Bitbucket Rest API for getting Repo names under a Project - bitbucket-api

Question

I'm trying to get the repo names under a Project using the Bitbucket API. The current link on the documentation says to use
curl -u username:pwd http://${bitbucket-url}/rest/api/1.0/projects/${projectkey}/repos/
Response:
{
"size": 1,
"limit": 25,
"isLastPage": true,
"values": [
{
"slug": "my-repo",
"id": 1,
"name": "My repo",
"scmId": "git",
"state": "AVAILABLE",
"statusMessage": "Available",
"forkable": true,
"project": {
"key": "PRJ",
"id": 1,
"name": "My Cool Project",
"description": "The description for my cool project.",
"public": true,
"type": "NORMAL",
"links": {
"self": [
{
"href": "http://link/to/project"
}
]
}
},
"public": true,
"links": {
"clone": [
{
"href": "ssh://git#/PRJ/my-repo.git",
"name": "ssh"
},
{
"href": "https:///scm/PRJ/my-repo.git",
"name": "http"
}
],
"self": [
{
"href": "http://link/to/repository"
}
]
}
}
],
"start": 0
}
But I only need the repo name from the response

Answer 1

from subprocess import call
import configparser
import subprocess
import json
import os
base_dir = os.getcwd()
DETACHED_PROCESS = 0x00000008
cmd = 'curl --url "' + bb_url + '?pagelen=100&page=' + str(page) + '" --user ' + bb_user + ':' + bb_pwd + ' --request GET --header "Accept: application/json"'
output = subprocess.Popen(cmd, stdout=subprocess.PIPE, stderr=subprocess.PIPE, creationflags=DETACHED_PROCESS).communicate()
datastore = json.loads(output[0].decode("utf-8"))
size = datastore.get("size")
values = datastore.get("values")
if(len(values)) == 0:
break
for repos in range(size):
repo_name = values[repos]["values"]["slug"]
f_initial = open (base_dir+"\\repositoryList.txt", "a+")
f_initial.write(repo_name)
f_initial.write("\n")
f_initial.close()
page = page + 1
This script will help you get the list of all the repositories in your project and write it under the file repositoryList.txt

Answer 2

With bash command
repoNamesJson=$(curl -D- -X GET -H "Authorization: Basic <encoded user pasword here>" -H "Content-Type: application/json" https://yourstash/rest/api/1.0/projects/ad/repos?limit=100000)
repoNames=$(echo $repoNamesJson | awk -v RS=',' '/{"slug":/ {print}' | sed -e 's/{"slug":/''/g' | sed -e 's/"/''/g')
echo $repoNames
With python-stash library
import stashy
bitbucket = stashy.connect("host", "username", "password")
projects = bitbucket.projects.list()
repos = bitbucket.repos.list()
for project in projects:
for repo in bitbucket.projects["%s" % (project["key"])].repos.list():
print(repo["name"])
print(repo["project"]['key'])

Answer 3

You can use BitBucket API partial responses in order to limit the fields returned by the API.
Taking excerpts from the doc page:
[...] use the fields query parameter.
The fields parameter supports 3 modes of operation:
Removal of select fields (e.g. -links)
Pulling in additional fields not normally returned by an endpoint, while still getting all the default fields (e.g. +reviewers)
Omitting all fields, except those specified (e.g. owner.display_name)
The fields parameter can contain a list of multiple comma-separated field names (e.g. fields=owner.display_name,uuid,links.self.href). The parameter itself is not repeated.
So in your case would be something like:
curl -u username:pwd
http://${bitbucket-url}/rest/api/1.0/projects/${projectkey}/repos?fields=values.slug
Though I must say that the JSON output is not flat, it will still retain its original structure:
{
"values": [
{
"slug": "your repo slug #1"
},
...
So, if you actually want only a list with each repo slug on its own line, there's still some leg work to do.