I am writing a ruby file that is called from zsh and, among others, I am trying to pass an array as an input variable like that:
ruby cim_manager.rb test --target=WhiteLabel --devices=["iPhone 8", "iPhone 12 Pro"]
Inside my ruby file I have a function:
# Generates a hash value from an array of arguments
#
# #param [Array<String>] The array of values. Each value of the array needs to separate the key and the value with "=". All "--" substrings will be replaced for empty substrings
#
# #return [Hash]
#
def generate_hash_from_arguemnts(args)
hash = {}
args.each{ |item|
item = item.gsub("--", "")
item = item.split("=")
puts item.kind_of?(Array)
hash[item[0].to_s] = item[1].to_s
}
return hash
end
So I can have a value like:
{"target": "WhiteLabel", "devices": ["iPhone 8", "iPhone 12 Pro"]}
The error I am getting when executing my Ruby file is:
foo#Mac-mini fastlane % ruby cim_manager.rb test --target=WhiteLabel --devices=["iPhone 8", "iPhone 12 Pro"]
zsh: bad pattern: --devices=[iPhone 8,
Any ideas?
#ReimondHill : I don't see how the error is possibly related to Ruby. You have a zsh-line, in which you have --devices= [.... You could get the same error when doing a
echo --devices=["iPhone 8", "iPhone 12 Pro"]
An open square bracket is a zsh wildcard construct; for instance, [aeiou] is a wildcard which tries to match against a vocal in a file name. Hence, this parameter tries to match against files starting with the name --devices= in your working directory, so you would expect an error message like no matches found: --devices=.... However, there is one gotcha: The list of characters between [ ... ] must not have an (unescaped) space. Therefore, you don't see no matches found, but bad pattern.
After all, you don't want a filename expansion to occur, but pass the parameter to your program. Therefore you need to quote it:
ruby .... '--devices=["iPhone 8", "iPhone 12 Pro"]'
Ronald
Following the answer from #user1934428, I am extending my ruby file like that:
# Generates a hash value from an array of arguments
#
# #param [Array<String>] The array of values. Each value of the array needs to separate the key and the value with "=". All "--" substrings will be replaced for empty substrings
#
# #return [Hash]
#
def generate_hash_from_arguemnts(args)
hash = {}
args.each{ |item|
item = item.gsub("--", "")
item = item.gsub("\"", "")
item = item.split("=")
key = item[0].to_s
value = item[1]
if value.include?("[") && value.include?("]") #Or any other pattern you decide
value = value.gsub("[","")
value = value.gsub("]","")
value = value.split(",")
end
hash[key] = value
}
return hash
end
And then my zsh-line:
ruby cim_manager.rb test --target=WhiteLabel --devices='[iPhone 8,iPhone 12 Pro]'
The return value from generate_hash_from_arguemnts prints:
{"target"=>"WhiteLabel", "devices"=>["iPhone 8", "iPhone 12 Pro"]}
Related
I was given an encrypted copy of the study guide here, but how do you decrypt and read it???
In a file called pa11.py write a method called decode(inputfile,outputfile). Decode should take two parameters - both of which are strings. The first should be the name of an encoded file (either helloworld.txt or superdupertopsecretstudyguide.txt or yet another file that I might use to test your code). The second should be the name of a file that you will use as an output file.
Your method should read in the contents of the inputfile and, using the scheme described in the hints.txt file above, decode the hidden message, writing to the outputfile as it goes (or all at once when it is done depending on what you decide to use).
The penny math lecture is here.
"""
Program: pennyMath.py
Author: CS 1510
Description: Calculates the penny math value of a string.
"""
# Get the input string
original = input("Enter a string to get its cost in penny math: ")
cost = 0
Go through each character in the input string
for char in original:
value = ord(char) #ord() gives us the encoded number!
if char>="a" and char<="z":
cost = cost+(value-96) #offset the value of ord by 96
elif char>="A" and char<="Z":
cost = cost+(value-64) #offset the value of ord by 64
print("The cost of",original,"is",cost)
Another hint: Don't forget about while loops...
Another hint: After letters -
skip ahead by their pennymath value positions + 2
After numbers - skip ahead by their number + 7 positions
After anything else - just skip ahead by 1 position
The issue I'm having in that I cant seem to get the coding right to decode the file it comes out looking the same. This is the current code I have been using. But once I try to decrypt the message it stays the same.
def pennycost(c):
if c >="a" and c <="z":
return ord(c)-96
elif c>="A" and c<="Z":
return ord(c)-64
def decryption(inputfile,outputfile):
with open(inputfile) as f:
fo = open(outputfile,"w")
count = 0
while True:
c = f.read(1)
if not c:
break;
if count > 0:
count = count -1;
continue
elif c.isalpha():
count = pennycost(c)
fo.write(c)
elif c.isdigit():
count = int(c)
fo.write(c)
else:
count = 6
fo.write(c)
fo.close()
inputfile = input("Please enter the input file name: ")
outputfile = input("Plese enter the output file name(EXISTING FILE WILL BE OVER WRITTEN!): ")
decryption(inputfile,outputfile)
I have 5 functions working relatively
1- singleline_diff(line1, line2)
comparing 2 line in one file
Inputs:
line1 - first single line string
line2 - second single line string
Output:
the index of the first difference between the two lines
identical if the two lines are the same.
2- singleline_diff_format(line1, line2, idx):
comparing 2 line in one file
Inputs:
line1 - first single line string
line2 - second single line string
idx - index at which to indicate difference (from 1st function)
Output:
abcd (first line)
==^ (= indicate identical character, ^ indicate the difference)
abef (second line)
If either input line contains a newline or carriage return,
then returns an empty string.
