End Game Function - qt

I'm trying to display "Game Over" once the player runs out of lives. However, it's never displayed after the game ends. Here is some example code.
void Game::end()
{
QGraphicsTextItem *text = new QGraphicsTextItem("GameOver");
text->setPos(400, 500);
scene->addItem(text);
sleep(2);
QApplication::quit();
}

You dont get the desired result because the drawing occurs after the function it's been called inside returns, and it never returns since you are quiting the application before. As drescherjm pointed out, try to delay the quit by using QTimer::SingleShot. Like this:
QTimer::singleShot(1000, [](){
QApplication::exit();
});
Thus QApplication::exit() is called in given interval, by which time Game::end() should return.

Related

Qt - start process with click event and stop it again with the second click event

I found time to investigate a bit into QT, and it is very interesting for me. However, right now I am encountering a problem that I am not aware about how to solve it. My aim is actually simple. I have a QCheckBox that I want to activate. If it is activated, I am starting a process (I am opening a file, reading it, taking some values out and change different labels accordingly). This process is repeated until the user is deactivating the QCheckBox. Some small code example to get a better idea of what I am going to do.
void Analyzer::on_actualTemperature_stateChanged(int arg1)
{
// Read data and change labels
if (arg1 != 0)
{
qDebug() << "Start data analysis";
// Infinity loop to get the data and display it
while true
{
// Open file and extract data
const actualTemperature = getData();
// Change any label or do something with the data
ui->anyLabel->setText(actualTemperature);
// Some break
QThread::sleep(1);
// Leave the loop if user deactivate the QCheckBox
// Something like on_actualTemperature_stateChange == 0
}
}
// Stop reading the data
else
{
qDebug() << "Stop data analysis";
}
}
It is obvious that after activating the QCheckBox, the loop will not finish at all and the GUI will not recognize anything anymore. Hence, I guess I have to start some new thread and have to kill it. However, I have no idea how to proceed here. An idea would be:
void Analyzer::on_actualTemperature_stateChanged(int arg1)
{
// Read data and change labels
if (arg1 != 0)
{
// Start reading the file and updating the label using some other thread
startThread(XY);
}
// Stop reading the data
else
{
// Kill thread 1234
killThread(XY);
}
}
Any hint is warmly welcomed and I hope this question is not too basic for you. Thank you for reading, Tobi.
I think killing a running thread is not a decent behavior. Let's be gentle to our threads with a loop control variable. In this example it named keepLoop. Set keepLoop when checkbox checked. Then start thread if it is not running. We are using QtConcurrent::run, and monitoring it by a QFuture in this case.
connect(ui->checkBox, &QCheckBox::toggled,
[&](const bool checked) {
analyzer->keepLoop = checked;
if (checked && !future.isRunning())
future = QtConcurrent::run(analyzer, &Analyzer::on_actualTemperature_stateChanged);
}
);
Don't call user interface slots directly, instead connect them to signals. Connections will be queued connection when signals emitted from another thread. It means slots will be called in event loop of main thread and changes will be shown when the next frame painted.
connect(analyzer, &Analyzer::temperatureCalculated, ui->anyLabel, &QLabel::setText);
Our asynchronous function does not forced to die immediately when user toggle checkbox. Instead we letting it to finish the iteration it already on halfway through.
Analyzer::on_actualTemperature_stateChanged() {
while (keepLoop) {
// Open file and extract data
const QString& actualTemperature = getData();
// send data
emit temperatureCalculated(actualTemperature);
}
}
You can use atomic bool if you want a more precise loop control.
Bonus:
If you don't want to mess with threads, you can avoid GUI freezing by using QTimer to run your loop periodically in main thread.

setCurrentWidget applied after the end of a clicked signal

When I create slots by name with this kind of syntax:
on_<widgetname>_clicked();
If I want to display a particular widget Inside this function it won't display until it reaches the end of the function.
That is, when I create the following function:
void MyWindow::on_myWidget_clicked()
{
// the stackedWidget is composed of:
// page_1 with myWidget
// page_2
ui->stackedWidget->setCurrentWidget(ui->page_2);
waitSomeTime();
}
whith
void MyWindow::waitSomeTime()
{
QThread t;
t.sleep(2); // Wait 2 seconds to see which line is going to be executed first.
}
When the code is launched, the 2 seconds elapsed first and only then the page_2 is displayed.
Why the line
ui->stackedWidget->setCurrentWidget(ui->page_2);
is not executed first?
void QThread::sleep(unsigned long secs) [static]
Forces the current thread to sleep for secs seconds.
the waitSomeTime function make the main (current) thread sleep, so it will block everything, even GUI processing. As #scopchanov commented, you could use QApplication::processEvents(), which will process the event of setCurrentWidget. However, the whole GUI will still be blocked until the sleep is done, which means, that the widget will be shown, but won't be able to handle any operation.
So it would be better to use QTimer::singleShot if you want to delay the work, or start another new QThread to do it.

