Im trying to convert a U.K. input date (dd-MM-yyyy) to format (yyyy-MM-dd)
I tried
"#formatDateTime('15-03-2019','yyyy-MM-dd')" ==> Error
but got error:
'In function 'convertTimeZone', the value provided
for date time string '15-03-2019' was not valid. The datetime
string must match ISO 8601 format.'
How do I go about converting this input date? The input format is (dd-MM-yyyy) and cannot be changed.
I can easily convert from (MM-dd-yyyy) as shown below, but im not able to convert from (dd-MM-yyyy)
"#formatDateTime('03-15-2019','yyyy-MM-dd')" ==> OK
Date and time functions provided by azure logic app cannot recognize the timestamp in dd-MM-yyyy format.
After my research, there is no existing function that can directly solve this problem, but you can use substring and concat to deal with this problem.
The workflow of the logic app looks like this:
The expression of the formatDataTime:
formatDateTime(concat(substring(<your-date-string>,6,4),'-',substring(<your-date-string>,3,2),'-',substring(<your-date-string>,0,2)),'yyyy-MM-dd')
Related
I have a DateTime variable (default formatting), and I would like to format it to a format to I receive from a string parameter.
I normally do something similar to: {myDate:yyyy-MM-dd}, and it works properly.
Now I have a lot of possible date formats and need to format according to the chosen one.
I have tried the following but returned garbage (ae0aor0aa):
string testFormat = "yyyy. MM. dd.";
{myDate:testFormat }
I have also tried to convert the date to string and back to date with ParseExact, but gave me an invalid date exception. NB: the date in myDate is valid, as I have checked it with the debugger.
Can you kindly advise?
Thanks to apc, it was easily solved by myDate.ToString(testFormat)
Can't format the below date using moment.js, the below statement returns Invalid Date
moment('20171206T062406927Z').format('D-MMM-YYYY');
Please help me on this.
You need to tell moment which format your date string is in:
moment('20171206T062406927Z', 'YYYYMMDD[T]HHmmssSSSZ', true).format('D-MMM-YYYY');
Edit: updated as per #VincenzoC comment to ensure the timestamp is parsed in UTC
Also fix: use HH for 24-hour format (not hh), and pass a third true parameter to ensure the timestamp is parsed in strict mode.
I am trying to obtain a date from an XML file that is in this format:
2016-10-27
however, the field I am trying to put it in is in this format:
mm/dd/yyyy
is there a code for this in dynamics ax 2012? I tried str2date but it doesn't output anything.
SOLVED: Just to let you guys know even though you are obtaining a string that has a format like mine 2016-10-27 AX automatically formats it to the default format to 10/27/2016 just input the sequence correctly. (THIS IS NOT PART OF THE ANSWER I AM JUST EXPLAINING MY FINDINGS)
You will need to use str2date(string _date, int _sequence). Specify the related format in sequence. Your desired format will be 213
I need to convert a string formatted as MM/DD/YYYY HH:MI plus AM/PM, but can't find a complete reference to the format string to find how to specify the AM/PM part.
I would certainly appreciate information on how to do this, but would appreciate a link to a good source of documentation for this even more.
:EDIT
SELECT top 1
v.CalendarDateTime
,TO_TIMESTAMP(v.CalendarDateTime,'MM/DD/YYYY HH:MIAM') as CalendarDateTimeTS
--,CAST(TO_TIMESTAMP(v.CalendarDateTime,'MM/DD/YYYY HH:MIAM') AS TIMESTAMP(0) FORMAT 'MM/DD/YYYYBHH:MIBT') AS CalendarDateTimeTS2
12/03/2015 03:00AM 12/3/2015 03:00:00.000000
The commented out line produces a "DateTime field overflow" error.
You probably want TO_TIMESTAMP instead of TO_DATE.
The only bad thing about the Oracle function is the resulting datatype of TIMESTAMP(6) which can't be changed:
TO_TIMESTAMP('12/03/2015 03:00AM', 'MM/DD/YYYY HH:MIAM')
Using Teradata's FORMAT you can specify the timestamp precision, but it's less flexible than Oracle's, the string must match the format exactly:
CAST('12/03/2015 03:00AM' AS TIMESTAMP(0) FORMAT 'MM/DD/YYYYbHH:MIT')
On the Teradata site you'll find the (slow) online docu, e.g. TO_DATE formats or Teradata FORMATs. Of course you should download the full documentation CD for your release.
Please tell us at least which programming language are you using.
Normally it would be something like "MM/DD/YYYY HH:MI a" but we need to know first you language.
I insert my date/time data into a CHAR column in the format: '6/4/2015 2:08:00 PM'.
I want that this should get automatically converted to format:
'2015-06-04 14:08:00' so that it can be used in a query because the format of DATETIME is YYYY-MM-DD hh:mm:ss.fffff.
How to convert it?
Given that you've stored the data in a string format (CHAR or VARCHAR), you have to decide how to make it work as a DATETIME YEAR TO SECOND value. For computational efficiency, and for storage efficiency, it would be better to store the value as a DATETIME YEAR TO SECOND value, converting it on input and (if necessary) reconverting on output. However, if you will frequently display the value without doing computations (including comparisons or sorting) it, then maybe a rococo locale-dependent string notation is OK.
The key function for converting the string to a DATETIME value is TO_DATE. You also need to look at the TO_CHAR function because that documents the format codes that you need to use, and because you'll use that to convert a DATETIME value to your original format.
Assuming the column name is time_string, then you need to use:
TO_DATE(time_string, '%m/%d/%Y %I:%M %x') -- What goes in place of x?
to convert to a DATETIME YEAR TO SECOND — or maybe DATETIME YEAR TO MINUTE — value (which will be further manipulated as if by EXTEND as necessary).
I would personally almost certainly convert the database column to DATETIME YEAR TO SECOND and, when necessary, convert to the string format on output with TO_CHAR. The column name would now be time_value (for sake of concreteness):
TO_CHAR(time_value, '%m/%d/%Y %I:%M %x') -- What goes in place of x?
The manual pages referenced do not immediately lead to a complete specification of the format strings. I think a relevant reference is GL_DATETIME environment variable, but finding that requires more knowledge of the arcana of the Informix product set than is desirable (it is not the first thing that should spring to anyone's mind — not even mine!). If that's correct (it probably is), then one of %p and %r should be used in place of %x in my examples. I have to get Informix (re)configured on my machine to be able to test it.