Comparison of two CSV files - unix

I'm trying to use Awk to compare the content of two large CSV files (more than 5000 rows each) but I can't get what I want.
Here is my problem:
I have a first file (File1) with a list of names ($1) and cities ($2) whose structure looks like this:
john;london
marc;paris
karen;new york
ben;london
vic;dublin
I have a second file (File2) with other information where we find some names ($3) of File1:
45456;windows;john;454646
47764;mac;zack;470093
41225;mac;ben;622101
12634;windows;ben;218996
7856;windows;karen;637294
12;mac;finn;878317
2315;windows;beverly;221167
445;windows;lilly;12316
3232;mac;john;601316
4546;mac;fish;305035
487;windows;vic;447421
46464;mac;karen;468154
I would like to extract from File2 all the lines whose names appear in File1 while adding the cities associated to each name in File1. Here is an example of the result I am looking for:
45456;windows;john;454646;london
3232;mac;john;601316;london
7856;windows;karen;637294;new york
46464;mac;karen;468154;new york
41225;mac;ben;622101;london
12634;windows;ben;218996;london
487;windows;vic;447421;dublin
Could you help me?

Build an associative array of the first file, making the name the index and the city the value. For the second file check if the name features in the aray, if yes, print the line and attach the city.
awk -F';' 'NR==FNR{a[$1]=$2}$3 in a{print $0";"a[$3]}' File1 File2
45456;windows;john;454646;london
41225;mac;ben;622101;london
12634;windows;ben;218996;london
7856;windows;karen;637294;new york
3232;mac;john;601316;london
487;windows;vic;447421;dublin
46464;mac;karen;468154;new york

With bash, GNU sort and GNU join:
join -t ';' -1 1 -2 3 <(sort File1) <(sort -t ';' -k 3 File2) -o 2.1,2.2,1.1,2.4,1.2
Output:
12634;windows;ben;218996;london
41225;mac;ben;622101;london
45456;windows;john;454646;london
3232;mac;john;601316;london
46464;mac;karen;468154;new york
7856;windows;karen;637294;new york
487;windows;vic;447421;dublin

Using csvkit
csvjoin -d ';' -H -c 3,1 File2 File1 | csvformat -D ';' | tail -n +2

Related

what is the alternate way to count the occurrence of each word without using 'uniq -c' command?

Is it possible to count the occurrence of each word like using uniq -c but with the count after the word rather than before?
Example scenario
Input file named as text1.txt which contain the following data
Renault:cilo:84563
Renault:cilo:84565
M&M:Thar:84566
Tata:nano:84567
M&M:quanto:84568
M&M:quanto:84569
The fields used in the above data are car_company:car_model:customerID
Desired result
cilo 2
Thar 1
nano 1
quanto 2
(car_model and number of cars sold grouped by car_model)
My code
cat test1.txt | cut -d: -f2 | uniq -c
Actual Result
2 cilo
1 Thar
1 nano
2 quanto
Is it possible to do the above process without using uniq -c ,so that I can swap the order of the fields (columns)?
You can use uniq, and simply post-process its output to swap the columns:
cut -d: -f2 test1.txt | uniq -c | awk '{print $2 "\t" $1 "\n" }'
EDIT: Added \n, as noted in a comment.
Save your commands output into a file "badresult";
cat test1.txt | cut -d: -f2 | uniq -c > badresult
Then cut the seventh field and save it into a file named "counts"(you should use space(" ") as a seperator);
cut -d" " -f7 badresult > counts
Then cut the eighth field and save it into a file named "models"(you should use space(" ") as a seperator);
cut -d" " -f8 badresult > models
Now you have your counts and models in seperate files. All you have to do is to show these two files seperately with "pr" command(-m: one file per column, -T:no pre-information)
pr -m -T models counts
Using awk:
cat test1.txt | cut -d: -f2 | uniq -c | awk '{ t = $1; $1 = $2; $2 = t; print }'
The little awk code exchanges fields 1 and 2 using a temporary.
You just need awk for this:
$ awk -F: '{a[$2]++} END {for (i in a) print i, a[i]}' file
cilo 2
quanto 2
nano 1
Thar 1
This goes through every line keeping track of how many times the second field has appeared. Since everything is stored in the array a, then it is just a matter of looping through it and printing its content.

