When I have
<ul class="menu">
<li>link</li>
</ul>
how do I make the LI-tag change a property (e.g. list-style-image) when is hovered (a:hover)?
You can apply hover to the li as well:
ul.menu li:hover
{
list-style-image: url(highlight.gif);
}
Note (Thanks to Andy E): :hover is not supported in IE6, and supported for links only in IE7. (See compatibility table here). There is a workaround for IE6 and 7 named whatever:hover.
On modern browsers you can use li:hover but on older ones you would have to use javascript.
Edit: By the way, if you set:
a {
display:block;
}
you can do all the styling on the a and you don´t need to style the li.
You can give add directly into anchor element which is sub element of li element
li a:hover { ..style.. }
Or you can add a class for anchor to do that
li a.HoverClass:hover { ..style.. }
There is a basic example here
Related
How do you change styles of another element based on whether the first element is empty.
<ul></ul>
<ul>
<li>....</li>
<li>....</li>
<li>....</li>
</ul>
In the above code, I want to give a style for the second ul { color:red } (to be more exact the ul that follows) ONLY if the first ul is empty.
Is there a pure CSS solution for this?
You can do this, but only if the element in question is completely empty- yes, not even a whitespace.
http://jsfiddle.net/NicoO/uTJ4N/
ul:empty + ul
{
color: red;
}
To be more accurate, this is the selector you need for the first empty <ul> of the body and the exact following <ul>:
body > ul:first-of-type:empty + ul
{
color: red;
}
http://jsfiddle.net/NicoO/uTJ4N/1/
Try this code:
ul > li {
color: red;
}
Its selects the ul which has a li as child element. And those can be colored red then.
http://jsfiddle.net/keypaul/KfaQv/1/
ul:not(:empty) {
color:red;
}
I dont think a pure css solution is the way to go, but you can use a pre-processor as they allow you to pass conditional statements.
I have:
<ul>
<li></li>
<li></li>
<li></li>
<li></li>
<li></li>
</ul>
I want to add a different width to each li.
I don't want to do it inline.
How can I target each li using CSS2 (not CSS3)?
Is there a way or do I need to give each li a class name?
Thanks
Why not use nth-of-type
ul li:nth-of-type(1){} /* First */
ul li:nth-of-type(2){} /* Seconds */
and if you're worried about older browsers, there's a great library that adds CSS3 pseudo-classes to them.
The only CSS2 way would be to add classes to each LI.
EDIT
Actually the different classes per LI isn't the only CSS2 way. #Hashem Qolami comment to the original question has a decent CSS2 solution, but like he says, it looks a little silly.
you can also use comb css as you have to add class for each li in CSS
e:g-
li {}
li + li {}
li + li + li {}
li + li + li + li {}
li + li + li + li + li {}
By "each li" do you mean each li element individually? if so, the nth selector might be your friend, though it is CSS3.
You can give class names to all your li and set to display block, with float.
Sample fiddle:
li{
display:block;
float:left;
background:blue;
}
li.small{
width:50%;
}
li.big{
width:100%;
}
If you want to use pure CSS2, you have to give them class names. This could be accomplished with the :nth-of-type() psuedoclass selector but that is a CSS3 feature.
This would be very simple to do with jQuery as well (if you want to avoid relying on CSS3 but don't want to add class names to your markup). This also would have the advantage of allowing you to dynamically change the widths as needed (rather than hard-coding property values as CSS classes).
I have the following:
<a class="folder"><span>Background</span></a>
and the following CSS:
ul.arbo li > a:hover span,
ul.arbo li > a.current span {
background: #999999;
}
How can I modify the CSS so it does NOT apply if the link has a class of folder. In other words so it will not apply for the above HTML
You can do in css with negation pseudo-class selector :not , as follows:
:not(.folder) {
}
See working demo (provided by insertusernamehere).
CSS3 has the :not() selector, which you can add to your CSS (or you could do this with jQuery, either way). Mind you, this will only work in newer browsers.
http://www.w3schools.com/cssref/sel_not.asp
:not(.folder)
In your instance:
ul.arbo li > a:not(.folder):hover span,
ul.arbo li > a:not(.folder).current span { }
You don't need JavaScript or jQuery for this, and you can do it without CSS3 too (which may be relevant depending on what browsers you plan on supporting).
Just add another rule to prevent the background from changing on certain elements, like this:
ul.arbo li > a.folder:hover span
{
background: inherit;
}
Working example.
:not(.folder) {
}
Is a good solutions.Don't forget to check what browser do you want too work!
:not selector is a CSS3 selector and not all the browser support it...for example IE8 and earlier do not support the :not selector.
