I have a bunch of files in a unix directory that look like the following:
filename_1234567.txt
I need to rename them by copying the last three characters of each filename
to the front of the filename like this:
567_filename_1234567.txt
Note: Both the filename and extension are variable.
I'm running this on a Solaris box.
Thanks in advance!
One possibility:
\ls *.txt | sed 's/\(.*\)\(...\).txt/mv \1\2.txt \2_\1.txt/' | sh
(probably wise to write that with echo mv, while you're double-checking it does what you think it does).
I can't decide if the alternative
sed 's/\(\(.*\)\(...\).txt\)/mv \1 \3_\2.txt/'
is more robust, or just way too fussy.
#for file in *_*.*
for file in `ls *_*.txt`
do
last_3="$(echo $file | grep -o "...\...."|cut -d'.' -f1)"
cp $file ${last_3}_${file}
done
How to I list only directories that contain certain files. I am running on a Solaris box. Example, I want to list sub-directories of directory ABC that contain files that end with .out, .dat and .log .
Thanks
Something along these lines might work out for you:
find ABC/ \( -name "*.out" -o -name "*.log" \) -print | while read f
do
echo "${f%/*}"
done | sort -u
The sort -u bit could be just uniq instead, but either should work.
Should work on bash or ksh. Probably not so much on /bin/sh - you'd have to replace the variable expansion with something like echo "${f}" | sed -e 's;/[^/]*$;;' or something else that would strip off the last component of the path. dirname "${f}" would be good for that, but I don't recall if Solaris includes that utility...
how can I remove the word "myfile" in a list of filenames with this structure?
mywork_myfile_XSOP.txt
mywork_myfile_ATTY.txt
mywork_myfile_ATPY.txt
Desired_output:
mywork_XSOP.txt
mywork_ATTY.txt
mywork_ATPY.txt
The simplest method is to use the common rename command which is available in most Unices.
rename 's/^mywork_myfile_/mywork_/' *
This of course expects you to be on the directory of the files. This will not overwrite files. If you want that, just pass the -f option. Also, take note that there's multiple versions of rename out there which may have different options.
Based on this answer on "Rename all files in "Rename all files in directory from $filename_h to $filename_half?", this can be a way:
for file in mywork_myfile*txt
do
mv "$file" "${file/_myfile/}"
done
Note that it uses the bash string operations as follows:
$ file="mywork_myfile_XSOP.txt"
$ echo ${file/_myfile/}
mywork_XSOP.txt
This would work in any Posix shell...
#!/bin/sh
for i
in mywork_myfile_XSOP.txt \
mywork_myfile_ATTY.txt \
mywork_myfile_ATPY.txt; do
set -x
mv "$i" "$(echo $i | sed -e s/myfile_//)"
set +x
done
This command will search all directories and subdirectories for files containing "text"
grep -r "text" *
How do i specify to search only in files that are named 'strings.xml'?
You'll want to use find for this, since grep won't work that way recursively (as far as I know). Something like this should work:
find . -name "strings.xml" -exec grep "text" "{}" \;
The find command searches starting in the current directory (.) for a file with the name strings.xml (-name "strings.xml"), and then for each found file, execute the grep command specified. The curly braces ("{}") are a placeholder that find uses to specify the name of the file it found. More detail can be found in man find.
Also note that the -r option to grep is no longer necessary, since find works recursively.
You can use the grep command:
grep -r "text" /path/to/dir/strings.xml
grep supports an --include option whose use is to recurse in directories only searching file matching PATTERN. So, try something like below:
grep -R --include 'strings.xml' text .
I also tried using find which seems to be quite faster than grep:
find ./ -name "strings.xml" -exec grep "text" '{}' \; -print
These links speak about the same issue, might help you:
'grep -R string *.txt' even when top dir doesn't have a .txt file
http://www.linuxquestions.org/questions/linux-newbie-8/run-grep-only-on-certain-files-using-wildcard-919822/
Try below command
find . -type f | xargs grep "strings\.xml"
This will run grep "strings\.xml" on every file returned by find
I need to rename files names like this
transform.php?dappName=Test&transformer=YAML&v_id=XXXXX
to just this
XXXXX.txt
How can I do it?
