I have an SQLite3 database from which I want to remove rows that have two fields of the same value.
It seems that I am able to select such values with this query:
SELECT * FROM mydb GROUP BY user_id, num HAVING COUNT(*) > 1
However I am not able to delete them.
DELETE FROM mydb WHERE user_id IN (SELECT * FROM mydb GROUP BY user_id, num HAVING COUNT(*) > 1)
returns a syntax error.
This is what I expect:
Example:
id user_id num
1 1 1
2 1 1
3 2 1
4 1 2
5 2 2
In this example id 1 and 2 have both columns (user_id and num) of the same value so they should be removed. Preferably, but not necessarily I would like to have a solution that would leave only one such row (doesn't matter which one).
Result:
id user_id num
2 1 1
3 2 1
4 1 2
5 2 2
Note: id is a primary key. user_id is a foreign key. num is an INTEGER.
You were having a syntax error because your IN operator has a single value on the left (user_id) but a table of non-single-value rows in the right side (SELECT *). Compare like with like; WHERE user_id IN (SELECT user_id ...) to avoid it.
Anyway, here's a query to delete all-but-newest:
DELETE FROM mydb
WHERE id NOT IN (
SELECT MAX(id) FROM mydb
GROUP BY user_id, num
);
The subquery will return the highest id for every unique (user_id, num) combination. Then we just delete all the other rows. I.e. in your example, the subquery would return 2, 3, 4, 5 as "correct", which would result in deletion of row 1.
Related
I need to get the next row from an ORDERBY query
I have 2 columns, ID(Primary key), Age(float) in a table T and I need something like the following
SELECT ID FROM T WHERE !> (inputted ID) + 1 rowID/Next row <! ORDERBY Age (then primary key, but I suspect if the Age values are the same SQLite would default to order by primary key anyway) LIMIT 1
Essentially it would select the next row after the inputted ID in the ordered table, its the next row / rowID + 1 I am not sure how to get.
As suggested here is a data set as an example
https://dbfiddle.uk?rdbms=sqlite_3.27&fiddle=19685ac20cc42041a59d318a01a2010f
ID Age
1 12.2
2 36.8
3 22.5
4 41
5 16.7
I am attempting to get the the following row from the ordered (by age) list given a specific ID
ID Age
1 12.2
5 16.7
3 22.5
2 36.8
4 41
Something similar to
SELECT ID FROM OrderedInfo WHERE ID = 5 ORDER BY Age ASC LIMIT 1 OFFSET 1;
My expected result would be '3' from the example data above
I have expanded the data set to include duplicate entries as I didn't implicitly state it could have such data - as such forpas answer works for the first example with no duplicate entries - thanks for your help
https://dbfiddle.uk?rdbms=sqlite_3.27&fiddle=f13d7f5a44ba414784547d9bbdf4997e
Use a subquery for the ID that you want in the WHERE clause:
SELECT *
FROM OrderedInfo
WHERE Age > (SELECT Age FROM OrderedInfo WHERE ID = 5)
ORDER BY Age LIMIT 1;
See the demo.
If there are duplicate values in the column Age use a CTE that returns the row that you want and join it to the table so that you expand the conditions:
WITH cte AS (SELECT ID, Age FROM OrderedInfo WHERE ID = 5)
SELECT o.*
FROM OrderedInfo o INNER JOIN cte c
ON o.Age > c.Age OR (o.Age = c.Age AND o.ID > c.ID)
ORDER BY o.Age, o.ID LIMIT 1;
See the demo.
I have gone through a similar post in Stack overflow...
but my query is :
If my table generates a flag in run time execution,then how can I increase Grp_number(generate run time) every time my flag changes.
my Oracle query:
Select emp_id,
Case when MOD(rownum/3)=1 and rownum>1 then 'Y' else 'N' as flag
from Transaction_table
Desired o/p Data format:
emp_id Flag GRP_number
1 N 1
2 N 1
3 N 1
4 Y 2
5 N 2
6 N 2
7 Y 3
You cannot reference a column in another column in the same select list. You need to use sub query to avoid INVALID IDENTIFIER error.