refresh label not working correctly javafx

I have a problem with a refresh on a Label.
I have an function like this :
public void majMontantPaye(Double montantPaye) {
System.out.println("montant paye : "+montantPaye);
setMontantPaye(this.montantPaye+montantPaye);
Platform.runLater(() -> labelMontantPaye.setText(String.format("%.2f", this.montantPaye)+Messages.getMessage("0052")));
}
And My function is call by an API. This API communicate with a machine who allow to insert coin. And my function must to show the sum insert in the machine.
The problem is, when I insert a lot of coin in the same time in the machine, my function is correctly call every coin detected, so the System.out.println("montant paye : "+montantPaye); is correctly show every coin detected, BUT the Label "labelMontantPaye" is not refresh to every coin detected. Just on finish with the total sum.
I guess that the UI is not correctly refresh but I don't know how refresh correctly my Label.
Help please and sorry for mistake, i'm french.
You can follow the logic below:
As mentioned in the comments:
Using Platform.runLater(...) you queue the task into the JavaFXThread. But when you have many "events" you will only see the last result. (And maybe previous ones for a short time).
🍄Use a BlockingQueue to store each coin that is inserted.Use the method below(also have a look at the tutorial for the available methods,here i am using put which is blocking the current thread if a maximum of coins are inserted into the Queue,if you don't want this set the maximum to something like 500.000):
public void insertCoin(//maybe the kind of coin){
//add the coin into the BlockingQueue
blockingQueue.put(//coin);
}
Use a Thread which is running an infinity loop.The Thread is waking up
every time a new coin is inserted and when that is done , that Thread
waits JavaFXThread to refresh the Label Text:
new Thread(() -> {
//Run an infinity Thread
while (true) {
// Blocks until the queue has really any coins inserted
blockingQueue.get();
// Synchronize with javaFX thread
CountDownLatch latch = new CountDownLatch(1);
Platform.runLater(() -> {
label.setText(....);
latch.countDown();
});
// Block the Current Thread until the text is refreshed from
// JavaFX Thread
latch.await();
}
}).start();

showEvent() called more than once - Intentional?

What I want to do is display a set of pages setting up a test. Once all the details are correct the user presses Commit and the next wizard page is displayed that I want to immediately run a series of tests in. Displaying those to the user and once complete the user can then click Next.
I know to disable Next is simply a case of returning false on isComplete() and that is implemented okay. So, I want to use the function that is called just after the widget is displayed and so I used showEvent() which was indicated to me as the function to use.
At the moment my test is just displaying a progress bar as a test hence using a timer.
void RunTestWizardPage::showEvent(QShowEvent *event)
{
ui->statusEdit->setText("Running Tests");
timer = new QTimer(this);
connect(timer, SIGNAL(timeout()), this, SLOT(update()));
timer->start(100);
}
void RunTestWizardPage::update()
{
static int i = 10;
ui->statusEdit->append("Running Tests...");
ui->testProgress->setValue(i++);
if(i == 100)
{
i = 0;
timer->stop();
complete = true;
emit completeChanged();
}
}
However this function appears to be called twice (and I think before the widget display although that may be a trick of my debugging) and as such it causes issues with the timer I think as the timer never ends. I did read in the docs about spontaneous events but from what I can see both calls to the function are not spontaneous.
Is it being called twice intentional and if so how do I stop it or is there another function to use?
Thanks!
There is QWizardPage::initializePage() which is called just before showing the page.

Qt: How to delay a program while QTimer is active?

