements like with statement...I make this a community wiki entry if anyone likes to add something)
To just convert the hour field, in python:
def to12(hour24):
return (hour24 % 12) if (hour24 % 12) > 0 else 12
def IsPM(hour24):
return hour24 > 11
def to24(hour12, isPm):
return (hour12 % 12) + (12 if isPm else 0)
def IsPmString(pm):
return "PM" if pm else "AM"
def TestTo12():
for x in range(24):
print x, to12(x), IsPmString(IsPM(x))
def TestTo24():
for pm in [False, True]:
print 12, IsPmString(pm), to24(12, pm)
for x in range(1, 12):
print x, IsPmString(pm), to24(x, pm)
This might be too simple thinking, but why not import it into excel, select the entire column and change the date format, then re-export as a tab delimited file? (I didn't test this, but it somehow sounds logical to me :)
Here i have converted 24 Hour system to 12 Hour system.
Try to use this method for your problem.
DateFormat fmt = new SimpleDateFormat("yyyyMMddHHssmm");
try {
Date date =fmt.parse("20090310232344");
System.out.println(date.toString());
fmt = new SimpleDateFormat("dd-MMMM-yyyy hh:mm:ss a ");
String dateInString = fmt.format(date);
System.out.println(dateInString);
} catch (Exception e) {
System.out.println(e.getMessage());
}
RESULT:
Tue Mar 10 23:44:23 IST 2009
10-March-2009 11:44:23 PM
In Python: Converting 12hr time to 24hr time
import re
time1=input().strip().split(':')
m=re.search('(..)(..)',time1[2])
sec=m.group(1)
tz=m.group(2)
if(tz='PM'):
time[0]=int(time1[0])+12
if(time1[0]=24):
time1[0]-=12
time[2]=sec
else:
if(int(time1[0])=12):
time1[0]-=12
time[2]=sec
print(time1[0]+':'+time1[1]+':'+time1[2])
Since you have multiple languages, I'll suggest the following algorithm.
1 Check the timestamp for the existence of the "PM" string.
2a If PM does not exist, simply convert the timestamp to the datetime object and proceed.
2b If PM does exist, convert the timestamp to the datetime object, add 12 hours, and proceed.