How do I check what module an object is defined in? - julia

If I have an object (say a method, or a struct, or a Type, imported with using), how can I get the module it was originally defined in?

You can use the parentmodule function. For example:
julia> parentmodule(rand)
Base
julia> parentmodule(versioninfo)
InteractiveUtils

Related

Is there a way to forcefully use a hidden default constructor in Julia?

I want to serialize and deserialize Julia objects from an external package. Some of these objects only have restricted inner constructors, like in the following example:
module ExternalModule
struct SillyType
f::Float64
function SillyType(i::Int)
new(float(i))
end
end
end
To reconstruct objects/structs from the stored values (here, to reconstruct the SillyType using a float), I need to call the default constructor, which is not available:
julia> ExternalModule.SillyType(2.0)
ERROR: MethodError: no method matching Main.ExternalModule.SillyType(::Float64)
The Julia documentation says
If any inner constructor method is defined, no default constructor
method is provided: it is presumed that you have supplied yourself
with all the inner constructors you need.
Is there a way around this to somehow forcefully call the missing default constructor? And what would be the least dirty approach for this?
I think the new function inside the inner constructor of SillyType is what you want to call? It is normally only allowed in inner constructors, but if you forge it using macros, it will still run. Try this:
julia> macro new(args...)
return Expr(:new, args...)
end
#new (macro with 1 method)
julia> #new(SillyType, 4.)
SillyType(4.0)

Use case for `function foo end` function declaration?

A declaration like this one is legal:
julia> function foo end
foo (generic function with 0 methods)
However, besides a placeholder to centralize documentation (and I am not even sure):
module Foo
"""
foo(...) functions
- foo(n::Int) : do something
- foo(n::Int,m::Int) : do other thing
"""
function foo end
I can not see the role/goal of such declaration.
Question: is there an illustrative use case?
The reason is explained in the Julia Manual in Empty generic functions section. There are two main uses:
simplifying documentation or improvement of code readability;
separation of interface definition from implementations.
A typical use case can be seen for definitions of randn! and randexp!. First empty generic functions are defined and are coupled with documentation string. Next methods for those functions are dynamically defined.
Another similar example to study is definition randstring.
Finally look at strides function. It is defined in abstractarray.jl as empty generic function and then used in the same file. But no methods are defined for this function in this file, other files e.g. dense.jl or subarray.jl define such methods.

Given a function object, how do I find its name and module?

Given a function object f, how do I find:
Function's name.
Module(s) of its method(s)?
In Julia 0.4 I was able to find name using f.env.name, but no tips for module. For Julia 0.5 I wasn't able to find any of two.
Name is easy: Symbol(f) or string(f) if you want a string
Module is, as you know going to be per method (i.e per type signature).
methods(f) with return a method table that prints out all the methods and where they are, in terms of files.
You can do [meth.module for meth in methods(f)] to get there modules
So to use an example, the collect function.
julia> using DataStructures #so we have some non-Base definitions
julia> Symbol(collect)
:collect
julia> methods(collect)
# 5 methods for generic function "collect":
collect(r::Range) at range.jl:813
collect{T}(::Type{T}, itr) at array.jl:211
collect(itr::Base.Generator) at array.jl:265
collect{T}(q::DataStructures.Deque{T}) at /home/ubuntu/.julia/v0.5/DataStructures/src/deque.jl:170
collect(itr) at array.jl:236
julia> [meth.module for meth in methods(collect)]
5-element Array{Module,1}:
Base
Base
Base
DataStructures
Base
julia> first(methods(collect, (Deque,))).module
DataStructures
#oxinabox's answer is correct. To add, typeof(f).name.mt.name is the v0.5 replacement for f.env.name. That can be useful to avoid the . that occurs when just applying string to a function introduced in a non-stdlib module. There also exists Base.function_name(f) which is probably less likely to break when the Julia version changes.
To get the module that a function (type) is introduced in, rather than the modules of individual methods, there's typeof(f).name.module, or the probably-better version, Base.function_module(f). The module of the method table is probably the same; that can be obtained through typeof(f).name.mt.module.
Note that f.env in v0.4 is a direct equivalent of typeof(f).name.mt, so on v0.4 the same f.env.name and f.env.module apply.
In Julia 1.x the commands are:
Base.nameof
Base.parentmodule
Since this two methods are exported, also nameof and parentmodule works.
Not exactly the answer but closely related: you can find the file name and line number of f using functionloc(f)