Please refer to the following link as I tried to simplify the problem I was having and now have run into a problem that I cannot solve.
Link: Qt: How to use QTimer to print a message to a QTextBrowser every 10 seconds?
In the posting for the link above I simplified the task I am trying to do by simply saying that I wanted to push a button and have it display something in a QTextBrowser every 10 seconds. I was having trouble getting QTimer working at the time so I thought that if I could get QTimer to work then I could finish my task.
What I am really trying to do is read lines from a file and after every 2500 lines I would like to print a message and then wait 10 seconds.
Pseudocode:
while(not at the end of the file)
{
read in 2500 lines
print a message
wait 10 seconds
}
QTimer is nice but it does opposite of what I want it to do. Instead of transmitting a message and waiting 10 seconds, first they wait 10 seconds, timeout and then send the message.
So to get it to work the way I want I first called the printMessage() SLOT and then I made a SLOT called stopTimer() that simply stops the timer. So after the 10 seconds has passed it will simply call stopTimer() and then continue processing the input file.
Onto the REAL problem:
Qt does not wait for a QTimer to finish before it moves on through the code. I want the code to wait the full 10 seconds before it reads the next 2500 lines of code. I found that QTimer has an isActive() function that returns a bool value.
So in the place where I wanted the 10 second delay to finish I put the following:
while(timer->isActive());
I figured the program would stay in this loop for 10 seconds and then exit after the QTimer timed out because the condition would then be false. The problem is that it doesn’t exit the loop because the status of the timer never changes regardless of how long it waits in this loop! I checked with the debugger and isActive( ) remains true regardless of elapsed time.
I then omitted the while(timer->isActive()) loop and observed the timer in the debugger. It seems that the timer does not actually start timing until it exits the while(not at the end of the file). So I believe that since the while(timer->isActive()) loop is nested inside this, it is causing it to never timeout. I could be wrong but this is what seems like is happening. Also, what is annoying is that the QTimer object has no field that shows the elapsed time of the timer when it is active. Therefore, I cannot check the elapsed time at all to further debug.
Someone please test this out or let me know a workaround for this!
For something that sounds so easy, this has been the biggest pain I have had in recent time, but I generally don’t use Qt so it could be my lack of experience.
Here is an excerpt from code I have which currently freezes as stated above:
void Form::startBtn_pushed()
{
QTimer *timer = new QTimer(this);
QFile file(“file.txt”);
QTextStream stream(&file);
QString line;
int lineCount = 0;
connect(timer, SIGNAL(timeout()), this, SLOT(stopTimer()));
while(!(stream.atEnd())
{
line = stream.readLine();
lineCount++;
if(lineCount == 2500)
{
printMessage();
timer->start(10000);
while(timer->isActive()); //Wait for timer to timeout before continuing
}
}
}
Sorry for the long post and if I might have made any grammatical errors with my code here. I do not have internet access on my dev machine so I had to retype this here.
Doing something like while(timer.isActive()) is not a good idea at all as it will cause your application to consume around 100% CPU time. It will also cause your application to never return to the event processing loop where the actual code for timer is executed, that's why it freezes.
If you still want to use this approach, you should call QCoreApplication::processEvents() in the loop. It will temporarily pass control back to the event loop, so it will cause timer to time out. Instead of connecting timeout() to stopTimer(), you can just call timer.setSingleShot(true) before you start it, it will cause it to stop automatically after the first timeout.
Note that you have a memory leak there as you create a new timer on each button push. Surely they are children of your form and will be destroyed, but only when the form is destroyed.
If you want a more elegant approach, you can create a separate class for reading that file. In the constructor you'd open your file and stream which should be fields in this class. This class should also have a sort of readMore() slot which will read 2500 lines, then put a message and return. If it doesn't reach the end of the stream, then it would call QTimer::singleShot(10000, this, SLOT(readMore())), which will cause the event loop to call readMore() again in 10 seconds. The code would looks something like this (didn't check for errors):
// myfilereader.h
class Form;
class MyFileReader: public QObject {
Q_OBJECT
public:
MyFileReader(const QString &fileName);
// this should be called after you create an instance of MyFileReader
void startReading() {readMore();}
private:
QFile file;
QTextStream stream;
private slots:
void readMore();
signals:
void message(); // this should be connected to printMessage() in the Form
void finished();
};
// myfilereader.cpp
MyFileReader::MyFileReader(const QString &fileName):
file(fileName),
stream(&file),
{
// open the file, possibly throwing an exception
// or setting some sort of "invalid" flag on failure
}
void MyFileReader::readMore()
{
QString line;