Do it like -
WITH DATA AS(
SELECT emp_id,
CASE
WHEN MOD(rownum/3)=1
AND rownum >1
THEN 'Y'
ELSE 'N' AS flag
FROM Transaction_table
)
SELECT emp_id, flag, SUM(gap) over (PARTITION BY person
ORDER BY DAY) grp
FROM(
SELECT emp_id, flag,
CASE WHEN flag = lag(flag) over (PARTITION BY person
ORDER BY DAY)
THEN 0
ELSE 1
END gap
FROM DATA)
I have two tables, one with objects, one with properties of the objects. Both tables have a personal ID and a date as "key", but since multiple orders of objects can be done by one person on a single day, it doesn't match well. I do know however, that the entries are entered in the same order in both tables, so it is possible to join on the order, if the personID and date are the same.
This is what I want to accomplish:
Table 1:
PersonID Date Object
1 20-08-2013 A
2 13-11-2013 B
2 13-11-2013 C
2 13-11-2013 D
3 21-11-2013 E
Table 2:
PersonID Date Property
4 05-05-2013 $
1 20-08-2013 ^
2 13-11-2013 /
2 13-11-2013 *
2 13-11-2013 +
3 21-11-2013 &
Result:
PersonID Date Object Property
4 05-05-2013 $
1 20-08-2013 A ^
2 13-11-2013 B /
2 13-11-2013 C *
2 13-11-2013 D +
3 21-11-2013 E &
So what I want to do, is join the two tables and "zip" the group of entries that have the same (PersonID,Date) "key".
Something called "Slick" seems to have this (see here), but I'd like to do it in SQLite.
Any advice would be amazing!
You are on the right track. Why not just do a LEFT JOIN between the tables like
select t2.PersonID,
t2.Date,
t1.Object,
t2.Property
from table2 t2
left join table1 t1 on t2.PersonID = t1.PersonID
order by t2.PersonID
Use a additional column to make every key unique in both tables. For example in SQLite you could use RowIDs to keep track of the order of insertion. To store this additional column in the database itself might be useful for other queries as well, but you do not have to store this.
First add the column ID to both tables, the DDL queries should now look like this: (make sure you do not add the primary key constraint until both tables are filled.
CREATE TABLE table1 (
ID,
PersonID,
Date,
Object
);
CREATE TABLE table2 (
ID,
PersonID,
Date,
Property
);
Now populate the ID column. You can adjust the ID to your liking. Make sure you do this for table2 as well:
UPDATE table1
SET ID =(
SELECT table1.PersonID || '-' || table1.Date || '-' || count( * )
FROM table1 tB
WHERE table1.RowID >= tB.RowID
AND
table1.PersonID == tB.PersonID
AND
table1.Date == tB.Date
);
Now you can join them:
SELECT t2.PersonID,
t2.Date,
t1.Object,
t2.Property
FROM table2 t2
LEFT JOIN table1 t1
ON t2.ID = t1.ID;
I already have an id as primary key so I can't use this construct.
I have a table with 5 fields, I'd like to not have more than one row with the same values of field1 field2 and field3.
That is, suppose I have A,B,C,D,E as field values (+1 id column)
Rows like;
1 2 3 4 5
A B C F A (row1)
A B E F B (row 2)
are allowed as field 3 is different among rows (C in row1 and E in row 2).
But a row
A B C E B (row 3)
should not be allowed, as field 1 2 and 3 are exactly the same of row 1.
primary key(field1,field2,field3) would solve my problem, but I'd like for it to be an id and so I can't use it.
There are more constraint types than PRIMARY KEY.
Use a UNIQUE constraint:
CREATE TABLE MyTable(
ID PRIMARY KEY,
Field1,
Field2,
Field3,
[...],
UNIQUE (Field1, Field2, Field3)
);
This is quite clumsy.
Initial info: There's a clumsy select query eventually returning 0 or 1 depending on several conditions. Usually it get's to select only one row (other data is cut of by where, etc.). The problem occurs when there's more rows to parse. So the data actually looks like follows:
Status
0
1
instead of
Status
1
Problem: Only one rowed data is needed in return, i.e. if there's a 1 present in any row, it should 1 returned, otherwise 0.
Condition: It should be done only in a query (no variables, ifs etc.).
Thanks in advance.
If you are sure that 1 and 0 are the only valuesbeing returned, Can't you use a max over this query to see any 1s..?
select max(id) result
from (
select 1 id from dual
union all
select 0 id from dual
)
RESULT
----------
1
1 select max(id)
2 from (
3 select 0 id from dual
4 union all
5 select 0 id from dual
6 union all
7 select 0 id from dual
8* )
SQL> /
MAX(ID)
----------
0