Add argument in function with default value if omitted in R - r

I have a dataframe (data) in R and I have created a function that does the following:
If data contains zero values, then replace data with data +2 and then return datanew <- data + data^2. If data does not contains zeros then do datanew <- data + data^2.
I manage to do that as follows:
set.seed(123)
data <- as.data.frame(matrix(rbinom(10 * 5, 1, 0.5), ncol = 5, nrow = 10))
Myfunction <- function(data) {
if (any(data == 0, na.rm = TRUE)) {
data <- data + 2
} # 2 is the a value that i want to add in all elements
datanew <- data + data ^ 2
print(datanew)
}
Myfunction(data = data)
However, I want to define in the function the element a (function(data, a)) and if omitted then the default value will be 2, otherwise the value that has be given by the user. How can i do that R??

Related

Unnest/Unlist moving window results in R

I have a dataframe that has two columns, x and y (both populated with numbers). I am trying to look at a moving window within the data, and I've done it like this (source):
# Extract just x and y from the original data frame
df <- dat_fin %>% select(x, y)
# Moving window creation
nr <- nrow(df)
windowSize <- 10
windfs <- lapply(seq_len(nr - windowSize + 1), function(i) df[i:(i + windowSize - 1), ])
This lapply creates a list of tibbles that are each 10 (x, y) pairs. At this point, I am trying to compute a single quantity using each of the sets of 10 pairs; my current (not working) code looks like this:
library(shotGroups)
for (f in 1:length(windfs)) {
tsceps[f] = getCEP(windfs[f], accuracy = TRUE)
}
When I run this, I get the error:
Error in getCEP.default(windfs, accuracy = TRUE) : xy must be numeric
My goal is that the variable that I've called tsceps should be a 1 x length(windfs) data frame, each value in which comes from the getCEP calculation for each of the windowed subsets.
I've tried various things with unnest and unlist, all of which were unsuccessful.
What am I missing?
Working code:
df <- dat_fin %>% select(x, y)
nr <- nrow(df)
windowSize <- 10
windfs <- lapply(seq_len(nr - windowSize + 1), function(i) df[i:(i + windowSize - 1), ])
tsceps <- vector(mode = "numeric", length = length(windfs))
library(shotGroups)
for (j in 1:length(windfs)) {
tsceps[j] <- getCEP(windfs[[j]], type = "CorrNormal", CEPlevel = 0.50, accuracy = TRUE)
}
ults <- unlist(tsceps)
ults_cep <- vector(mode = "numeric", length = length(ults))
for (k in 1:length(ults)) {
ults_cep[k] <- ults[[k]]
}
To get this working with multiple type arguments to getCEP, just use additional code blocks for each type required.

R: How to access a 'complicated list'

I am working on an assignment, which tasks me to generate a list of data, using the below code.
##Use the make_data function to generate 25 different datasets, with mu_1 being a vector
x <- seq(0, 3, len=25)
make_data <- function(a){
n = 1000
p = 0.5
mu_0 = 0
mu_1=a
sigma_0 = 1
sigma_1 = 1
y <- rbinom(n, 1, p)
f_0 <- rnorm(n, mu_0, sigma_0)
f_1 <- rnorm(n, mu_1, sigma_1)
x <- ifelse(y == 1, f_1, f_0)
test_index <- createDataPartition(y, times = 1, p = 0.5, list = FALSE)
list(train = data.frame(x = x, y = as.factor(y)) %>% slice(-test_index),
test = data.frame(x = x, y = as.factor(y)) %>% slice(test_index))
}
dat <- sapply(x,make_data)
The code looks good to go, and 'dat' appears to be a 25 column, 2 row table, each with its own data frame.
Now, each data frame within a cell has 2 columns.
And this is where I get stuck.
While I can get to the data frame in row 1, column 1, just fine (i.e. just use dat[1,1]), I can't reach the column of 'x' values within dat[1,1]. I've experimented with
dat[1,1]$x
dat[1,1][1]
But they only throw weird responses: error/null.
Any idea how I can pull the column? Thanks.
dat[1, 1] is a list.
class(dat[1, 1])
#[1] "list"
So to reach to x you can do
dat[1, 1]$train$x
Or
dat[1, 1][[1]]$x
As a sidenote, instead of having this 25 X 2 matrix as output in dat I would actually prefer to have a nested list.
dat <- lapply(x,make_data)
#Access `x` column of first list from `train` dataset.
dat[[1]]$train$x
However, this is quite subjective and you can chose whatever format you like the best.

How to run function on indivisual columns instead of data frame?

