#!/usr/bin/env zsh
doit() {
if [[ "$1" = "start" ]]; then
for loc in $(cat all-doc); do
if ! screen -list | grep -q My-$loc; then
screen -dmS My-$loc /home/Server -f /home/$loc.cfg
fi
done
elif [[ "$1" = "stop" ]]; then
for loc in $(cat all-doc); do
if screen -list | grep -q My-$loc; then
pkill -f My-$loc;
fi
done
else
echo "Option: ERROR..."
fi
}
nothing() {
if [[ "$1" = "start" ]]; then
echo "Option: 1"
elif [[ "$1" = "stop" ]]; then
echo "Option: 2"
else
echo "Option: 3"
fi
}
case "$2" in
start)
"$1" "$2";
;;
stop)
"$1" "$2";
;;
restart)
restart;
;;
*)
echo "Usage: $0 {doit|nothing} {start|stop|restart}"
exit 1
;;
esac
exit 0
Output:
./script.sh:34> case test (start)
./script.sh:34> case test (stop)
./script.sh:34> case test (restart)
./script.sh:34> case test (*)
./script.sh:45> echo 'Usage: ./script.sh {start|stop|restart}'
sage: ./script.sh {start|stop|restart}
./script.sh:46> exit 1
this script for start and stop and restart my servers.
If $2 not match with "start" "stop" "restart" in both function must call else but not work.
Ok question is why ./script.sh doit test did not call
else
echo "Option: ERROR..."
whats the sulotion ? Is there better way to do somthing for ./script.sh $1 $2 i mean $1 get function and $2 get start|stop|restart ?
I have script which is running in bg(nohup) but it was accidently deleted,but that is continue running now I need to edit the code which is already deleted.
How can I now get that code.I assume somewhere it should be as it is running.
Try this :
#!/bin/bash
if [[ ! $1 || $1 == -h || $1 == --help ]]; then
echo -e "Usage:\n\n\t$0 '[path/]<file name>'"
exit 1
fi
files=(
$(file 2>/dev/null /proc/*/fd/* |
grep "(deleted)'$" |
sed -r 's#(:.*broken\s+symbolic\s+link\s+to\s+.|\(deleted\).$)# #g' |
grep "$1" |
cut -d' ' -f1
)
)
if [[ ${files[#]} ]]; then
for f in ${files[#]}; do
echo "fd $f match... Try to copy this fd to another place quickly!"
done
else
echo >&2 "No matching fd found..."
exit 2
fi
Not tested on non GNU-Linux
I have the below script that is expected to work when the user invokes sh <scriptName> <propertyfile> It does work when I provide this at the dollar prompt. However, I am having two issues with the script.
If I provide just one argument, ie if I do - sh <scriptName>, I see the below error -
my-llt-utvsg$ sh temp.sh
Usage temp.sh
When I do -help, I see the below error -
my-llt-utvsg$ sh tmp.sh -help
-help does not exist
What am I doing wrong? Can someone please advise? I am a software developer that very rarely needs to do shell scripting, so please go easy on me ;)
#!/bin/bash
FILE="system.properties"
FILE=$1
if [ ! -f $FILE ];
then
echo "$FILE does not exist"
exit
fi
usage ()
{
echo "Usage $0 $FILE"
exit
}
if [ "$#" -ne 1 ]
then
usage
fi
if [ "$1" = "-help" ] ; then
echo ""
echo '############ HELP PROPERTIES ############ '
echo ""
echo 'Blah.'
exit
The reason your
if [ "$1" = "-help" ] ; then
check is not working is that it only checks $1 or the first argument.
Try instead:
for var in "$#"
do
if [ "$var" = "-help" ] ; then
echo ""
echo '############ HELP PROPERTIES ############ '
echo ""
echo 'Blah.'
fi
done
Which will loop over each argument and so will run if any of them are -help.
Try this as well:
#!/bin/bash
FILES=()
function show_help_info_and_exit {
echo ""
echo '############ HELP PROPERTIES ############ '
echo ""
echo 'Blah.'
exit
}
function show_usage_and_exit {
echo "Usage: $0 file"
exit
}
for __; do
if [[ $__ == -help ]]; then
show_help_info_and_exit
elif [[ -f $__ ]]; then
FILES+=("$__")
else
echo "Invalid argument or file does not exist: $__"
show_usage_and_exit
fi
done
if [[ ${#FILES[#]} -ne 1 ]]; then
echo "Invalid number of file arguments."
show_usage_and_exit
fi
echo "$FILES"
I have been trying to execute the following UNIX shell script which is not working.