I understand that i need more than one mv command because they are at least 25000 files.
Easiest solution is to use "mmv"
You can write:
mmv "long_name*.txt" "short_#1.txt"
Where the "#1" is replaced by whatever is matched by the first wildcard.
Similarly #2 is replaced by the second, etc.
So you do something like
mmv "index*_type*.txt" "t#2_i#1.txt"
To rename index1_type9.txt to t9_i1.txt
mmv is not standard in many Linux distributions but is easily found on the net.
If you are using zsh you can also do this:
autoload zmv
zmv 'transform.php?dappName=Test&transformer=YAML&v_id=(*)' '$1.txt'
You write a fairly simple shell script in which the trickiest part is munging the name.
The outline of the script is easy (bash syntax here):
for i in 'transform.php?dappName=Test&transformer=YAML&v_id='*
do
mv $i <modified name>
done
Modifying the name has many options. I think the easiest is probably an awk one-liner like
`echo $i | awk -F'=' '{print $4}'`
so...
for i in 'transform.php?dappName=Test&transformer=YAML&v_id='*
do
mv $i `echo $i | awk -F'=' '{print $4}'`.txt
done
update
Okay, as pointed out below, this won't necessarily work for a large enough list of files; the * will overrun the command line length limit. So, then you use:
$ find . -name 'transform.php?dappName=Test&transformer=YAML&v_id=*' -prune -print |
while read
do
mv $reply `echo $reply | awk -F'=' '{print $4}'`.txt
done
Try the rename command
Or you could pipe the results of an ls into a perl regex.
You may use whatever you want to transform the name (perl, sed, awk, etc.). I'll use a python one-liner:
for file in 'transform.php?dappName=Test&transformer=YAML&v_id='*; do
mv $file `echo $file | python -c "print raw_input().split('=')[-1]"`.txt;
done
Here's the same script entirely in Python:
import glob, os
PATTERN="transform.php?dappName=Test&transformer=YAML&v_id=*"
for filename in glob.iglob(PATTERN):
newname = filename.split('=')[-1] + ".txt"
print filename, '==>', newname
os.rename(filename, newname)
Side note: you would have had an easier life saving the pages with the right name while grabbing them...
find -name '*v_id=*' | perl -lne'rename($_, qq($1.txt)) if /v_id=(\S+)/'
vimv lets you rename multiple files using Vim's text editing capabilities.
Entering vimv opens a Vim window which lists down all files and you can do pattern matching, visual select, etc to edit the names. After you exit Vim, the files will be renamed.
[Disclaimer: I'm the author of the tool]
I'd use ren-regexp, which is a Perl script that lets you mass-rename files very easily.
21:25:11 $ ls
transform.php?dappName=Test&transformer=YAML&v_id=12345
21:25:12 $ ren-regexp 's/transform.php.*v_id=(\d+)/$1.txt/' transform.php*
transform.php?dappName=Test&transformer=YAML&v_id=12345
1 12345.txt
21:26:33 $ ls
12345.txt
This should also work:
prfx='transform.php?dappName=Test&transformer=YAML&v_id='
ls $prfx* | sed s/$prfx// | xargs -Ipsx mv "$prfx"psx psx
this renamer command would do it:
$ renamer --regex --find 'transform.php?dappName=Test&transformer=YAML&v_id=(\w+)' --replace '$1.txt' *
Ok, you need to be able to run a windows binary for this.
But if you can run Total Commander, do this:
Select all files with *, and hit ctrl-M
In the Search field, paste "transform.php?dappName=Test&transformer=YAML&v_id="
(Leave Replace empty)
Press Start
It doesn't get much simpler than that.
You can also rename using regular expressions via this dialog, and you see a realtime preview of how your files are going to be renamed.