Tree Show toolTip during drag - apache-flex

I am denying a user the ability to drop into my tree during certain conditions, it's all going well, but I want to tell the user why I'm denying the drop. I would prefer to do it with a toolTip, but it doesn't seem to work. Can I not have a toolTip during a drag operation? How can I force one?
Flex seems to treat toolTips as a property of the UI component, with the component deciding when and if to show it. I would like it to force it to be like doing one in javaScript where it was always just like saying "Show it now" "stop showing it now"
Does anyone know about doing this during drag?
Thanks
~Mike

What you could try is to show the tooltip yourself with the mx.managers.ToolTipManager. Create for example a VBox that implements mx.controls.ToolTip and displays the message you want to show to the user.
You can see a working example at FlexExamples.
Another idea is to show a programmatic mouse cursor when the drop is denied. I've just read an article about that on Inside Ria.

Related

No event getting generated on button click in MFC

I have a dialog based application. I have one static text control and a button on this, both of which I have made invisible in the beginning. I want to show both the controls on reaching a certain condition. When I click this button, again I want to make both the controls invisible.
However, I am able to show and hide the control and also captured the button click event like this:
ON_BN_CLICKED(IDC_MY_BUTTON, &MyDlg::OnBnClickedMyButton)
and defined OnBnClickedMyButton().
But when I press the button, it is not pressed and the event is also not generated.
Any suggestions?
First check if the IDC_MY_BUTTON exists and is valid.
Remember to add DECLARE_MESSAGE_MAP() at the header file.
Also check at the BEGIN_MESSAGE_MAP(MyClass,MyParentClass) if the class
and the parent class you write are right.
I hope this helps.
I think the IDC_MY_BUTTON maybe is invalid or other control has the same ID.
Well, finally I have come to know that though the button was visible but on clicking it was not taking control, hence I used BringWindowToTop() to draw it on top. Now it is being clicked and OnBnClickedMyButton() is also being called.
But now the issue is that after calling BringWindowToTop() the button is not shown. It is shown only when I take the mouse pointer on it. Not able to understand what is the issue.

JavaFX 8 Dialog Button Area

Please see this gist to see what I am trying to achieve: https://gist.github.com/d9e22915234e6ea34d20
The code is heavily cut down on the problem I face. As you can see when running the code there is a "miss" detected on the label or the text area (if you miss it by 5em or whatever). Unfortunately this does not work for the Dialog's own buttons OK and Cancel (Please run the code and you will see immediately what i am talking about). If you click near an FX-Node it should detect wheter you missed it or not.
Does anybody know if it is possible to detect clicks in the Dialogs button area?
And if it is possible, how to link them to the node like the label and the area?
Thank you in advance.
From what you're seeing, I would guess that the Dialog consumes click events in the button bar, so they don't make it to the Window (which is where you added the EventHandler). If you really want to do this, you can change addEventHandler to addEventFilter. This works for me.
Read this tutorial if you want to find out why this works:
http://docs.oracle.com/javase/8/javafx/events-tutorial/processing.htm#CEGJAAFD

How to make Qt widgets do not react on mouse click

I need on my form ordinary widgets (e.g. buttons) do not react on mouse clicks but NOT to be disabled (it change look to grayed one -- not good).
I wonder is there some neat small hack for this?
You could stick in an event filter and filter out the mouse events before passing the remaining events on for processing, but I'm not sure that not giving the user a visual clue that certain elements are effectively disabled is such a good idea.
You could try using style sheets to control how the disabled mode of the buttons in your form get styled. Unfortunately I'm not sure exactly how to do that but you could have a look at the style sheet docs to get you started.

Detecting out-of-view flex controls

In my flex app I have custom tooltips on buttons that hide and show based on user context.
The problem that I dealing with is that when I call my showTips() function I only want to show tooltips on the buttons that visible in the view. So buttons that on a un-selected tab (tabNavigator) should not show the tooltips.
For some reason all tooltips are showing.
Is there a way to detect if a button is not in current view, like on a un-selected tab?
If you gave us some code I could check this out, but would this work?
if(button.parent.visible) { showTip(button);}
Instead of custom coding for each button, make use your tabnavigator's creation policy is set to "auto".
Check this link for more details
http://livedocs.adobe.com/flex/3/html/help.html?content=layoutperformance_05.html

Navigation issue in Flex - ViewStack, states or something else?

I have a bit of doubt regarding my application which is being created using Mate framework. The first thing user has to do is to log in, so I created Login.mxml view. After a successful login I need to display the main view with applicationControlBar at the top and a workspace below. At the moment I have two separate views, so if I understand correctly it makes sense using ViewStack.
Thing is, I'd like also to display some kind of panel with buttons on top of the workspace after login - here is screenshot. After clicking on a button the panel should dissapear. To complicate things a little bit more, there is a possibility for this panel to change state. Clicking on a specific button may result in showing progress bar at the bottom of panel.
I feel I should create separate view, MenuDialog.mxml and put there buttons, progress bar and states, but how to display it on the top of the workspace? I hope my problem is clear enough :)
I would make the panel a popUp, with the main application (or the ViewStack's parent container) as the parent of the popUp. You can use the PopUpManager Class to close it based on user actions within the Panel.
Assuming that perhaps you do not want a modal login style panel (which many apps these days eschew) then you should absolutely use states rather than ViewStacks.
States are a much cleaner way to distinguish the various, uh, states that your UI can be in -LOGGED_IN, LOGGED_OUT, etc.
It may take a little to get used to working with states, but once you do, you'll never go back. :-)

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