If idx is not a valid index, then returns an empty string.
3- multiline_diff(lines1, lines2):
deal with two lists of lines
Inputs:
lines1 - list of single line strings
lines2 - list of single line strings
Output:
a tuple containing the line number (starting from 0) and
the index in that line where the first difference between lines1
and lines2 occurs.
Returns (IDENTICAL, IDENTICAL) if the two lists are the same.
4-get_file_lines(filename)
Inputs:
filename - name of file to read
Output:
a list of lines from the file named filename.
If the file does not exist or is not readable, then the
behavior of this function is undefined.
5- file_diff_format(filename1, filename2) " the function with the problem"
deals with two input files
Inputs:
filename1 - name of first file
filename2 - name of second file
Output:
four line string showing the location of the first
difference between the two files named by the inputs.
If the files are identical, the function instead returns the
string "No differences\n".
If either file does not exist or is not readable, then the
behavior of this function is undefined.
testing the function:
everything goes will until it the test use one empty file
it gave me "list index out of range"
this is the code I use
def file_diff_format(filename1, filename2):
file_1 = get_file_lines(filename1)
file_2 = get_file_lines(filename2)
mli_dif = multiline_diff(file_1, file_2)
min_lens = min(len(file_1), len(file_2))
if mli_dif == (-1,-1) :
return "No differences" "\n"
else:
diff_line_indx = mli_dif[0]
diff_str_indx = int (mli_dif[1])
if len(file_1) >= 0:
line_file_1 = ""
else:
line_file_1 = file_1[diff_line_indx]
if len(file_2) >= 0:
line_file_2 = ""
else:
line_file_2 = file_2[diff_line_indx]
line_file_1 = file_1[diff_line_indx]
line_file_2 = file_2 [diff_line_indx]
out_print = singleline_diff_format(line_file_1, line_file_2, diff_str_indx)
return ( "Line {}{}{}".format ((diff_line_indx), (":\n"), (out_print)))
If one of the files is empty, either file1 or file2 should be an empty list, so that trying to access an element of either would cause the error you describe.
Your code checks for these files to be empty when assigning to line_file_`` andline_file_2`, but then goes ahead and tries to access elements of both.
declare variable $fb := doc("factbook.xml")/mondial;
for $c in $fb//country
where ($c/encompassed/#continent = 'f0_119') and ($c/#population < 100000)
return concat('Country: ',$c/name, ', Population: ',$c/#population);
it returns:
Type Error: Type of value '
()
' does not match sequence type: xs:anyAtomicType?
At characters 11681-11698
At File "q2_3.xq", line 4, characters 13-67
At File "q2_3.xq", line 4, characters 13-67
At File "q2_3.xq", line 4, characters 13-67
however, if i do not do a concat return, just name or population it will work, and most strange thing is i have another program :
declare variable $fb := doc("factbook.xml")/mondial;
for $c in $fb//country
where $c/religions = 'Seventh-Day Adventist'
order by $c/name
return concat('Country: ',$c/name, ', Population: ',$c/#population);
The return syntax is exactly same, however, it works.
Why this happens?
Without seeing an example of your data it's impossible to say for sure, but if $c/name returns more than one value, then your error would make sense. Do you have any results where there are more than one name element?
I'm trying to read a file and put contents in a list. I have done this mnay times before and it has worked but this time it throws back the error "list index out of range".
the code is:
with open("File.txt") as f:
scores = []
for line in f:
fields = line.split()
scores.append( (fields[0], fields[1]))
print(scores)
The text file is in the format;
Alpha:[0, 1]
Bravo:[0, 0]
Charlie:[60, 8, 901]
Foxtrot:[0]
I cant see why it is giving me this problem. Is it because I have more than one value for each item? Or is it the fact that I have a colon in my text file?
How can I get around this problem?
Thanks
If I understand you well this code will print you desired result:
import re
with open("File.txt") as f:
# Let's make dictionary for scores {name:scores}.
scores = {}
# Define regular expressin to parse team name and team scores from line.
patternScore = '\[([^\]]+)\]'
patternName = '(.*):'
for line in f:
# Find value for team name and its scores.
fields = re.search(patternScore, line).groups()[0].split(', ')
name = re.search(patternName, line).groups()[0]
# Update dictionary with new value.
scores[name] = fields
# Print output first goes first element of keyValue in dict then goes keyName
for key in scores:
print (scores[key][0] + ':' + key)
You will recieve following output:
60:Charlie
0:Alpha
0:Bravo
0:Foxtrot
I am trying to use Pyparsing to identify a keyword which is not beginning with $ So for the following input:
$abc = 5 # is not a valid one
abc123 = 10 # is valid one
abc$ = 23 # is a valid one
I tried the following
var = Word(printables, excludeChars='$')
var.parseString('$abc')
But this doesn't allow any $ in var. How can I specify all printable characters other than $ in the first character position? Any help will be appreciated.
Thanks
Abhijit
You can use the method I used to define "all characters except X" before I added the excludeChars parameter to the Word class:
NOT_DOLLAR_SIGN = ''.join(c for c in printables if c != '$')
keyword_not_starting_with_dollar = Word(NOT_DOLLAR_SIGN, printables)
This should be a bit more efficient than building up with a Combine and a NotAny. But this will match almost anything, integers, words, valid identifiers, invalid identifiers, so I'm skeptical of the value of this kind of expression in your parser.