Hello everyone I have two data frame trying to do bootstrapping with below script1 in my script1 i am taking number of rows from data frame one and two. Instead of taking rows number from entire data frame I wanted split individual columns as a data frame and remove the zero values and than take the row number than do the bootstrapping using below script. So trying with script2 where I am creating individual data frame from for loop as I am new to R bit confused how efficiently do add the script1 function to it
please suggest me below I am providing script which is running script1 and the script2 I am trying to subset each columns creating a individual data frame
Script1
set.seed(2)
m1 <- matrix(sample(c(0, 1:10), 100, replace = TRUE), 10)
m2 <- matrix(sample(c(0, 1:5), 50, replace = TRUE), 5)
m1 <- as.data.frame(m1)
m2 <- as.data.frame(m2)
nboot <- 1e3
n_m1 <- nrow(m1); n_m2 <- nrow(m2)
temp<- c()
for (j in seq_len(nboot)) {
boot <- sample(x = seq_len(n_m1), size = n_m2, replace = TRUE)
value <- colSums(m2)/colSums(m1[boot,])
temp <- rbind(temp, value)
}
boot_data<- apply(temp, 2, median)
script2
for (i in colnames(m1)){
m1_subset=(m1[m1[[i]] > 0, ])
m1_subset=m1_subset[i]
m2_subset=m2[m2[[i]] >0, ]
m2_subset=m2_subset[i]
num_m1 <- nrow(m1_subset); n_m2 <- nrow(m2_subset)# after this wanted add above script changing input
}
If I understand correctly, you want to do the sampling and calculation on each column individually, after removing the 0 values. I. modified your code to work on a single vector instead of a dataframe (i.e., using length() instead of nrow() and sum() instead of colSums(). I also suggest creating the empty matrix for your results ahead of time, and filling in -- it will be fasted.
temp <- matrix(nrow = nboot, ncol = ncol(m1))
for (i in seq_along(m1)){
m1_subset = m1[m1[,i] > 0, i]
m2_subset = m2[m2[,i] > 0, i]
n_m1 <- length(m1_subset); n_m2 <- length(m2_subset)
for (j in seq_len(nboot)) {
boot <- sample(x = seq_len(n_m1), size = n_m2, replace = TRUE)
temp[j, i] <- sum(m2_subset)/sum(m1_subset[boot])
}
}
boot_data <- apply(temp, 2, median)
boot_data <- setNames(data.frame(t(boot_data)), names(m1))
boot_data

