zsh command line processing - separating the last arguments from the previous ones - zsh

I am writing a zsh script, which is invoked with a variable number of arguments, such as
scriptname a b c d filename
Inside the script, I want first to loop over the arguments (except the last one) and process them, and finally do something with the processed data and the last argument (filename).
I got this working, but am not entirely happy with my solution. Here is what I came up with (where process and apply are some other scripts not relevant to my problem):
#!/bin/zsh
set -u
x=""
filename=$#[-1]
# Process initial arguments
for ((i=1; i<$#; i++))
do
x+=$(process ${#[$i]})
done
apply $x $filename
I find the counting loop too cumbersome. If filename where the first argument, I would do a shift and then could simply loop over the arguments, after having saved the filename. However I want to keep the filename as the last argument (for consistency with other tools).
Any ideas how to write this neatly without counting loop?

You can slice off the last argument from the original list and save them into an array, if thats an option
args=("${#:1:$# -1}")
for arg in "${args[#]}"; do # iterate over all, except the last
printf '%s\n' "$arg"
done
Using the array as a placeholder is optional as you can iterate over the arguments slice directly i.e. for arg in "${#:1:$# -1}"; do. The syntax is even available in bash also.
As pointed out by chepner's comment, you could use a zsh specifc syntax as
for arg in $#[1,-2]; do
printf '%s\n' "$arg"
done

Related

applying zsh qualifiers on array elements or directly on a result of a command substitution

I did
a=( pacman -Qlq packagename )
to put files belonging to package into array
Why is this printing only the frist match, and how to print them all in zsh:
print -l ${a[(r)*i*]}
Also, how to apply zsh qualifiers on all array elements, say to list files
only via (.)
Is there an easier way to skip intermediary array in this process,
in a way to have qualifier specified on a result of a command substition?
As per documentation the subscript flag (r) will only return the first matching array element.
In order to get all matching elements you can use the {name:#pattern} parameter expansion, which removes any element maching pattern from the expansion. In order to remove the non-matching elements you can either use the flag (M) or negate the pattern with ^ (this requires the EXTENDED_GLOB option to be enabled):
print -l ${(M)a:#*i*}
setopt extendedglob
print -l ${a:#^*i*}
You can skip explicitly creating an intermediary array by just using the parameter expansion on the command substitution ($(...)) directly:
print -l ${(M)$(pacman -Qlq packagename):#*i*}
It seems that globbing qualifiers do not work with patterns inside parameter expansions. But you can enable the RC_EXPAND_PARAM option to expand every single array element within a word instead of the whole array. So foo${xx}bar with x=(a b c) will be expanded to fooabar foobbar foocbar instead of fooa b cbar. You can enabley it either globally with setopt rcexpandparam or for a specific expansion by wrapping it in ${^...}. This way you can add a glob qualifier to each element of the filtered array. To print only elements that are paths to files, you can use
print -l ${^${(M)$(pacman -Qlq packagename):#*i*}}(.N)
This essentially takes each path and attaches (.N) as glob qualifier (which works, even though there are no globs). The resulting patterns are then evaluated as part of filename generation. . tells zsh to only match plain files. N enables the NULL_GLOB option for these patterns, otherwise the command would abort with an "no matches found" error, if it encounters a pattern that is not a plain file (e.g. /usr is a directory, so /usr(.) does not match any plain file on your system.).

Zsh: How to force file completion everywhere following a set of characters?

