I need to get the next row from an ORDERBY query
I have 2 columns, ID(Primary key), Age(float) in a table T and I need something like the following
SELECT ID FROM T WHERE !> (inputted ID) + 1 rowID/Next row <! ORDERBY Age (then primary key, but I suspect if the Age values are the same SQLite would default to order by primary key anyway) LIMIT 1
Essentially it would select the next row after the inputted ID in the ordered table, its the next row / rowID + 1 I am not sure how to get.
As suggested here is a data set as an example
https://dbfiddle.uk?rdbms=sqlite_3.27&fiddle=19685ac20cc42041a59d318a01a2010f
ID Age
1 12.2
2 36.8
3 22.5
4 41
5 16.7
I am attempting to get the the following row from the ordered (by age) list given a specific ID
ID Age
1 12.2
5 16.7
3 22.5
2 36.8
4 41
Something similar to
SELECT ID FROM OrderedInfo WHERE ID = 5 ORDER BY Age ASC LIMIT 1 OFFSET 1;
My expected result would be '3' from the example data above
I have expanded the data set to include duplicate entries as I didn't implicitly state it could have such data - as such forpas answer works for the first example with no duplicate entries - thanks for your help
https://dbfiddle.uk?rdbms=sqlite_3.27&fiddle=f13d7f5a44ba414784547d9bbdf4997e
Use a subquery for the ID that you want in the WHERE clause:
SELECT *
FROM OrderedInfo
WHERE Age > (SELECT Age FROM OrderedInfo WHERE ID = 5)
ORDER BY Age LIMIT 1;
See the demo.
If there are duplicate values in the column Age use a CTE that returns the row that you want and join it to the table so that you expand the conditions:
WITH cte AS (SELECT ID, Age FROM OrderedInfo WHERE ID = 5)
SELECT o.*
FROM OrderedInfo o INNER JOIN cte c
ON o.Age > c.Age OR (o.Age = c.Age AND o.ID > c.ID)
ORDER BY o.Age, o.ID LIMIT 1;
See the demo.
Related
I have an SQLite3 database from which I want to remove rows that have two fields of the same value.
It seems that I am able to select such values with this query:
SELECT * FROM mydb GROUP BY user_id, num HAVING COUNT(*) > 1
However I am not able to delete them.
DELETE FROM mydb WHERE user_id IN (SELECT * FROM mydb GROUP BY user_id, num HAVING COUNT(*) > 1)
returns a syntax error.
This is what I expect:
Example:
id user_id num
1 1 1
2 1 1
3 2 1
4 1 2
5 2 2
In this example id 1 and 2 have both columns (user_id and num) of the same value so they should be removed. Preferably, but not necessarily I would like to have a solution that would leave only one such row (doesn't matter which one).
Result:
id user_id num
2 1 1
3 2 1
4 1 2
5 2 2
Note: id is a primary key. user_id is a foreign key. num is an INTEGER.
You were having a syntax error because your IN operator has a single value on the left (user_id) but a table of non-single-value rows in the right side (SELECT *). Compare like with like; WHERE user_id IN (SELECT user_id ...) to avoid it.
Anyway, here's a query to delete all-but-newest:
DELETE FROM mydb
WHERE id NOT IN (
SELECT MAX(id) FROM mydb
GROUP BY user_id, num
);
The subquery will return the highest id for every unique (user_id, num) combination. Then we just delete all the other rows. I.e. in your example, the subquery would return 2, 3, 4, 5 as "correct", which would result in deletion of row 1.
I tried this request:
UPDATE studentTble e SET e.oStudent.oPerson.oAddr.city='UK' WHERE rownum = 2
ID NAME STREET CITY
100 --------Henrry.Student-----ST 17.---NY
101 --------Samm.Student-------ST 17D.--OR
102 --------Hanna.Student------ST 25D.--MX
WHERE rownum = 2
That is not how ROWNUM works. Rownum is not incremented to 2 unless Oracle assigns rownum to the first row. So, WHERE ROWNUM = 2 would return no rows, since rownum is never incremented beyond 1 in this case.
how update the second row in oracle11g?
There is nothing called a Nth row unless you have an ordered set of rows. In your case, if you have an explicit ORDER BY on ID column, by default in ascending order, then you could choose the second row from the sub-query.
UPDATE studenttble e
SET e.ostudent.operson.oaddr.city = 'UK'
WHERE id = (SELECT id
FROM (SELECT id,
ROWNUM rn
FROM (SELECT id,
ROWNUM rn
FROM studenttble
ORDER BY id))
WHERE rn = 2)
You could also use ANALYTIC ROW_NUMBER() to assign rank to each row ordered by ID column.
I have two tables, one with objects, one with properties of the objects. Both tables have a personal ID and a date as "key", but since multiple orders of objects can be done by one person on a single day, it doesn't match well. I do know however, that the entries are entered in the same order in both tables, so it is possible to join on the order, if the personID and date are the same.
