Problem with understanding Functional Programming concept - functional-programming

Question

I'm taking a course in functional programming and coming from OOP my brain hurts trying to solve something that I think is quite trivial but I'm just not understanding the concept here. This is an exercise I need to do for school
Given a phrase, in my case it is
"Pattern Matching with Elixir. Remember that equals sign is a match operator, not an assignment"
I need to check starting letters of every word for a matching pattern and apply specific modification depending on pattern.
Im not even entirely sure what my current code is producing, when I inspect x and y I sort of understand what the loops are doing, they have a list for every word of phrase and that inner list consists of checks against every single letter, nil if it doesnt start with that letter and modified word if it does.
OOP in me wants those loops not to return any "nil" and only return a single edited word in every iteration. In functional programming I cant break loops and force returns so I need to think about this in another way.
My question is how should I approach this problem from functional programming perspective?
In the beginning I get a list of words which form a phrase, then I wish to edit every word and in the end get a list again containing these edited words.
Maybe a pseudo-code-like structure on how to tackle this would help me understand underlying concepts.
Here is my current code:
#Task two
def taskTwo() do
IO.puts "Task Two"
IO.puts "Pattern Matching with Elixir. Remember that equals sign is a match operator, not an assignment"
IO.puts "Task Two\n...Editing Words ..."
phrase = String.downcase("Pattern Matching with Elixir. Remember that equals sign is a match operator, not an assignment") |> String.split()
x = for word <- phrase do
checkVowels(word)
end
y = for word <- phrase do
checkConsonants(word)
end
IO.inspect x
IO.inspect y
end
#check vowels
def checkVowels(word) do
vowels = ["a","e","i","o","u"]
for vowel <- vowels do
if String.starts_with?(word, vowel) do
word <> "ay "
end
end
end
#check consonants
def checkConsonants(word) do
consonants = ["b","c","d","f","g","h","j","k","l","m","n","p","q","r","s","t","v","w","x","z","y"]
for consonant <- consonants do
if String.starts_with?(word, consonant) do
edited = String.replace_prefix(word, consonant, "")
edited <> consonant <> "ay "
end
end
end
MOdifications I need to apply: First check for starting letter and apply modification, then check again an see if inside word there are any of the multiletter combinations
Words beginning with consonants should have the consonant moved to the end of the word, followed by "ay".
Words beginning with vowels (aeiou) should have "ay" added to the end of the word.
Some groups of letters are treated like consonants, including "ch", "qu", "squ", "th", "thr", and "sch".
Some groups are treated like vowels, including "yt" and "xr".

Answer 1

One possible way (maybe not the most efficient, but using some of the Elixir powers) is to use recursion and pattern matching.
So one possible way to solve the first part of your exercise.
defmodule Example do
#vowels ~w[a e i o u y]
#phrase "Pattern Matching with Elixir. Remember that equals sign is a match operator, not an assignment"
def task_two() do
phrase =
#phrase
|> String.downcase()
|> String.split()
|> Enum.reverse()
# splitting the first letter of each word
|> Enum.map(&String.split_at(&1, 1))
# pass the phrase and an accumulator as arguments
result = check_words(phrase, [])
IO.inspect(result)
end
# using recursion to traverse the list
# when the phrase have no more words, it will match the empty list
def check_words([], phrase) do
Enum.join(phrase, " ")
end
# pattern match on the first letter and using guards to decide if vowel
def check_words([{first_letter, rest_of_word} | rest_of_list], accumulator)
when first_letter in #vowels do
# call the function again, with the rest of the list
new_word = first_letter <> rest_of_word <> "ay"
check_words(rest_of_list, [new_word | accumulator])
end
# when the pattern does not match for vowels, it should be a consonant
def check_words([{first_letter, rest_of_word} | rest_of_list], accumulator) do
new_word = rest_of_word <> first_letter <> "ay"
check_words(rest_of_list, [new_word | accumulator])
end
end
You will need to skip/handle the commas and possible some more tweaks to be fully functional. But hope it helps as a general idea.
Notes:
write tests. They will really help you understand what the code is doing
Elixir is an amazing language. If you come from OOP may look strange in the beginning. This book: Programming Elixir is really good and will help you a lot if you want to progress quickly.