rule is a worksheet's name,the command works fine:
oCell.Formula = "=LOOKUP(A2;$'rule'.$A$2:$A$9;$'rule'.$B$2:$B$9)"
I want to make the first A2 in LOOKUP with a variable:
for id=2 to NumRows
oCell = Sheet.getCellrangeByName("B"&id)
arg = "A"&id
oCell.Formula = "=LOOKUP(arg;$'rule'.$A$2:$A$9;$'rule'.$B$2:$B$9)"
next id
The arg will not assign its value into LOOKUP ,how to fix it?
oCell.Formula = "=LOOKUP(arg;$'rule'.$A$2:$A$9;$'rule'.$B$2:$B$9)"
Use quoting syntax similar to the line where you defined arg.
id = 2
MsgBox("=LOOKUP(A" & id & ";$'rule'.$A$2:$A$9;$'rule'.$B$2:$B$9)")
Result:
=LOOKUP(A2;$'rule'.$A$2:$A$9;$'rule'.$B$2:$B$9)
Related
I am working in R, this is a look of my table :
IAE_2017 IAE_2018
L1PYSH L2PYSH
M1CHIMIE M2CHIMIE
..... ........
Now I want to make a condition which take the 2 first caracters of IAE_2017 and verify if it is different for the 2 fisrt's of IAE_2018.
You could use substr(), assuming df a dataframe :
substr(df[,1], start = 1, stop = 2)==substr(df[,2], start = 1, stop = 2)
Sample code snippet tried:
for row in range(1,sheet.max_row+1):
for col in range(1, sheet.max_column+1):
temp = None
cell_obj = sheet.cell(row=row,column=col)
temp = re.search(r"requestor", str(cell_obj.value))
if temp:
if 'requestor' in cell_obj.value:
cell_obj.value.replace('requestor',
'ABC')
Trying to replace from an xlsx cell containing value "Customer name: requestor " with value "Customer name: ABC" .How can this be achieved easily ?
I found my answer in this post:https://www.edureka.co/community/42935/python-string-replace-not-working
The replace function doesn't store the result in the same variable. Hence the solution for above:
mvar = None
for row in range(1,sheet.max_row+1):
for col in range(1, sheet.max_column+1):
temp = None
cell_obj = sheet.cell(row=row,column=col)
temp = re.search(r"requestor", str(cell_obj.value))
if temp:
if 'requestor' in cell_obj.value:
mvar = cell_obj.value.replace('requestor',
'ABC')
cell_obj.value = mvar
Just keep it simple. Instead of re and replace, search for the given value and override the cell.
The example below also gives you the ability to change 'customer name' if needed:
wb = openpyxl.load_workbook("example.xlsx")
sheet = wb["Sheet1"]
customer_name = "requestor"
replace_with = "ABC"
search_string = f"Customer name: {customer_name}"
replace_string = f"Customer name: {replace_with}"
for row in range(1, sheet.max_row + 1):
for col in range(1, sheet.max_column + 1):
cell_obj = sheet.cell(row=row, column=col)
if cell_obj.value == search_string:
cell_obj.value = replace_string
wb.save("example_copy.xlsx") # remember that you need to save the results to the file
I have the following strings:
F:\Sheyenne\ROI\SWIR32_subset\SWIR32_2005210_East_A.dat
F:\Sheyenne\ROI\SWIR32_subset\SWIR32_2005210_Froemke-Hoy.dat
and from each I want to extract the three variables, 1. SWIR32 2. the date and 3. the text following the date. I want to automate this process for about 200 files, so individually selecting the locations won't exactly work for me.
so I want:
variable1=SWIR32
variable2=2005210
variable3=East_A
variable4=SWIR32
variable5=2005210
variable6=Froemke-Hoy
I am going to be using these to add titles to graphs later on, but since the position of the text in each string varies I am unsure how to do this using strmid
I think you want to use a combination of STRPOS and STRSPLIT. Something like the following:
s = ['F:\Sheyenne\ROI\SWIR32_subset\SWIR32_2005210_East_A.dat', $
'F:\Sheyenne\ROI\SWIR32_subset\SWIR32_2005210_Froemke-Hoy.dat']
name = STRARR(s.length)
date = name
txt = name
foreach sub, s, i do begin
sub = STRMID(sub, 1+STRPOS(sub, '\', /REVERSE_SEARCH))
parts = STRSPLIT(sub, '_', /EXTRACT)
name[i] = parts[0]
date[i] = parts[1]
txt[i] = STRJOIN(parts[2:*], '_')
endforeach
You could also do this with a regular expression (using just STRSPLIT) but regular expressions tend to be complicated and error prone.
Hope this helps!
I'm trying to read a file and put contents in a list. I have done this mnay times before and it has worked but this time it throws back the error "list index out of range".
the code is:
with open("File.txt") as f:
scores = []
for line in f:
fields = line.split()
scores.append( (fields[0], fields[1]))
print(scores)
The text file is in the format;
Alpha:[0, 1]
Bravo:[0, 0]
Charlie:[60, 8, 901]
Foxtrot:[0]
I cant see why it is giving me this problem. Is it because I have more than one value for each item? Or is it the fact that I have a colon in my text file?
How can I get around this problem?
Thanks
If I understand you well this code will print you desired result:
import re
with open("File.txt") as f:
# Let's make dictionary for scores {name:scores}.
scores = {}
# Define regular expressin to parse team name and team scores from line.
patternScore = '\[([^\]]+)\]'
patternName = '(.*):'
for line in f:
# Find value for team name and its scores.
fields = re.search(patternScore, line).groups()[0].split(', ')
name = re.search(patternName, line).groups()[0]
# Update dictionary with new value.
scores[name] = fields
# Print output first goes first element of keyValue in dict then goes keyName
for key in scores:
print (scores[key][0] + ':' + key)
You will recieve following output:
60:Charlie
0:Alpha
0:Bravo
0:Foxtrot
I am trying to use Pyparsing to identify a keyword which is not beginning with $ So for the following input:
$abc = 5 # is not a valid one
abc123 = 10 # is valid one
abc$ = 23 # is a valid one
I tried the following
var = Word(printables, excludeChars='$')
var.parseString('$abc')
But this doesn't allow any $ in var. How can I specify all printable characters other than $ in the first character position? Any help will be appreciated.
Thanks
Abhijit
You can use the method I used to define "all characters except X" before I added the excludeChars parameter to the Word class:
NOT_DOLLAR_SIGN = ''.join(c for c in printables if c != '$')
keyword_not_starting_with_dollar = Word(NOT_DOLLAR_SIGN, printables)
This should be a bit more efficient than building up with a Combine and a NotAny. But this will match almost anything, integers, words, valid identifiers, invalid identifiers, so I'm skeptical of the value of this kind of expression in your parser.