How can I select data from a table based on weekday or weekend, like
if date is a weekday then select only historical weekday data from the table &
if date is a weekend then select only historical weekend data.
I have tried to do that in this way but no luck
DECLARE #MyDate DATE = '08/17/2013'
SELECT datename(dw,#MyDate)
SELECT * FROM MyTable
WHERE
datename(dw,DateColumnInTable) IN (
CASE WHEN (datename(dw,#MyDate) IN ('Saturday','Sunday')) THEN '''Saturday'',''Sunday'''
ELSE 'Monday'',''Tuesday'',''Wednesday'',''Thursday'',''Friday'
END )
Any I can see lots of data in my table for saturday and sunday but this query is giving me blank record set.
Here's one way:
DECLARE #MyDate DATE = '08/17/2013'
IF (DATEPART(weekday, #MyDate) IN (1,7))
SELECT *
FROM MyTable
WHERE DATEPART(weekday, DateColumnInTable) IN (1,7)
ELSE
SELECT *
FROM MyTable
WHERE DATEPART(weekday, DateColumnInTable) BETWEEN 2 AND 6
If you would like to do it in one clause you can do something like the following, but it may perform worse:
SELECT *
FROM MyTable
WHERE (DATEPART(weekday, #MyDate) IN (1,7) AND DATEPART(weekday, DateColumnInTable) IN (1,7))
OR (DATEPART(weekday, #MyDate) BETWEEN 2 AND 6 AND DATEPART(weekday, DateColumnInTable) BETWEEN 2 AND 6)
Related
I want to query last 24h in my database SQLite. I have 2 rows time example (18:04:56) and date (2020-12-06 ). When I use this query
SELECT name,cdate,ctime, * FROM {table} WHERE cdate >= datetime('now','-1 day') ORDER BY id DESC
I got only last queries in the same day. (LAST QUERY 00:00:46)
How deal with it ?
You should create a datetime value from cdate and ctime to compare with DATETIME('now','-1 day'):
SELECT name, cdate, ctime
FROM {table}
WHERE (cdate || ' ' || ctime) >= DATETIME('now','-1 day')
ORDER BY id DESC
i m trying like this:
char *Query = "DELETE FROM tablename WHERE starttime < NOW() - INTERVAL 1 DAY";
First,to delete last 2 days,you need to check data greater than the specified date,then you need to use DATE('now', '-1 days') to get the date,more details can be found at How to structure my query in sqlite?
DELETE FROM bandwidthmaster WHERE starttime > DATE('now', '-1 days');
I'm doing a query to return the number of count records for a certain date.
The problem is when I use the GroupBy by a certain day, If the date have no records then the date for that day will not be shown in the output.
How can I achieve that?
I'm doing something like:
SELECT COUNT(History.Id)
FROM History
INNER JOIN User ON User.Id = History.UserId
WHERE (#StartDate = #NullDate OR History.CreatedOnDate >= #StartDate)
AND (#EndDate = #NullDate OR History.CreatedOnDate <= #EndDate)
GROUP BY History.CreatedOnDat
Example
01-08, 3 records
02-08, 2 records
04-08, 5 records
I need to have 03-08 with 0 records.
Create a temp table with one day per row:
Declare #StartDate datetime = '2016-08-01'
Declare #EndDate datetime = '2016-08-31'
declare #temp table
(
oneday datetime
);
WHILE #StartDate <= #EndDate
begin
INSERT INTO #temp VALUES (#StartDate);
SET #StartDate = Dateadd(Day,1, #StartDate);
end
select * from #temp
Then, simply join your query with this temp table.
I am developing one chart in that chart I want to show last six month's details separately.
I want to show the details in bar chart.
But I am not getting the any solution.
I am bit weak in sql queries.
Till now I got the data for last month.
But I want the data for last six month.
here's my code.
