Function to create the array by reading the file - unix

Question

I am creating scripts which will store the contents of pipe delimited file. Each column is stored in a separate array. I then read the information from the arrays and process it. There are 20 pipe delimited files and I need to write 20 scripts. The processing that will happen in each script after the information is stored in the array is different. The number of columns in each pipe delimited file is different (but in no case it would be more than 9 columns). I need to do this activity of storing the information in the array in the beginning of each script. The way I am doing it at present is given below. I want help from you to understand how can I write a function to do this activity.
cat > example_file.txt <<End-of-message
some text first row|other text first row|some other text first row
some text nth row|other text nth row|some other text nth row
End-of-message
# Note that example_file.txt will available. I have created it inside the script just to let you know the format of the file
OIFS=$IFS
IFS='|'
i=0
while read -r first second third ignore
do
first_arr[$i]=$first
second_arr[$i]=$second
third_arr[$i]=$third
(( i=i+1 ))
done < example_file.txt
IFS=$OIFS

Answer 1

Here is a sort-of minimal change to your script that should get you further...
...
...
while read -r first second third ignore
do
arr0[$i]=$first
arr1[$i]=$second
arr2[$i]=$third
(( i=i+1 ))
done < example_file.txt
IFS=$OIFS
proc0 () {
for j in "$#"; do
echo proc0 : "$j"
done
}
proc1 () {
echo proc1
}
proc2 () {
echo proc2
}
for i in 0 1 2; do
t=arr$i'[#]'
proc$i "${!t}"
done