For Loop in R to Transform Each Column Using Box Cox from the Cars Package

I am working on an assignment for school. I need to transform the columns in a data frame using a for loop and the bcPower function from the cars package. My data frame named bb2.df consists of 13 columns of baseball statistics for 337 players. The data is from:
http://ww2.amstat.org/publications/jse/datasets/baseball.dat.txt
I read the data in using:
bb.df <- read.fwf("baseball.dat.txt",widths=c(4,6,6,4,4,3,3,3,4,4,4,3,3,2,2,2,2,19))
And then I created a second data frame just for the numeric stats using:
bb2.df <- bb.df[,1:13]
library(cars)
Then I unsuccessfully tried to build the for loop.
> bb2.df[[i]] <- bcPower(bb2.df[[i]],c)
> for (i in 1:ncol(bb2.df)) {
+ c <- coef(powerTransform(bb2.df[[i]]))
+ bb2.df[[i]] <- bcPower(bb2.df[[i]],c)
+ }
Error in bc1(out[, j], lambda[j]) :
First argument must be strictly positive.
The loop seems to transform the first three columns but stops.
What am I doing wrong?
This solution
tests whether a column appears to contain logical values and omits them from the transformation
replaces zero values in the vectors with a small number, outside the range of the actual values
stores the transformed values in a new data frame, retaining the column and row names
I have also tested all of the variables for normality before and after the transformation. I tried to find a variable that's interesting in that the transformed variable has a large p-value for the Shapiro test, but also there there was a large change in the p-value. Finally, the interesting variable is scaled in both the original and transformed version, and the two versions are overlaid on a density plot.
library(car); library(ggplot2); library(reshape2)
# see this link for column names and type hints
# http://ww2.amstat.org/publications/jse/datasets/baseball.txt
# add placeholder column for opening quotation mark
bb.df <-
read.fwf(
"http://ww2.amstat.org/publications/jse/datasets/baseball.dat.txt",
widths = c(4, 6, 6, 4, 4, 3, 3, 3, 4, 4, 4, 3, 3, 2, 2, 2, 2, 2, 17)
)
# remove placeholder column
bb.df <- bb.df[,-(ncol(bb.df) - 1)]
names(bb.df) <- make.names(
c(
'Salary', 'Batting average', 'OBP', 'runs', 'hits', 'doubles', 'triples',
'home runs', 'RBI', 'walks', 'strike-outs', 'stolen bases', 'errors',
"free agency eligibility", "free agent in 1991/2" ,
"arbitration eligibility", "arbitration in 1991/2", 'name'
)
)
# test for boolean/logical values... don't try to transform them
logicals.test <- apply(
bb.df,
MARGIN = 2,
FUN = function(one.col) {
asnumeric <- as.numeric(one.col)
aslogical <- as.logical(asnumeric)
renumeric <- as.numeric(aslogical)
matchflags <- renumeric == asnumeric
cant.be.logical <- any(!matchflags)
print(cant.be.logical)
}
)
logicals.test[is.na(logicals.test)] <- FALSE
probably.numeric <- bb.df[, logicals.test]
result <- apply(probably.numeric, MARGIN = 2, function(one.col)
{
# can't transform vectors containing non-positive values
# replace zeros with something small
non.zero <- one.col[one.col > 0]
small <- min(non.zero) / max(non.zero)
zeroless <- one.col
zeroless[zeroless == 0] <- small
c <- coef(powerTransform(zeroless))
transformation <- bcPower(zeroless, c)
return(transformation)
})
result <- as.data.frame(result)
row.names(result) <- bb.df$name
cols2test <- names(result)
normal.before <- sapply(cols2test, function(one.col) {
print(one.col)
temp <- shapiro.test(bb.df[, one.col])
return(temp$p.value)
})
normal.after <- sapply(cols2test, function(one.col) {
print(one.col)
temp <- shapiro.test(result[, one.col])
return(temp$p.value)
})
more.normal <- cbind.data.frame(normal.before, normal.after)
more.normal$more.normal <-
more.normal$normal.after / more.normal$normal.before
more.normal$interest <-
more.normal$normal.after * more.normal$more.normal
interesting <-
rownames(more.normal)[which.max(more.normal$interest)]
data2plot <-
cbind.data.frame(bb.df[, interesting], result[, interesting])
names(data2plot) <- c("original", "transformed")
data2plot <- scale(data2plot)
data2plot <- melt(data2plot)
names(data2plot) <- c("Var1", "dataset", interesting)
ggplot(data2plot, aes(x = data2plot[, 3], fill = dataset)) +
geom_density(alpha = 0.25) + xlab(interesting)
Original, incomplete answer:
I believe you're trying to do illegal power transformations (vectors including non-positive values, specifically zeros; vectors with no variance)
The fact that you are copying bb.df into bb2.df and then overwriting is a sure sign that you should really be using apply.
This doesn't create a useful dataframe, but it should get you started,
library(car)
bb.df <-
read.fwf(
"baseball.dat.txt",
widths = c(4, 6, 6, 4, 4, 3, 3, 3, 4, 4, 4, 3, 3, 2, 2, 2, 2, 19)
)
bb.df[bb.df == 0] <- NA
# skip last (text) col
for (i in 1:(ncol(bb.df) - 1)) {
print(i)
# use comma to indicate indexing by column
temp <- bb.df[, i]
temp[temp == 0] <- NA
temp <- temp[complete.cases(temp)]
if (length(unique(temp)) > 1) {
c <- coef(powerTransform(bb.df[, i]))
print(bcPower(bb.df[i], c))
} else {
print(paste0("column ", i, " is invariant"))
}
}
# apply solution
result <- apply(bb.df[,-ncol(bb.df)], MARGIN = 2, function(one.col)
{
temp <- one.col
temp[temp == 0] <- NA
temp <- temp[complete.cases(temp)]
if (length(unique(temp)) > 1) {
c <- coef(powerTransform(temp))
transformation <- bcPower(temp, c)
return(transformation)
} else
{
print("skipping invariant column")
return(NULL)
}
})

MHSMM package R input data format with multiple variables

my problem is similar to the question as followingthe problem of R-input Format
I have tried the above code in the above link and revised some part to suit my data. my data is like follow
I want my data can be created as a data frame with 4 variable vectors. The code what I have revised is
formatMhsmm <- function(data){
nb.sequences = nrow(data)
nb.variables = ncol(data)
data_df <- data.frame(matrix(unlist(data), ncol = 4, byrow = TRUE))
# iterate over these in loops
rows <- 1: nb.sequences
# build vector with id value
id = numeric(length = nb.sequences)
for( i in rows)
{
id[i] = data_df[i,2]
}
# build vector with time value
time = numeric (length = nb.sequences)
for( i in rows)
{
time[i] = data_df[i,3]
}
# build vector with observation values
sequences = numeric(length = nb.sequences)
for(i in rows)
{
sequences[i] = data_df[i, 4]
}
data.df = data.frame(id,time,sequences)
# creation of hsmm data object need for training
N <- as.numeric(table(data.df$id))
train <- list(x = data.df$sequences, N = N)
class(train) <- "hsmm.data"
return(train)
}
library(mhsmm)
dataset <- read.csv("location.csv", header = TRUE)
train <- formatMhsmm(dataset)
print(train)
The output observation is not the data of 4th col, it's a list of (4, 8, 12,...,396, 1, 1, ..., 56, 192,...,6550, 68, NA, NA,...) It has picked up 1/4 data of each col. Why it is like this?
Thank you very much!!!!
Why don't you simply count yout observations by Id, and create the hsmm.data object directly? Supposing yout dataframe is called "data", we have:
N <- as.numeric(table(data$id))
train <- list(x=data$location, N = N)
class(train) <- "hsmm.data"
Extracted from http://www.jstatsoft.org/v39/i04/paper

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