DECLARE #StartDate DATETIME, #EndDate DATETIME
SET #StartDate = DATEADD(mm, DATEDIFF(mm,0,getdate())-1, 0)
SET #EndDate = DATEADD(mm, 1, #StartDate)
SELECT sum(quantity)
FROM RS_Sell_Order_Master as s
left outer join RS_Sell_Order_Mapping as sm on sm.sell_order_no = s.sell_order_no
left outer join RS_GIN_Master as GIN on gin.product_id = sm.product_id
WHERE del_date BETWEEN #StartDate AND #EndDate
I want o/p of last six month like this suppose I have sell 10 quantity last month & 20 prevous to that month & I didnt sell before that So o/p should be
null
null
null
null
10
20
some thing like this.
This will assign a date exactly 6 months ago - there doesn't seem to be a reason why you would need to go back to the zero datum of SqlServer's DATETIME:
SET #StartDate = DATEADD(mm, -6, CURRENT_TIMESTAMP);
Edit
Assuming that you want month's aligned from the first to the end of each month,
and assuming because you have nulls but still want to show data that we will need to manufacture the missing months (e.g. with a recursive CTE)
DECLARE #StartDate DATETIME;
SET #StartDate = DATEADD(mm, -6, CURRENT_TIMESTAMP);
WITH cte AS
(
SELECT 0 AS TheMonth
UNION ALL
SELECT TheMonth + 1
FROM cte
WHERE TheMonth < 5
)
SELECT sum(quantity)
FROM
cte
LEFT OUTER JOIN RS_Sell_Order_Master as s
ON del_date >= DATEADD(MM, cte.TheMonth, #StartDate) AND del_date < DATEADD(MM, cte.TheMonth + 1, #StartDate)
-- Other Joins here
GROUP BY cte.TheMonth
ORDER BY cte.TheMonth;
SqlFiddle here
total no of items per month can be calculated like
select sum(items),left(date,6)+'01' from yourTable
group by left(date,6)
assuming your date is in 112 format....and it is of varchar(8) type..
I need some help to build SQL Query. I have table having data like:
ID Date Name
1 1/1/2009 a
2 1/2/2009 b
3 1/3/2009 c
I need to get result something like...
1 1/1/2009 a
2 1/2/2009 b
3 1/3/2009 c
4 1/4/2009 Null
5 1/5/2009 Null
6 1/6/2009 Null
7 1/7/2009 Null
8 1/8/2009 Null
............................
............................
............................
30 1/30/2009 Null
31 1/31/2009 Null
I want query something like..
Select * from tbl **where month(Date)=1 AND year(Date)=2010**
Above is not completed query.
I need to get all the record of particular month, even if some date missing..
I guess there must be equi Join in the query, I am trying to build this query using Equi join
Thanks
BIG EDIT
Now understand the OPs question.
Use a common table expression and a left join to get this effect.
DECLARE #FirstDay DATETIME;
-- Set start time
SELECT #FirstDay = '2009-01-01';
WITH Days AS
(
SELECT #FirstDay as CalendarDay
UNION ALL
SELECT DATEADD(d, 1, CalendarDay) as CalendarDay
FROM Days
WHERE DATEADD(d, 1, CalendarDay) < DATEADD(m, 1, #FirstDay)
)
SELECT DATEPART(d,d.CalendarDay), **t.date should be (d.CalendarDay)**, t.Name FROM Days d
LEFT JOIN tbl t
ON
d.CalendarDay = t.Date
ORDER BY
d.CalendarDay;
Left this original answer at bottom
You need DATEPART, sir.
SELECT * FROM tbl WHERE DATEPART(m,Date) = 1
If you want to choose month and year, then you can use DATEPART twice or go for a range.
SELECT * FROM tbl WHERE DATEPART(m,Date) = 1 AND DATEPART(yyyy,Date) = 2009
Range :-
SELECT * FROM tbl WHERE Date >= '2009-01-01' AND Date < '2009-02-01'
See this link for more info on DATEPART.
http://msdn.microsoft.com/en-us/library/ms174420.aspx
You can use less or equal to.
Like so:
select * from tbl where date > '2009-01-01' and date < '2009-02-01'
However, it is unclear if you want month 1 from all years?
You can check more examples and functions on "Date and Time Functions" from MSDN
Create a temporary table containing all days of that certain month,
Do left outer join between that table and your data table on tempTable.month = #month.
now you have a big table with all days of the desired month and all the records matching the proper dates + empty records for those dates who have no data.
i hope that's what you want.