I'm using the excellent Julia Mat File reader to read a mat file with the structure similar to test2
Dict1 = Dict("a" => [1,3], "b" => 2, "c" => "Hello")
test2=Dict("test"=>Dict1,"a"=>[2,4])
With the read command I can access Dict1 like this:
using MAT
read(file, "test")
But I'd also like to access variables within Dict1, like "a" or "b".
Any suggestions?
Thanks!
dict_1 = Dict("a" => [1,3], "b" => 2, "c" => "Hello")
dict_2 = Dict("test" => dict_1, "a" => [2,4])
#show dict_2["test"]["b"]
I have two dicts and I want to subtract the matching values from the two dicts to generate a third dict.
A = Dict("w" => 2, "x" => 3)
B = Dict("x" => 5, "w" => 7)
# Ideally I could go B .- A and get a dict like
C = Dict("w" => 5, "x" => 2)
# but I get ERROR: ArgumentError: broadcasting over dictionaries and `NamedTuple`s is reserved
One ugly solution is to overload the subtraction operator but I am not keen to overload for a builtin type like dict for fear of breaking other code.
import Base.-
function -(dictA::Dict, dictB::Dict)
keys_of_A = keys(dictA)
subtractions = get.(Ref(dictB), keys_of_A, 0) .- get.(Ref(dictA), keys_of_A, 0)
return Dict(keys_of_A .=> subtractions)
end
Is there a cleaner way to do algebraic operations on matching values from different dicts?
merge provides the result you want.
A = Dict("w" => 2, "x" => 3)
B = Dict("x" => 5, "w" => 7)
C = merge(-, B, A)
Dict{String,Int64} with 2 entries:
"w" => 5
"x" => 2
Note that merge performs a union of the two collections and combines common keys by performing the given operation. So, for example:
W = Dict("w" => 4)
merge(-, B, W)
Dict{String,Int64} with 2 entries:
"w" => 3
"x" => 5
haskey() and in() functions are very useful to test the content of dictionaries in Julia :
julia> dict = Dict("a" => 1, "b" => 2, "c" => 3, "d" => 4, "e" => 5)
Dict{String,Int64} with 5 entries:
"c" => 3
"e" => 5
"b" => 2
"a" => 1
"d" => 4
julia> haskey(dict, "a")
true
julia> in(("a" => 1), dict)
true
but I was surprised by their behavior with complex keys :
julia> immutable MyT
A::String
B::Int64
end
julia> a = Dict(MyT("Tom",191)=>1,MyT("Bob",20)=>1,MyT("Jo",315)=>1,MyT("Luc",493)=>1)
Dict{MyT,Int64} with 4 entries:
MyT("Tom",191) => 1
MyT("Jo",315) => 1
MyT("Bob",20) => 1
MyT("Luc",493) => 1
julia> keys(a)
Base.KeyIterator for a Dict{MyT,Int64} with 4 entries. Keys:
MyT("Tom",191)
MyT("Jo",315)
MyT("Bob",20)
MyT("Luc",493)
julia> haskey(a, MyT("Tom",191))
false
julia> in((MyT("Tom",191) => 1), a)
false
What I did wrong ?
Thank you very much for your comments !
Thanks to #Michael K. Borregaard, I can propose this solution :
a = Dict{MyT, Int64}()
keyArray = Array{MyT,1}()
keyArray = [MyT("Tom",191),MyT("Bob",20),MyT("Jo",315),MyT("Luc",493)]
for i in keyArray
a[i] = 1
end
println(a)
# Dict(MyT("Tom",191)=>1,MyT("Tom",191)=>1,MyT("Luc",493)=>1,MyT("Jo",315)=>1,MyT("Luc",493)=>1,MyT("Bob",20)=>1,MyT("Jo",315)=>1,MyT("Bob",20)=>1)
keyArray[1] # MyT("Tom",191)
haskey(a, keyArray[1]) # true
But I have to store keys in a separate array. This means that can't warranty the unicity of the keys which is the strength of the dictionaries and why I choose to use it :(
So I have to use another step :
unique(keyArray)
Another better solution :
function CompareKeys(k1::MyT, k2::MyT)
if k1.A == k2.A && k1.B == k2.B
return true
else
return false
end
end
function ExistKey(k::MyT, d::Dict{MyT, Int64})
for i in keys(d)
if CompareKeys(k, i)
return true
end
end
return false
end
a = Dict(MyT("Tom",191)=>1,MyT("Bob",20)=>1,MyT("Jo",315)=>1,MyT("Luc",493)=>1)
ExistKey(MyT("Tom",192),a) # false
ExistKey(MyT("Tom",191),a) # true
Compared to Julia, Go is more straightforward for this problem :
package main
import (
"fmt"
)
type MyT struct {
A string
B int
}
func main() {
dic := map[MyT]int{MyT{"Bob", 10}: 1, MyT{"Jo", 21}: 1}
if _, ok := dic[MyT{"Bob", 10}]; ok {
fmt.Println("key exists")
}
}
// answer is "key exists"
You just need to teach your MyT type that you want it to consider equality in terms of its composite fields:
julia> immutable MyT
A::String
B::Int64
end
import Base: ==, hash
==(x::MyT, y::MyT) = x.A == y.A && x.B == y.B
hash(x::MyT, h::UInt) = hash(x.A, hash(x.B, hash(0x7d6979235cb005d0, h)))
julia> a = Dict(MyT("Tom",191)=>1,MyT("Bob",20)=>1,MyT("Jo",315)=>1,MyT("Luc",493)=>1)
Dict{MyT,Int64} with 4 entries:
MyT("Jo", 315) => 1
MyT("Luc", 493) => 1
MyT("Tom", 191) => 1
MyT("Bob", 20) => 1
julia> haskey(a, MyT("Tom",191))
true
julia> in((MyT("Tom",191) => 1), a)
true
There are lots of good answers here, I'd just like to add a subtlety: this is partly because == calls === rather than recursively calling == when checking for structural equality, and partly because equal (==) strings are not generally identical (===) currently. Specifically, the fact that MyT("foo", 1) != MyT("foo", 1) is because "foo" !== "foo".