Morning Guys,
I have a CSS issue that's driving me up the wall. I have an unordered list with custom bullet images:
.mainTable ul {
list-style-position: inside;
list-style-image: url(../img/bullet_white.png);
line-height: 18px;
color: #335;
}
Now some of these list items contain links and some do not. For the ones that do, I'd like the bullet to change on rollover. Not too tricky you'd think... Here's how I marked it up:
.mainTable ul li a:link {
padding-left:0px; // using padding as a test
}
.mainTable ul li a:hover {
list-style-image: url(../img/bullet_red.png);
padding-left:2px; // padding changes (moves link text), but bullet's still white
}
Now I've sussed (as the padding changes) that the styling is being applied to the inner link, and not the "li" container. I tried testing:
.mainTable ul li:hover
and the image changes, but it changes for all "li" tags in scope (because that's what I've told it to do), but that's not what I'm after. There must be a simple way of doing this without resorting to js but I'll be buggered if I can figure it out.
Any suggestions? All help (even if it's just "You need to use js you nugget") gratefully appreciated :)
Danny
GOT IT SORTED! (can't answer my own question yet - for some reason...)
Thanks for the heads up guys. The answer is a mixture of the above suggestions. Moving the bullets from the li tags and on to the anchors worked a treat, but the list items without the link got no bullet...DOH!
I then set up another class, "notALink", and stuck my default list styling on it. Here's the Markup if anyone's interested...
.mainTable ul { /* kill formatting on the ul */
list-style-position: inside;
line-height: 18px;
color: #335;
list-style-type: none;
}
.mainTable ul li a:link { /* link becomes the list, essentially */
list-style-image: url(../img/bullet_white.png);
list-style-position: inside;
display: list-item;
}
.notALink { /* looks like link above, just ain't a link */
list-style-image: url(../img/bullet_white.png);
list-style-position: inside;
display: list-item;
}
.mainTable ul li a:hover { /* changes the bullet image on rollover - nugget! :) */
list-style-image: url(../img/bullet_red.png);
}
Works fine - Cheers peeps, you've dug me out of a little hole I was digging myself
Danny
No, there is no way to change parent on child hover in pure CSS (2 or 3). See: Is there a CSS parent selector?
So you have two options:
Use JavaScript
or
Leave list style as empty and add bullets to childs (a or something else). That way, you will change style of a, not li.
This is what I would do;]
or (from Yi Jiang comment)
Add extra class to li elements containing a
What you can do is style the a as display: block and move it to the left (using negative margin) to cover the li:s bullet. Check this fiddle:
http://jsfiddle.net/TG5Lj/
You may need to set a background-color to the a as well if your a:s background-image doesn't completely cover the li:s.
Try applying styling to
.mainTable ul li:hover li
or something like that. It should override the rule for the parents.
EDIT: Sorry, I didn't fully understand your question. It seems to me that it's impossible to do with css as you would have to apply styling to "a li that has no 'a' descendants", which I don't think can be expressed in css selectors. As a walkaround in order not to use scripts I suggest that you change the background of the link and not the bullet image.
i have list like that:
<ul>
<li><a...>...</a></li>
<li>...</li>
</ul>
where both type of listelements are there multiple times in arbitrary order.
Is there a way to format those li's differently? (different list-style-image) The only difference is that the one kind contains a link and the other one doesnt.
No, there is no way in CSS to specify a selector depending on the child elements.
You would have to add something to distinguish the li elements themselves, like a class on all li elements that contains links.
If you can use jQUery, you could add the class to the li elements that contains anchor tags:
$('li:has(a)').addClass('linkItem');
A non-jQuery solution could look like this:
var items = document.getElementsByTagName('LI');
for (var i=0; i<items.length; i++) {
if (items[i].getElementsByTagName('A').length > 0) {
items[i].className = 'linkItem';
}
}
sure. If you give each different li a class you can do it simple. Or you can always do this if you can't use classes.
ul li
{
styles....
}
ul li a
{
styles....
}
The styles in the first class will apply to all li elements and styles in the second class will apply to the < a > tags respectively.
You can't do this with CSS alone, you could use Javascript to accomplish this. Here's an example using jQuery:
$('ul li a').each(function() {
$(this).parent().css('list-style-image', 'url("/path/image.gif")');
});
This will set the style for the li tags, not the a tags. Technically, the list-style-image property is supposed to be set for ul tags, not li, but most (all?) browsers handle it the way you would expect when you style the li tags individually.
Hello there
I would add a <p></p> tag like this:
<ul>
<li><a...>...</a></li>
<li><p></p></li>
</ul>
And then apply 2 different styles like this:
ul a {display:block; padding:3em; background: #ccc;}
ul p {display:block; padding:3em; background: #aaa;}
I would not recommend using javascript for this, some people block javascript ect. but it depends. I would perfer css/html.
Edit:
For some reason you can write <p></p> without making it code - Fixed
Also I might have overlooked that you wanted to apply list-style-image, then this will not work.
This is what classes are for. In HTML:
<ul>
<li class="linked"><a...>...</a></li>
<li>...</li>
</ul>
and in CSS
ul li {...}
ul li.linked {...}