Robot Framework - run keyword if file exists - robotframework

Question

How can you run keywords in the robot framework if the file exists in the filesystem?
For example:
Run Keyword If ${filename} exists Delete File

Answer 1

OperatingSystem library could be used for this, even though there's not exactly any keyword for what you need. But you can get creative and perhaps use Get File, Get File Size, List Files In Directory, Run And Return Rc or even something else. There are also keywords like File Should Exist, File Should Not Exist, Should Exist. Perhaps you can change your code so you can use these.
Or you create your own simple library:
Libraries/file.py
import os
def file_exists(file):
return os.path.isfile(file)
import it and use it like you mentioned in your question:
Tests/test.robot
*** Settings ***
Library ../Libraries/file.py
*** Test Cases ***
Test File Exists
${fileExists}= File Exists test.robot
Run Keyword If ${fileExists} is True Log To Console Exists!

Answer 2

When I need this kind of action, I code something like that... maybe can work for you.
*** Settings ***
Library Process
*** Variables ***
#{FILES} ${CURDIR}/someFolder/aaa.pdf
... ${CURDIR}/someFolder/bbb.pdf
*** Test Cases ***
Check and Delete Files
FOR ${file} IN #{FILES}
${out} = run process ls ${file}
run keyword if ${out.rc} == 0 Delete File ${file}
END
*** Keywords ***
Delete File
[Arguments] ${f}
${o} = run process rm -f ${f}
Should Be Equal As Integers ${o.rc} 0

Answer 3

Get the File status and then use the status as
${file_exists}= Run Keyword and Return Status File Should Exist test.robot
IF ${file_exists}
Log File Exists
END