Strings are only "immutable by convention" – they are technically mutable, but Julia doesn't expose APIs for mutating them and encourages you not to mutate them. You can, however, access their underlying bytes and mutate that, which allows you to write a program that distinguishes two strings by getting by mutating one and not the other. That means that they cannot be === in the sense of Henry Baker's "EGAL" predicate (also here). If you have an immutable type with only "primitive" type fields, then this does not happen:
julia> immutable MyT2 # `struct MyT2` in 0.6
A::Float64
B::Int
end
julia> x = MyT2(1, 1)
MyT2(1.0, 1)
julia> y = MyT2(1, 1)
MyT2(1.0, 1)
julia> x == y
true
julia> x === y
true
I have already proposed that we change this and have == recursively call ==. This should be fixed, someone just needs to do the work. Moreover, in Julia 1.0 we could make Strings truly immutable rather than merely immutable by convention, and therefore have "foo" === "foo" be true. I've created an issue to discuss and track this change.
You're creating a new object in the haskey call. But two objects created by MyT("Tom", 191) are just two different MyT objects with the same field values.
Instead, do
key1 = MyT("Tom", 191)
a = Dict(key1 => 1)
haskey(a, key1)
see also
key2 = MyT("Tom", 191)
key1 == key2 # false
A julia-ideomatic way to deal with this would be to define an == method for MyT objects, so two objects are equal if they have the same field values. That would allow you to use them like you do.
It depends whether you need the type to be complex. Another easy and performant way to do what you want is to use a Tuple as the key:
a = Dict(("Tom", 191) => 1)
haskey(a, ("Tom", 191)) # true
a[("Tom", 191)] # 1
My approach would be similar to Matt's, but a bit simpler(?). Tuples are perfectly valid dictionary keys, so I would simply overload the relevant functions to convert your type back and forth to a tuple:
julia> immutable M; A::String; B::Int64; end
julia> import Base: =>, haskey, in
julia> =>(a::M, b) = (a.A, a.B)=>b
julia> haskey(a::Dict, b::M) = haskey(a, (b.A, b.B))
julia> in(a::Pair{M, Int64}, b::Int64) = in((a.first.A,a.first.B)=>a.second,b)
julia> a = Dict(M("Dick", 10)=>1, M("Harry", 20)=>2)
Dict{Tuple{String,Int64},Int64} with 2 entries:
("Dick", 10) => 1
("Harry", 20) => 2
julia> haskey(a, M("Dick", 10))
true
julia> in(M("Dick", 10)=>1, a)
true
"Compared to Julia, Go is more straightforward for this problem"
True. It also happens to be more error-prone (depending on your perspective). If you wanted to differentiate between two objects (used as keys) that do not correspond to the same object in memory, then Go's approach of simply testing 'value equality' would have landed you in trouble here (though one could argue 'value equality' generally makes more sense when comparing 'keys').
When I tried to do:
d = {1:2, 3:10, 6:300, 2:1, 4:5}
I get the error:
syntax: { } vector syntax is discontinued
How to initialize a dictionary in Julia?
The {} syntax has been deprecated in julia for a while now. The way to construct a dict now is:
Given a single iterable argument, constructs a Dict whose key-value pairs are taken from 2-tuples (key,value) generated by the argument.
julia> Dict([("A", 1), ("B", 2)])
Dict{String,Int64} with 2 entries:
"B" => 2
"A" => 1
Alternatively, a sequence of pair arguments may be passed.
julia> Dict("A"=>1, "B"=>2)
Dict{String,Int64} with 2 entries:
"B" => 2
"A" => 1
(as quoted from the documentation, which can be obtained by pressing ? in the terminal to access the "help" mode, and then type Dict)
I tried to run this command
dict = Dict("a" => 1, "b" => 2, "c" => 3, "d" => 4, "e" => 5)
in Julia 0.3.2 (via https://try.jupyter.org/) and got this error:
unsupported or misplaced expression =>
while loading In[1], in expression starting on line 1
I understand from here that this notation for dicts should be ok.
What is wrong?
The syntax is slightly different in 0.3:
x= Dict({"a"=>5})
Note the curly brackets!
Whereas the code you wrote is 0.4 syntax. You can check the documents by changing the version number.
Just for reference the 0.4 syntax is:
x=Dict("a"=>5)
For those coming here who are using Julia 1.0.0, note that the OP's code now works:
julia> dict = Dict("a" => 1, "b" => 2, "c" => 3, "d" => 4, "e" => 5)
Dict{String,Int64} with 5 entries:
"c" => 3
"e" => 5
"b" => 2
"a" => 1
"d" => 4
julia> VERSION
v"1.0.0"
An example from the Julia 1.0.0 docs is below:
Alternatively, a sequence of pair arguments may be passed.
julia> Dict("A"=>1, "B"=>2)
Dict{String,Int64} with 2 entries:
"B" => 2
"A" => 1