I'm trying to figure out how to get file completion to work at any word position on the command line after a set of characters. As listed in a shell these characters would be [ =+-\'\"()] (the whitespace is tab and space). Zsh will do this, but only after the backtick character, '`', or $(. mksh does this except not after the characters [+-].
By word position on the command line, I'm talking about each set of characters you type out which are delimited by space and a few other characters. For example,
print Hello World,
has three words at positions 1-3. At position 1, when you're first typing stuff in, completion is pretty much perfect. File completion works after all of the characters I mentioned. After the first word, the completion system gets more limited since it's smart. This is useful for commands, but limiting where you can do file completion isn't particularly helpful.
Here are some examples of where file completion doesn't work for me but should in my opinion:
: ${a:=/...}
echo "${a:-/...}"
make LDFLAGS+='-nostdlib /.../crt1.o /.../crti.o ...'
env a=/... b=/... ...
I've looked at rebinding '^I' (tab) with the handful of different completion widgets Zsh comes with and changing my zstyle ':completion:*' lines. Nothing has worked so far to change this default Zsh behaviour. I'm thinking I need to create a completion function that I can add to the end of my zstyle ':completion:*' completer ... line as a last resort completion.
In the completion function, one route would be to cut out the current word I want to complete, complete it, and then re-insert the completion back into the line if that's possible. It could also be more like _precommand which shifts the second word to the first word so that normal command completion works.
I was able to modify _precommand so that you can complete commands at any word position. This is the new file, I named it _commando and added its directory to my fpath:
#compdef -
# precommands is made local in _main_complete
precommands+=($words[1,$(( CURRENT -1 ))])
shift words
CURRENT=1
_normal
To use it I added it to the end of my ':completion:*' completer ... line in my zshrc so it works with every program in $path. Basically whatever word you're typing in is considered the first word, so command completion works at every word position on the command line.
I'm trying to figure out a way to do the same thing for file completion, but it looks a little more complicated at first glace. I'm not really sure where to go with this, so I'm looking to get some help on this.
I took a closer look at some of Zsh's builtin functions and noticed a few that have special completion behaviour. They belong to the typeset group, which has a function _typeset in the default fpath. I only needed to extract a few lines for what I wanted to do. These are the lines I extracted:
...
elif [[ "$PREFIX" = *\=* ]]; then
compstate[parameter]="${PREFIX%%\=*}"
compset -P 1 '*='
_value
...
These few lines allow typeset completion after each slash in a command like this:
typeset file1=/... file2=~/... file3=/...
I extrapolated from this to create the following function. You can modify it to put in your fpath. I just defined it in my zshrc like this:
_reallyforcefilecompletion() {
local prefix_char
for prefix_char in ' ' $'\t' '=' '+' '-' "'" '"' ')' ':'; do
if [[ "$PREFIX" = *${prefix_char}* ]]; then
if [[ "$PREFIX" = *[\'\"]* ]]; then
compset -q -P "*${prefix_char}"
else
compset -P "*${prefix_char}"
fi
_value
break
fi
done
}
You can use this by adding it to a zstyle line like this:
zstyle ':completion:*' completer _complete _reallyforcefilecompletion
This way, it's only used as a last resort so that smarter completions can try before it. Here's a little explanation of the function starting with the few variables and the command involved:
prefix_char: This gets set to each prefix character we want to complete after. For example, env a=123 has the prefix character =.
PREFIX: Initially this will be set to the part of the current word from the beginning of the word up to the position of the cursor; it may be altered to give a common prefix for all matches.
IPREFIX (not shown in code): compset moves string matches from PREFIX to IPREFIX so that the rest of PREFIX can be completed.
compset: This command simplifies modification of the special parameters, while its return status allows tests on them to be carried out.
_value: Not really sure about this one. The documentation states it plays some sort of role in completion.
Documentation for the completion system
The function: In the second line, we declare prefix_char local to avoid variable pollution. In line three, we start a for loop selecting each prefix_char we want to complete after. In the next if block, we check if the variable PREFIX ends with one of the prefix_chars we want to complete after and if PREFIX contains any quotes. Since PREFIX contains quotes, we use compset -q to basically allow quotes to be ignored so we can complete in them. compset -P strips PREFIX and moves it to IPREFIX, basically so it gets ignored and completion can work.
The next elif statement is for a PREFIX ending with prefix_char but not containing quotes, so we only use compset -P. I added the return 0 to break the loop. A more correct way to make this function would be in a case statement, but we're not using the compset return value, so this works. You don't see anything about file completion besides _value. For the most part we just told the system to ignore part of the word.
Basically this is what the function does. We have a line that looks like:
env TERM=linux PATH=/<---cursor here
The cursor is at the end of that slash. This function allows PREFIX, which is PATH=, to be ignored, so we have:
env TERM=linux /<---cursor here
You can complete a file there with PATH= removed. The function doesn't actually remove the PATH= though, it just recategorizes it as something to ignore.
With this function, you can now complete in all of the examples I listed in the question and a lot more.
One last thing to mention, adding this force-list line in your zshrc cripples this function somehow. It still works but seems to choke. This new force-list function is way better anyway.
zstyle ':completion:*' force-list always
EDIT: There were a couple lines I forgot to copy into the function. Probably should have checked before posting. I think it's good now.

