I am applying style to div using JavaScript it appears well at the first time but when I click an image to open a virtual window the applied CSS goes away.
How can I apply style using script that stays forever.
**There is no way left for me to apply any style at design time because I am using ready made user control and I get ID for the DIV only at run time.
Any Idea??
Here is the script I am using...
window.onload = changeDivOverflow;
function changeDivOverflow()
{
var treeDiv = document.getElementById('T_ctl00contentMainctl04tvw');
treeDiv.style.overflow = "auto";
}
Since you are using ASP.NET, but I cannot see all your full code, I can only assume that your DIV has a runat="server" tag and that's why you cannot get the ID on the client side.
If this is the case, you may consider the following change to get the treeDiv:
var treeDiv = document.getElementById("<%= tvw.ClientID %>");
All styles you apply using javascript and DOM calls, apply only to element you are applying it. In your example it will be only element with ID = 'T_ctl00contentMainctl04tvw'
If you want to reuse that style for more than one element, you should create a CSS class and store that style there. Then apply that class for every element you want. If you want to do it with script, then you should:
var treeDiv = document.getElementById('T_ctl00contentMainctl04tvw');
treeDiv.className = "your-class";
Related
Setting the width of select2 using css is overridden by the javascript call of the select2
// javascript
$(function() {
renderSelect("select");
});
# HAML example (Rails)
= select_tag "countries", options_for_select(#countries), class: 'some-ignored-css-class'
related: How to control the width of select tag?
The problem isn't javascript, the issue is that you're not preserving the CSS.
The only way to set the width is to use CSS. Even your JS sets the CSS (.width):
The difference between .css(width) and .width() is that the latter returns a unit-less pixel value (for example, 400) while the former returns a value with units intact (for example, 400px). They both set the CSS "style" element
A better way is to either set the CSS on a "container" element, or make sure you're persisting the CSS whenever you call the renderSelect function:
Container
#app/assets/stylesheets/application.css
.container select { width: 50px; }
#app/views...
.container= select_tag "countries", options_for_select(#countries)
Using a container will allow you to set the CSS on the container, removing the need for the class on the select itself. Whilst it means adding a container div, it will give you the most autonomy.
--
JS
The alternative will be to change the renderSelect function to take the class of the current select & append it to the new element.
Since I don't know your renderSelect function, I can only provide that level of suggestion.
A solution is to javascript again
// javascript
$(function() {
renderSelect("select");
$("div#s2id_countries").width(300);
});
# HAML example (Rails)
= select_tag "countries", options_for_select(#countries), class: 'some-ignored-css-class'
ahh, Javascript, the cause of, and solution to, all of life's problems
(any improvements?)
Let's say for example I'm going through my stylesheet but I can't remember what element a certain CSS selector affects.
Is there any method, tool, or anything that I could do/use to find out what exactly it is affecting?
Thanks!
I just opened up a random bootstrap template site and did what you where asking for.
Open up your chrome browser (I prefer this as I feel this is easy to debug both Jquery and css) and Press F12, you will get a developer window as in the image.
Switch to the console tab.
Use Jquery selector to select all
the intended elements (you can use the same css selector here too
but just place them inside $('')) Eg: $('.tab-content') I am trying to find out all the elements with the class tab-content
The result is all the elements
of that selector.
NOTE: This appraoch woud require you to have Jquery loaded into your page. Else the script will throw an error saying $ is not defind.
In addition to using your browser's development tools, there are two easy ways to do it that should work in almost any browser (no matter how bad the developer environment).
Visually
Temporarily set a border or background color for the selector, like:
border: 1px solid red;
Or:
background: red;
This makes it very easy to find the affected elements.
Programmatically
On the JavaScript console, use:
// Replace with something that prints the relevant details
var stringify = function(element) { return element.innerHTML; };
// Iterate over all affected elements and print relevant info
var affectedElements = document.querySelectorAll('.your .selector');
var len = affectedElements.length;
console.log('Elements affected: ' + len);
for (var i = 0; i < len; i++) {
var affectedElement = affectedElements[i];
console.log(
'Element ' + (i+1) + ':\n' +
stringify(affectedElement) + '\n\n');
}
The inspection of elements feature of the browser is meant for the purpose you want.
1.Open up the index file in any browser(preferably Mozilla Developer edition),
2.Right click and Inspect element,
3.Then open the compiled stylesheet. Find out the style element you want to check the effect of.
4. Go back to inspection, remove/add CSS properties and see the effect in real time.
The other way is to use Adobe brackets. It's live preview feature will highlight the section that involves the code snippet, you point your cursor to.
I want to add a custom CSS Class to a dijit/layout/ContentPane so I'm able to style it myself.
This is cause I got more than one tab in my TabContainer where my ContentPanes are located and I don't want to double the borders. Using a border all around the Tab will double the border so I removed the left border of the tabs. In the first tab in the TabContainer I need the left border, too.
To get this I tried to assume the first ContentPane a custom CSS class which will do it.
As you see me writing here, I didn't find a way to do this.
I tried it within the data-dojo-props with
<div data-dojo-type="dijit/layout/ContentPane" title="FunnyTitle" data-dojo-props="class:'firstTab'">
So this didn't work. I tried to add it like I do it in a simple HTML element with class="firstTab"
<div data-dojo-type="dijit/layout/ContentPane" title="FunnyTitle" class="firstTab">
Both ways didn't add my class to the ContentPane.
So how is it done?
The class property is actually not used for that kind of purpose, but it used for identifying of which type the widget is.