Compare 2 files in unix file1(2M numbers/rows/lines) , file2(2,000,480 numbers/rows/lines)

How can I compare this 2 big files in unix.
I've already tried using 'grep -Fxvf file1.txt file2.txt | wc -l' but the output is 2,000,480 and when switching file1 and file2 the output is 1,999,999.
How can I get the output of '480' because that's what i am expecting.
I've also tried using diff/cmp commands but the output is too complicated.
I think you want an absolute value of a difference in line numbers in 2 files. You can achieve it easily with awk and get a decent result. You'd read numbers of lines in an array and later subtract the array values in the END block. For pure shell it'd have to get more complex. Imagine you get some test data generated (10 and 14 line files):
$ seq 1 10 > ten
$ seq 1 14 > fourteen
And then you do:
$ ( wc -l ten ; wc -l fourteen ) | awk '{ print $1}' | sort -rn | xargs -J % echo % - p | dc
The result:
4
But much better way would be do just do it in 3 lines (get word count for file1, then file2 and then subtract)

How to get a pattern from a file and search in another file in unix

I have 2 files File1 and File2.
File1 has some values separated by "|". For example,
A|a
C|c
F|f
File2 also has some values separated by "|". For example,
a|1
b|2
c|3
d|4
e|5
Means 2nd column in File1 is resembled with 1st column of File2.
I have to create 3rd file File3 with expected output
A|a|1
C|c|3
I tried to take each record in loop and searched for that in File2 using "awk".
It worked, but the problem is both File1 and File2 are having more than 5 million records.
I need an optimized solution.
You can use this awk,
awk -F'|' 'NR==FNR{a[$2]=$1;next} $1 in a { print a[$1],$1,$2 }' OFS="|" file1 file2 > file3
More clearer way:
awk 'BEGIN{ OFS=FS="|";} NR==FNR{a[$2]=$1;next} $1 in a { print a[$1],$1,$2 }' file1 file2 > file3
As per #Kent suggestion:
If your file2 have more than two columns that you want it in file3 then,
awk 'BEGIN{ OFS=FS="|";} NR==FNR{a[$2]=$1;next} $1 in a { print a[$1],$0 }' file1 file2 > file3
Here,
FS - Field Separator
OFS - Output Field Separator
This is what join was created to do:
$ join -t '|' -o '1.1,1.2,2.2' -1 2 -2 1 file1 file2
A|a|1
C|c|3
man join for more details and pay particular attention to the files needing to be sorted on the join fields (i.e. 2nd field for file1 and 1st field for file2), as your posted sample input is.

Create a CSV File with specific format from a String obtained after WS Invocation