This is what I want to accomplish:
Table 1:
PersonID Date Object
1 20-08-2013 A
2 13-11-2013 B
2 13-11-2013 C
2 13-11-2013 D
3 21-11-2013 E
Table 2:
PersonID Date Property
4 05-05-2013 $
1 20-08-2013 ^
2 13-11-2013 /
2 13-11-2013 *
2 13-11-2013 +
3 21-11-2013 &
Result:
PersonID Date Object Property
4 05-05-2013 $
1 20-08-2013 A ^
2 13-11-2013 B /
2 13-11-2013 C *
2 13-11-2013 D +
3 21-11-2013 E &
So what I want to do, is join the two tables and "zip" the group of entries that have the same (PersonID,Date) "key".
Something called "Slick" seems to have this (see here), but I'd like to do it in SQLite.
Any advice would be amazing!
You are on the right track. Why not just do a LEFT JOIN between the tables like
select t2.PersonID,
t2.Date,
t1.Object,
t2.Property
from table2 t2
left join table1 t1 on t2.PersonID = t1.PersonID
order by t2.PersonID
Use a additional column to make every key unique in both tables. For example in SQLite you could use RowIDs to keep track of the order of insertion. To store this additional column in the database itself might be useful for other queries as well, but you do not have to store this.
First add the column ID to both tables, the DDL queries should now look like this: (make sure you do not add the primary key constraint until both tables are filled.
CREATE TABLE table1 (
ID,
PersonID,
Date,
Object
);
CREATE TABLE table2 (
ID,
PersonID,
Date,
Property
);
Now populate the ID column. You can adjust the ID to your liking. Make sure you do this for table2 as well:
UPDATE table1
SET ID =(
SELECT table1.PersonID || '-' || table1.Date || '-' || count( * )
FROM table1 tB
WHERE table1.RowID >= tB.RowID
AND
table1.PersonID == tB.PersonID
AND
table1.Date == tB.Date
);
Now you can join them:
SELECT t2.PersonID,
t2.Date,
t1.Object,
t2.Property
FROM table2 t2
LEFT JOIN table1 t1
ON t2.ID = t1.ID;
How do I increment a column value based on previous column value in Sqlite? I need to do this for 1000+ rows. I have data in the first row say 100. I need to increment the next 1000 rows by 2.
Row# ColName
1 100
2 102
3 104
4 106
I tried something like this:
Update Table SET ColName = (Select max(ColName ) from Table ) + 2 but this puts 102 in all columns.
Assuming that this table has a rowid column, it is possible to count how many previous rows there are:
UPDATE MyTable
SET ColName = (SELECT MAX(ColName)
FROM MyTable
) +
(SELECT COUNT(*)
FROM MyTable AS Previous
WHERE Previous.rowid < MyTable.rowid
) * 2
WHERE ColName IS NULL
I need some help to build SQL Query. I have table having data like:
ID Date Name
1 1/1/2009 a
2 1/2/2009 b
3 1/3/2009 c
I need to get result something like...
1 1/1/2009 a
2 1/2/2009 b
3 1/3/2009 c
4 1/4/2009 Null
5 1/5/2009 Null
6 1/6/2009 Null
7 1/7/2009 Null
8 1/8/2009 Null
............................
............................
............................
30 1/30/2009 Null
31 1/31/2009 Null
I want query something like..
Select * from tbl **where month(Date)=1 AND year(Date)=2010**
Above is not completed query.
I need to get all the record of particular month, even if some date missing..
I guess there must be equi Join in the query, I am trying to build this query using Equi join
Thanks
BIG EDIT
Now understand the OPs question.
Use a common table expression and a left join to get this effect.
DECLARE #FirstDay DATETIME;
-- Set start time
SELECT #FirstDay = '2009-01-01';
WITH Days AS
(
SELECT #FirstDay as CalendarDay
UNION ALL
SELECT DATEADD(d, 1, CalendarDay) as CalendarDay
FROM Days
WHERE DATEADD(d, 1, CalendarDay) < DATEADD(m, 1, #FirstDay)
)
SELECT DATEPART(d,d.CalendarDay), **t.date should be (d.CalendarDay)**, t.Name FROM Days d
LEFT JOIN tbl t
ON
d.CalendarDay = t.Date
ORDER BY
d.CalendarDay;
Left this original answer at bottom
You need DATEPART, sir.
SELECT * FROM tbl WHERE DATEPART(m,Date) = 1
If you want to choose month and year, then you can use DATEPART twice or go for a range.
SELECT * FROM tbl WHERE DATEPART(m,Date) = 1 AND DATEPART(yyyy,Date) = 2009
Range :-
SELECT * FROM tbl WHERE Date >= '2009-01-01' AND Date < '2009-02-01'
See this link for more info on DATEPART.
http://msdn.microsoft.com/en-us/library/ms174420.aspx
You can use less or equal to.
Like so:
select * from tbl where date > '2009-01-01' and date < '2009-02-01'
However, it is unclear if you want month 1 from all years?
You can check more examples and functions on "Date and Time Functions" from MSDN
Create a temporary table containing all days of that certain month,
Do left outer join between that table and your data table on tempTable.month = #month.
now you have a big table with all days of the desired month and all the records matching the proper dates + empty records for those dates who have no data.
i hope that's what you want.