int lineCount = 0;
while(!(stream.atEnd())
{
line = stream.readLine();
lineCount++;
if(lineCount == 2500)
{
emit message();
break;
}
}
if (stream.atEnd())
emit finished();
else
QTimer::singleShot(10000, this, SLOT(readMore()));
}
This is a kind of more heavyweight approach, but this is the price of asynchronous event handling. You could also put all this stuff into the Form class, but I think using a separate class is better.
As Daniel points out, if reading 2500 lines takes a long time, say 5 seconds, the message will be printed after 10 seconds after the reading has finished, that is, 15 seconds after it has started. If you want the message to be printed approximately each 10 seconds no matter how long reading takes, you should add a QTimer timer field to the class, connect it's timeout() signal to the readMore() slot in the MyFileReader constructor, then in the startReading() method call timer.start() before calling readMore(). Now, at the end of readMore() do this:
if (stream.atEnd()) {
timer.stop();
emit finished();
}
You need a QTimer field in this case because you can't cancel a QTimer::singleShot() call, but you need to do it if you have reached the end of the stream, otherwise your readMore() will just keep on getting called again and again, even if there is nothing more to read. Note that even in this case, it is still possible for the message to appear less frequently than every 10 seconds in case if reading 2500 lines takes longer than these 10 seconds. If you want exactly 10 seconds, you should probably check the elapsed time in the loop instead, but I think that's an overkill, unless you expect reading to be very slow.
Slightly off topic, but if you want an easy way to avoid memory leaks, you can also do this in the constructor:
connect(this, SIGNAL(finished()), this, SLOT(deleteLater()));
It will automatically mark your reader for deletion when you emit finished(), and, once that happens, the reader will be deleted as soon as the control goes back to the event loop. That is, after all slots connected to the finished() signal return. This approach allows you to just allocate a MyFileReader on the heap, then discard the pointer without worrying about memory leaks.
QTimer has a signal called timedout(). If you connect a slot to this, you can set the initial timer to a REALLY short interval (1 MS maybe). When the timer expires, inside the slot, you can send your message. At the end of the slot, set the interval to 10 seconds, set singleshot to false, and the start the timer again.
If you don't want to do the setting each and every time the slot is called, you can simply make 2 slots. The first time, the slot does the setup for the rest of the calls. It also disconnects itself from the QTimer and connects the second slot. Then things continue merrily on their way.
Edit:
Also, realize that when slots are called they are called on the event thread. So, by clicking a button and putting a loop that spin-blocks/busy-waits until the timer expires, you are guaranteeing that you will not enter this state because you are blocking the very thread that the timeout signal will be processed on.
QTimer does all of its processing inside Qt's event loop, so your code must return to the event loop to cause the timer to time out. So what you want to do is have startBtn_pushed set up the timer, connect a slot to the timer's timeout signal, then probably call that slot itself (so that it is called immediately). It would look something like this:
// timer, file, and stream are now instance variables (or maybe file and stream
// are broken out into their own class... up to you.
void Form::startBtn_pushed()
{
// timer has been allocated before (but not started)
file.open(“file.txt”);
stream.setDevice(&file);
connect(timer, SIGNAL(timeout()), this, SLOT(readAndPrint()));
timer->start(10000);
readAndPrint(); // respond to the button press immediately
}
void Form::readAndPrint()
{
int lineCount = 0;
while(!(stream.atEnd() && lineCount < 2500)
{
line = stream.readLine();
lineCount++;
if(lineCount == 2500)
{
printMessage();
}
}
}
I have figured out a solution that is much simpler than those proposed here.
I realized it was much easier to use a QTime object instead of a QTimer object.
Basically you start a QTime object and then you use its elapsed() function to check how much time has passed to since it was started.
Thanks to everyone for taking the time to help. I did try to implement a couple of your solutions into my code but had some trouble since I am not a pro at Qt and they were more complex than I would have thought. In the end I find this solution to be a easy solution to what should have been an easy problem.
I certainly learned a lot from this problem and I hope you all did too.
My question to you is why didn't anyone suggest using QTime from the start?
Thanks again!
My solution:
void Form::startBtn_pushed()
{
QTime *timer = new QTime();
QFile file(“file.txt”);
QTextStream stream(&file);
QString line;
int lineCount = 0;
connect(timer, SIGNAL(timeout()), this, SLOT(stopTimer()));
while(!(stream.atEnd())
{
line = stream.readLine();
lineCount++;
if(lineCount == 2500)
{
timer->start();
while(1)
{
QApplication::processEvents();
if(timer->elapsed() == 10000)
{
printMessage();
break;
}
}
}
}
}
QEventLoop l;
connect( timer, SIGNAL( timeout() ), &l, SLOT( quit() ) );
l.exec(); // Waiting without freezing ui

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