The title is self explanatory. I am calling a web service which is returning a String like this :
First Name="Kunal";Middle Name="";Last Name="Bhowmick";Address 1="HGB";Address 2="cvf";Address 3="tfg";City="DF";State="KL";Country="MN";Postal Code="0012";Telephone="(+98)6589745623"
Now i have to write a shell script to create a csv file named CSV_Output.csv and the file must be formatted with the String content.
The format must be something like this :
Field Name(in yellow color) Value(in yellow color)
First Name Kunal
Middle Name
Last Name Bhowmick
Address 1 HGB
Address 2 cvf
Address 3 tfg
City DF
State KL
Country MN
Postal Code 0012
Telephone (+98)6589745623
Now I can easily generate a CSV file using redirection(>>), but how can i create and format a CSV file like in the format show above ?
Sorry, to be blunt and i have no code to show as well, as i am not understanding what to use here.
Kindly provide some suggestions(sample code). Any help is greatly appreciated .
an awk one-liner could convert the format:
awk -v RS="\\n|;" -v OFS="\t" -F= '{gsub(/"/,"");$1=$1}7' file
if you want the output to look better, you could pass the output to column and change the OFS like:
awk -v RS="\\n|;" -v OFS="#" -F= '{gsub(/"/,"");$1=$1}7' file|column -s"#" -t
the output is:
kent$ awk -v RS="\\n|;" -v OFS="#" -F= '{gsub(/"/,"");$1=$1}7' f|column -s"#" -t
First Name Kunal
Middle Name
Last Name Bhowmick
Address 1 HGB
Address 2 cvf
Address 3 tfg
City DF
State KL
Country MN
Postal Code 0012
Telephone (+98)658974562
short explanation:
awk #awk command
-v RS="\\n|;" #set line separator is \n(newline) or ;(semi)
-v OFS="\t" #set output field separator: <tab>
-F= #set "=" as field separator
'{gsub(/"/,""); #remove all double quotes
$1=$1} #$1=$1, to let awk reformat the line with given OFS
7' #the non-zero number to print the whole line.
Can be achieved using tr and column:
$ cat input
First Name="Kunal";Middle Name="";Last Name="Bhowmick";Address 1="HGB";Address 2="cvf";Address 3="tfg";City="DF";State="KL";Country="MN";Postal Code="0012";Telephone="(+98)6589745623"
$ cat input | tr ";" "\n" | column -s= -t | tr -d \"
First Name Kunal
Middle Name
Last Name Bhowmick
Address 1 HGB
Address 2 cvf
Address 3 tfg
City DF
State KL
Country MN
Postal Code 0012
Telephone (+98)6589745623
Split input on ;; pipe the output to column specifying = as the delimiter, get rid of quotes!
EDIT: Didn't realize that you want a CSV. In that event, use:
$ cat input | tr ";" "\n" | tr "=" "\t" | tr -d \"
which will result into a TAB delimited output.

How to interleave lines from two text files

What's the easiest/quickest way to interleave the lines of two (or more) text files? Example:
File 1:
line1.1
line1.2
line1.3
File 2:
line2.1
line2.2
line2.3
Interleaved:
line1.1
line2.1
line1.2
line2.2
line1.3
line2.3
Sure it's easy to write a little Perl script that opens them both and does the task. But I was wondering if it's possible to get away with fewer code, maybe a one-liner using Unix tools?
paste -d '\n' file1 file2
Here's a solution using awk:
awk '{print; if(getline < "file2") print}' file1
produces this output:
line 1 from file1
line 1 from file2
line 2 from file1
line 2 from file2
...etc
Using awk can be useful if you want to add some extra formatting to the output, for example if you want to label each line based on which file it comes from:
awk '{print "1: "$0; if(getline < "file2") print "2: "$0}' file1
produces this output:
1: line 1 from file1
2: line 1 from file2
1: line 2 from file1
2: line 2 from file2
...etc
Note: this code assumes that file1 is of greater than or equal length to file2.
If file1 contains more lines than file2 and you want to output blank lines for file2 after it finishes, add an else clause to the getline test:
awk '{print; if(getline < "file2") print; else print ""}' file1
or
awk '{print "1: "$0; if(getline < "file2") print "2: "$0; else print"2: "}' file1
#Sujoy's answer points in a useful direction. You can add line numbers, sort, and strip the line numbers:
(cat -n file1 ; cat -n file2 ) | sort -n | cut -f2-
Note (of interest to me) this needs a little more work to get the ordering right if instead of static files you use the output of commands that may run slower or faster than one another. In that case you need to add/sort/remove another tag in addition to the line numbers:
(cat -n <(command1...) | sed 's/^/1\t/' ; cat -n <(command2...) | sed 's/^/2\t/' ; cat -n <(command3) | sed 's/^/3\t/' ) \
| sort -n | cut -f2- | sort -n | cut -f2-
With GNU sed:
sed 'R file2' file1
Output:
line1.1
line2.1
line1.2
line2.2
line1.3
line2.3
Here's a GUI way to do it: Paste them into two columns in a spreadsheet, copy all cells out, then use regular expressions to replace tabs with newlines.
cat file1 file2 |sort -t. -k 2.1
Here its specified that the separater is "." and that we are sorting on the first character of the second field.

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