Returning multiple values from one step using 'select', 'by' in Gremline - gremlin

Question

My graph schema looks like this:
(Location)<-[:INVENTOR_LOCATED_IN]-(Inventor)-[:INVENTOR_OF]->(Patent)
I'm trying to return multiple values from each step in the query path. Here's the query I have so far that runs correctly:
g.V().and(has('Location', 'city', textContains('Bloomington')), has('Location','state',textContains('IN'))).as('a').
bothE().bothV().hasLabel('Inventor').as('b').
bothE().bothV().has('Patent', 'title', textContains('Lid')).as('c').
select('a,', 'b', 'c').
by('state').by('name_first').by('title').
fold();
What I would like to do is for each step return two node properties. I tried the following but it returns an error:
g.V().and(has('Location', 'city', textContains('Bloomington')), has('Location', 'state',textContains('IN'))).as('a').
bothE().bothV().hasLabel('Inventor').as('b').
bothE().bothV().has('Patent', 'title', textContains('Lid')).as('c').
select('a,', 'b', 'c').
by('city', 'state').by('name_first', 'name_last').by('title', 'abstract').
fold();
Can anyone suggest syntax that will allow me to return multiple properties from each node in the path?

Answer 1

The by(key) is meant to be a sort of shorthand for values(key) which means if you have more than one value you could do:
g.V().and(has('Location', 'city', textContains('Bloomington')), has('Location', 'state',textContains('IN'))).as('a').
bothE().bothV().hasLabel('Inventor').as('b').
bothE().bothV().has('Patent', 'title', textContains('Lid')).as('c').
select('a,', 'b', 'c').
by(values('city', 'state').fold()).
by(values('name_first', 'name_last').fold()).
by(values('title', 'abstract').fold()).
fold()
You might also consider forms of elementMap(), valueMap(), or project() as alternatives. Since by() takes a Traversal you have a lot of flexibility.