How to display the definition of a function

This is probably a newbie question... but is it possible to show the definition of a (user defined) function? While debugging/optimizing it is convenient to quickly see how a certain function was programmed.
Thanks in advance.
You can use the #edit macro, which is supposed to take you to the definition of a method, similarly to how the #which macro which shows the file and line # where that particular method was defined, for example:
julia> #which push!(CDFBuf(),"foo")
push!{T<:CDF.CDFBuf}(buff::T, x) at /d/base/DA/DA.jl:105
julia> #which search("foobar","foo")
search(s::AbstractString, t::AbstractString) at strings/search.jl:146
Note that methods that are part of Julia will show a path relative to the julia source directory "base".
While this is not an automatic feature available with Julia in general (as pointed out by Stefan), if you add docstrings when you define your initial function, you can always use the help?> prompt to query this docstring. For example
julia> """mytestfunction(a::Int, b)""" function mytestfunction(a::Int, b)
return true
This attaches the docstring "mytestfunction(a::Int, b)" to the function mytestfunction(a::Int, b). Once this is defined, you can then use the Julia help prompt (by typing ? at the REPL), to query this documentation.
help?> mytestfunction
mytestfunction(a::Int, b)

Function signature not found despite showing with methods(...)

I am new to Julia, so this might be trivial.
I have a function definition within a module that looks like (using URIParser):
function add!(graph::Graph,
subject::URI,
predicate::URI,
object::URI)
...
end
Outside of the module, I call:
add!(g, URIParser.URI("http://test.org/1"), URIParser.URI("http://test.org/2"), URIParser.URI("http://test.org/1"))
Which gives me this error:
ERROR: no method add!(Graph,URI,URI,URI)
in include at boot.jl:238
in include_from_node1 at loading.jl:114
at /Users/jbaran/src/RDF/src/RDF.jl:79
Weird. Because when I can see a matching signature:
julia> methods(RDF.add!)
# 4 methods for generic function "add!":
add!(graph::Graph,subject::URI,predicate::URI,object::Number) at /Users/jbaran/src/RDF/src/RDF.jl:29
add!(graph::Graph,subject::URI,predicate::URI,object::String) at /Users/jbaran/src/RDF/src/RDF.jl:36
add!(graph::Graph,subject::URI,predicate::URI,object::URI) at /Users/jbaran/src/RDF/src/RDF.jl:43
add!(graph::Graph,statement::Statement) at /Users/jbaran/src/RDF/src/RDF.jl:68
At first I thought it was my use of object::Union(...), but even when I define three functions with Number, String, and URI, I get this error.
Is there something obvious that I am missing? I am using Julia 0.2.1 x86_64-apple-darwin12.5.0, by the way.
Thanks,
Kim
This looks like you may be getting bit by the very slight difference between method extension and function shadowing.
Here's the short of it. When you write function add!(::Graph, ...); …; end;, Julia looks at just your local scope and sees if add! is defined. If it is, then it will extend that function with this new method signature. But if it's not already defined locally, then Julia creates a new local variable add! for that function.
As JMW's comment suggests, I bet that you have two independent add! functions. Base.add! and RDF.add!. In your RDF module, you're shadowing the definition of Base.add!. This is similar to how you can name a local variable pi = 3 without affecting the real Base.pi in other scopes. But in this case, you want to merge your methods with the Base.add! function and let multiple dispatch take care of the resolution.
There are two ways to get the method extension behavior:
Within your module RDF scope, say import Base: add!. This explicitly brings Base.add! into your local scope as add!, allowing method extension.
Explicitly define your methods as function Base.add!(graph::Graph, …). I like this form as it more explicitly documents your intentions to extend the Base function at the definition site.
This could definitely be better documented. There's a short reference to this in the Modules section, and there's currently a pull request that should be merged soon that will help.

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