I want to query last 24h in my database SQLite. I have 2 rows time example (18:04:56) and date (2020-12-06 ). When I use this query
SELECT name,cdate,ctime, * FROM {table} WHERE cdate >= datetime('now','-1 day') ORDER BY id DESC
I got only last queries in the same day. (LAST QUERY 00:00:46)
How deal with it ?
You should create a datetime value from cdate and ctime to compare with DATETIME('now','-1 day'):
SELECT name, cdate, ctime
FROM {table}
WHERE (cdate || ' ' || ctime) >= DATETIME('now','-1 day')
ORDER BY id DESC
Related
I want to delete elements at today's date. But this statement doesn't work.
cur.execute("DELTE FROM medicine WHERE date DATE('now') AND DATE('now', '-1 day')")
try:
tree.delete(cur)
except IndexError:
pass
If the column's date format is YYYY-MM-DD then you need this statement:
DELETE FROM medicine WHERE date = DATE('now')
or:
DELETE FROM medicine WHERE date = CURRENT_DATE
I have a table 4 columns - Code, Status, EffectiveDate (EFF_DT), EndDate (END_DT). All the columns are Varchar2 type. EFF_DT and END_DT has ISO format date (YYYY-MM-DD) with NULL values for few rows. Need to get the rows which has END_DT greater than today's date.
While executing the below query, it returns all the Not NULL rows for END_DT. Do not compare the END_DT at all.
select code, status, EFF_DT, END_DT
from (
select CODE, EFF_DT, Status,to_date("END_DT" ,'YYYY-MM-DD' ) as END_DT
from xxx.ZZZ
) TAB
where to_date(TAB.END_DT ,'DD-MM-YY' ) > to_date(CAST(CURRENT_TIMESTAMP as Date), 'DD-MM-YY')
ORDER BY 1 ASC
But the below query compares the END_DT and returns the result properly -
SELECT "TAB"."CODE" , "TAB"."STATUS" AS "STATUS" , "TAB"."EFF_DT" , "TAB"."END_DT"
FROM xxx.ZZZ "TAB"
WHERE ( (to_date("TAB"."END_DT",'YYYY-MM-DD') > to_date(CAST(CURRENT_TIMESTAMP as Date), 'YY-MM-DD')) )
ORDER BY 1 ASC
What is going wrong with the 1st query?
I see difference in return value of END_DT.
For the 1st query, the data is coming like -
while as for the 2nd query, the data is coming like
i m trying like this:
char *Query = "DELETE FROM tablename WHERE starttime < NOW() - INTERVAL 1 DAY";
First,to delete last 2 days,you need to check data greater than the specified date,then you need to use DATE('now', '-1 days') to get the date,more details can be found at How to structure my query in sqlite?
DELETE FROM bandwidthmaster WHERE starttime > DATE('now', '-1 days');
I'm doing a query to return the number of count records for a certain date.
The problem is when I use the GroupBy by a certain day, If the date have no records then the date for that day will not be shown in the output.
How can I achieve that?
I'm doing something like:
SELECT COUNT(History.Id)
FROM History
INNER JOIN User ON User.Id = History.UserId
WHERE (#StartDate = #NullDate OR History.CreatedOnDate >= #StartDate)
AND (#EndDate = #NullDate OR History.CreatedOnDate <= #EndDate)
GROUP BY History.CreatedOnDat
Example
01-08, 3 records
02-08, 2 records
04-08, 5 records
I need to have 03-08 with 0 records.
Create a temp table with one day per row:
Declare #StartDate datetime = '2016-08-01'
Declare #EndDate datetime = '2016-08-31'
declare #temp table
(
oneday datetime
);
WHILE #StartDate <= #EndDate
begin
INSERT INTO #temp VALUES (#StartDate);
SET #StartDate = Dateadd(Day,1, #StartDate);
end
select * from #temp
Then, simply join your query with this temp table.
How can I select data from a table based on weekday or weekend, like
if date is a weekday then select only historical weekday data from the table &
if date is a weekend then select only historical weekend data.
I have tried to do that in this way but no luck
DECLARE #MyDate DATE = '08/17/2013'
SELECT datename(dw,#MyDate)
SELECT * FROM MyTable
WHERE
datename(dw,DateColumnInTable) IN (
CASE WHEN (datename(dw,#MyDate) IN ('Saturday','Sunday')) THEN '''Saturday'',''Sunday'''
ELSE 'Monday'',''Tuesday'',''Wednesday'',''Thursday'',''Friday'
END )
Any I can see lots of data in my table for saturday and sunday but this query is giving me blank record set.
Here's one way:
DECLARE #MyDate DATE = '08/17/2013'
IF (DATEPART(weekday, #MyDate) IN (1,7))
SELECT *
FROM MyTable
WHERE DATEPART(weekday, DateColumnInTable) IN (1,7)
ELSE
SELECT *
FROM MyTable
WHERE DATEPART(weekday, DateColumnInTable) BETWEEN 2 AND 6
If you would like to do it in one clause you can do something like the following, but it may perform worse:
SELECT *
FROM MyTable
WHERE (DATEPART(weekday, #MyDate) IN (1,7) AND DATEPART(weekday, DateColumnInTable) IN (1,7))
OR (DATEPART(weekday, #MyDate) BETWEEN 2 AND 6 AND DATEPART(weekday, DateColumnInTable) BETWEEN 2 AND 6)