Make zsh complete arguments from a file

zsh is great but its completion system is very diverse. And the documentation lacks good examples. Is there a template for completing for a specific application. The completion would get its match data from a file, separated by newlines?
I tried modifying an older example of mine that takes match data "live":
~ % cat .zsh/completers/_jazzup
#compdef jazz_up
_arguments "2: :(`mpc lsplaylists|sed -e 's# #\\\\ #g'`)"
I could supply cat my_file there instead of mpc invocation and so on but would there be a more elegant way to do this simple task? And that completion there is placement-specific: can you provide an example where zsh would attempt to complete at any point after the program name is recognized?
The match data will have whitespaces and so on, the completion should escape the WS. Example of that:
Foo bar
Barbaric
Get it (42)
Now if that completion would be configured for a command Say, we should get this kind of behaviour out of zsh:
$ Say Fo<TAB>
$ Say Foo\ bar
$ Say Ge<TAB>
$ Say Get\ it\ \(42\)
Simple completion needs are better addressed with _describe, it pairs an array holding completion options and a description for them (you can use multiple array/description pairs, check the manual).
(_arguments is great but too complex.)
[...]
First create a file
echo "foo\nbar\nbaz\nwith spac e s\noh:noes\noh\:yes" >! ~/simple-complete
Then create a file _simple somewhere in your $fpath:
#compdef simple
# you may wish to modify the expansion options here
# PS: 'f' is the flag making one entry per line
cmds=( ${(uf)"$(< ~/simple-complete)"} )
# main advantage here is that it is easy to understand, see alternative below
_describe 'a description of the completion options' cmds
# this is the equivalent _arguments command... too complex for what it does
## _arguments '*:foo:(${cmds})'
then
function simple() { echo $* }
autoload _simple # do not forget BEFORE the next cmd!
compdef _simple simple # binds the completion function to a command
simple [TAB]
it works. Just make sure the completion file _simple is placed somewhere in your fpath.
Notice that : in the option list is supposed to be used for separating an option from their (individual) description (oh:noes). So that won't work with _describe unless you quote it (oh\:yes). The commented out _arguments example will not use the : as a separator.
Without changing anything further in .zshrc (I already have autoload -Uz compinit
compinit) I added the following as /usr/local/share/zsh/site-functions/_drush
#compdef drush
_arguments "1: :($(/usr/local/bin/aliases-drush.php))"
Where /usr/local/bin/aliases-drush.php just prints a list of strings, each string being a potential first argument for the command drush. You could use ($(< filename)) to complete from filename.
I based this on https://unix.stackexchange.com/a/458850/9452 -- it's surprising how simple this is at the end of the day.

How can I implement the command 'ls' with wildcard, '*'?

EDIT #1 : I'm under the limit that all arguments are enclosed in two quotes, so that shell do not expand any argument with * to the corresponding path.
EDIT #2 : In order to retrieve directories such as */*, ../*, and dirA/*/file.out, How should I use iteration loop or recursive call?
I have just learned about the function fnmatch(). But I don't know start place.
There are many possible cases. I'm confused dealing with these all cases.
For example, Let me assume that executable program is a.out.
$./a.out -l */*
$./a.out -l ../*
$./a.out -l [file_name] [directory_name]
/* Since I also have to implement ls command with no wildcard. */
What should I do? Any advice would be awesome.
Thank you in advance.
Your problem is : shell replaces wildcard caracter * with all of the filenames matching the pattern.
Solution:
If you do not want to use this feature of bash, just put quotation marks around your command line arguments.
Calling your program that way will have the original arguments, containing wildcards.
After this, you can list all the filenames with their paths. For example using some recursive algorithm. Then you can apply some matching to these path string. (when visiting it)
If you want to be a good unix citizen, the rule is Don't do filename globbing unless you are writing a shell.
You want to write an ls-like program? Don't do any wildcard expansion. Don't treat "*" specially. Just treat your argv as a list of filenames. If your program handles these cases:
./a.out file1
./a.out file1 file2 file3
Then it will also handle
./a.out file*
correctly because the shell will do the expansion and your program won't need to know about it. And besides that, it will handle this:
zsh% ./a.out **/file<40-185>~file<90-100>(.mm-30OL[1,2])
which in zsh expanded glob syntax means: expand file40 through file185, except for file90 through file100, include only the ones that have been modified in the last 30 minutes, and use only the largest 2 files in the resulting set.
fnmatch is never going to do anything like that. But these fancy globs can be used with any command that just takes a filename list and doesn't care where it came from.
When you're in a situation where you can't take a list of filenames from the command line, then consider using fnmatch. ls isn't one of those situations.

need help in unix for iterating a for loop

The bellow line code is not working.it is not iterating through the directory.
input={20132802,20132802}
for i in $(ls -1 /home/$input/*s.log)
do
...
done
but when providing the input in the loop working fine.
for i in $(ls -1 /home/{20132802,20132802}/*s.log)
do
...
done
please help.
Brace expansion cannot be used in variables because it is performed before any other expansions.
From man bash:
Brace expansion is performed before any other expansions, and any
characters special to other expansions are preserved in the result. It
is strictly textual. Bash does not apply any syntactic interpretation
to the context of the expansion or the text between the braces. To
avoid conflicts with parameter expansion, the string ‘${’ is not
considered eligible for brace expansion.
However, you can use eval to overcome this limitation:
input={20132802,20132802}
for i in $(eval ls -1 /home/$input/*s.log)
do
...
done
Obligatory reading: eval is evil
Try writing ${input} instead of $input since i is the index of the for loop and I guess $i is used when you write $input ('$i'nput).

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