However, the class attribute should work, because declarative widgets usually keep their parent attributes. If I have the following HTML:
It eventually gets rendered into:
<div class="dijitContentPane test" data-dojo-type="dijit/layout/ContentPane" id="myContent" widgetid="myContent">
Hello
</div>
However, please note that when using a dijit/layout/ContentPane inside a dijit/layout/TabContainer a lot of additional CSS is added, possibily overriding your own CSS.
For example, for overriding the background color of a tab inside a dijit/layout/TabContainer, I had to use the following CSS selector:
.dijitTabContainerTop-dijitContentPane.test2 {
background-color: #D4D4D1;
}
Demo: http://jsfiddle.net/Lcog9saj/
But also, be aware that the borders generated by the TabContainer are not applied to the ContentPane itself, but to an element with classname .dijitTabContainerTop-container (part of the TabContainer itself).
If this really doesn't work, then you can always access the domNode property of the widget you're trying to alter, for example:
require(["dijit/registry", "dojo/ready", "dojo/dom-class"], function(registry, ready, domClass) {
ready(function() {
domClass.add(registry
.byId("myContentPane")
.get("domNode"), "test2");
});
});
It's that simple that I didn't get it.
All you need to do is adding an ID to the ContentPane.
Dojo generates a widgetID with it like "dijit_layout_TabContainer_0_tablist_myID"
If the TabContainer itself has an ID, it could be different. Just have a look at the generated code.
Now you're able to get it with dijit.byId.
At the end it looks something like:
var tab = dijit.byId("dijit_layout_TabContainer_0_tablist_myID");
domClass.add(tab.domNode,"myClassName");
domClass is a part of dojo. For using it you just need to require it "dojo/dom-class"
The title pretty much says what I'm looking to do, but to elaborate a little more, I want to apply some CSS to a class called prochart-colitem for users who do not have javascript enabled.
The reason? I am using percentages for column widths to equal 100%, then using javascript to subtract 2 pixels from each div for a border that is also added.
If there's no javascript enabled, the columns + borders equal more than 100% of the parent div, and I need to subtract a couple pixels from a class to make it fit in the parent div to no-js users.
Any easy way to do this? I tried <noscript> with <style> inside of that, no luck.
One way to approach it is by always adding a CSS class to the elements you wish to have a specific style and then, once loaded, run some JavaScript to remove those classes from the elements with that class.
As an example (I use jQuery here for simplicity's sake but this can obviously be done without a JS library):
$(document).ready(function()
{
$(".nonJsClass").each(function()
{
$(this).removeClass("nonJsClass");
}
}
Where the 'nonJsClass' has CSS rules that will now only apply if the user doesn't have JS enabled.
You could add a class to the body tag, that triggers your desired CSS when JS is not enabled, then right after the body tag, remove it with JS.
Thus users with JS support won't see the effects of the special class.
Including a stylesheet inside a noscript tag was not possible before HTML5, but it is now (as long as you do it in the "head" of the document).
http://adapt.960.gs/
In the case of JavaScript being purposefully disabled or unavailable, stylesheet defaults can be served via , which is perfectly valid in the for HTML5.
scunliffe's answer is good. An alternate way would be to write a CSS style that only displays if JavaScript is enabled and only targets the div you want, using class chaining:
.prochart-colitem.js-enabled {
/* your JS-specific styles */
}
You can then use jQuery, for example, to add that additional class:
$(document).ready(function() {
$('.prochart-colitem').addClass('js-enabled');
});
Is it possible to create a new property in CSS? For example, say you're developing a control that displays a photo and you want to add a property to css to control what style frame to have around the photo. Something like:
#myphoto { frame-style: fancy }
Is there some way to do this in a cross browser compatible manner, and how would you define whether the style inherits or not?
EDIT: It's a custom control - your JS code would deal with the style - I'm not expecting the browser to magically know what to do. I want the user to be able to style the control with CSS instead of JS.
Sure, why not. Check this out as an example: http://bililite.com/blog/2009/01/16/jquery-css-parser/
You may also be able to get away with using CSS classes instead of properties. Not sure if that works for what you're doing.
You can't. Browsers interpret CSS based on how their layout engines are coded to do so.
Unless you took an existing open source engine like WebKit or Gecko, added custom code to handle your custom CSS and made a browser that used your customized layout engine. But then only your implementation would understand your custom CSS.
Re your edit: it'd depend on whether you're able to read that style somehow. Typically browsers just instantly discard any properties they don't recognize, and CSS is not normally reachable by JavaScript because CSS code is not part of the DOM.
Or you could look at Jordan's answer.
If you'd prefer a straight JavaScript solution that uses no JS libraries, you could use the query string of a background-image to keep "custom properties" inside your CSS.
HTML
<div id="foo">hello</div>
CSS
#foo {
background: url('images/spacer.gif?bar=411');
}
JavaScript
getCustomCSSProperty('foo', 'bar');
Supporting JavaScript Functions
function getCustomCSSProperty(elId, propName)
{
var obj = document.getElementById(elId);
var bi = obj.currentStyle ? obj.currentStyle.backgroundImage : document.defaultView.getComputedStyle(obj, null).getPropertyValue('background-image');
var biurl = RegExp('url\\(["\\\']?([^"\\\']+)["\\\']?\\)').exec(bi);
return getParameterByName(propName, biurl[1]);
}
function getParameterByName(name, qs) {
var match = RegExp('[?&]' + name + '=([^&]*)').exec(qs);
return match && decodeURIComponent(match[1].replace(/\+/g, ' '));
}
Demo:
http://jsfiddle.net/t2DYk/1/
Explanation:
http://refactorer.blogspot.com/2011/08/faking-custom-css-properties.html
I've tested the solution in IE 5.5-9, Chrome, Firefox, Opera, and Safari.