I am running it by KornShell (ksh).
echo $?;
if [ $? -ne 0 ]
then
failed $LINENO-2 $5 $6
fi
failed()
{
echo "$0 failed at line number $1";
echo "moving $2 to failed folder"
}
This is giving an error saying Syntax error:then unexpected.. Basically I have to check for the last executed ksh script's highest/last statement's return code and if it is not equal to zero I have to call function failed with the given parameters. I tried putting semicolon before then but that also did not work.
Can you please help?
Edit1: Based on the inputs I changed code. Still the same problem exists.
ksh ../prescript/Pre_process $1 $2 $3
rc=$?;
if [[ $rc -ne 0 ]];then
echo "failed";
exit 1;
Edit2:
It is working for the then part by using double squared brackets. I feel I used code of bash script for ksh. I am facing problem in function call of failed. Please let me know appropriate way of function call in ksh for this example
This looks like bash rather than ksh
failed() {
echo "$0 failed at line number $1";
echo "moving $2 to failed folder"
}
if [[ $? -ne 0 ]]
then
failed $LINENO-2 $5 $6
fi
You need to be careful. The first operation on $? will usually clear it so that your if won't work anyway.
You would be better off using:
rc=$?
echo $rc
if [ $rc -ne 0 ]
:
Other than that, it works fine for me:
$ grep 1 /dev/null
$ if [ $? -ne 0 ]
> then
> echo xx
> fi
xx
$ grep 1 /dev/null
$ echo $?;
1
$ if [ $? -ne 0 ]
> then
> echo yy
> fi
$ _
Note the lack of output in the last one. That's because the echo has sucked up the return value and overwritten it (since the echo was successful).
As an aside, you should let us know which UNIX and which ksh you're actually using. My working version is ksh93 under Ubuntu. Your mileage may vary if you're using a lesser version.
It looks like, from your update, your only problem now is the function call. That's most likely because you're defining it after using it. The script:
grep 1 /dev/null
rc=$?
if [ $rc -ne 0 ]
then
failed $rc
fi
failed()
{
echo Return code was $1
}
produces:
qq.ksh[6]: failed: not found
while:
failed()
{
echo Return code was $1
}
grep 1 /dev/null
rc=$?
if [ $rc -ne 0 ]
then
failed $rc
fi
produces
Return code was 1
you are missing semicolons at the end of the lines:
if [ $? -ne 0]; then
# …
This question already has answers here:
How do I test if a variable is a number in Bash?
(40 answers)
Closed 1 year ago.
How do I check to see if a variable is a number, or contains a number, in UNIX shell?
if echo $var | egrep -q '^[0-9]+$'; then
# $var is a number
else
# $var is not a number
fi
Shell variables have no type, so the simplest way is to use the return type test command:
if [ $var -eq $var 2> /dev/null ]; then ...
(Or else parse it with a regexp)
No forks, no pipes. Pure POSIX shell:
case $var in
(*[!0-9]*|'') echo not a number;;
(*) echo a number;;
esac
(Assumes number := a string of digits). If you want to allow signed numbers with a single leading - or + as well, strip the optional sign like this:
case ${var#[-+]} in
(*[!0-9]*|'') echo not a number;;
(*) echo a number;;
esac
In either ksh93 or bash with the extglob option enabled:
if [[ $var == +([0-9]) ]]; then ...
Here's a version using only the features available in a bare-bones shell (ie it'd work in sh), and with one less process than using grep:
if expr "$var" : '[0-9][0-9]*$'>/dev/null; then
echo yes
else
echo no
fi
This checks that the $var represents only an integer; adjust the regexp to taste, and note that the expr regexp argument is implicitly anchored at the beginning.
This can be checked using regular expression.
###
echo $var|egrep '^[0-9]+$'
if [ $? -eq 0 ]; then
echo "$var is a number"
else
echo "$var is not a number"
fi
I'm kind of newbee on shell programming so I try to find out most easy and readable
It will just check the var is greater or same as 0
I think it's nice way to choose parameters... may be not what ever... :
if [ $var -ge 0 2>/dev/null ] ; then ...
INTEGER
if echo "$var" | egrep -q '^\-?[0-9]+$'; then
echo "$var is an integer"
else
echo "$var is not an integer"
fi
tests (with var=2 etc.):
2 is an integer
-2 is an integer
2.5 is not an integer
2b is not an integer
NUMBER
if echo "$var" | egrep -q '^\-?[0-9]*\.?[0-9]+$'; then
echo "$var is a number"
else
echo "$var is not a number"
fi
tests (with var=2 etc.):
2 is a number
-2 is a number
-2.6 is a number
-2.c6 is not a number
2. is not a number
2.0 is a number
if echo $var | egrep -q '^[0-9]+$'
Actually this does not work if var is multiline.
ie
var="123
qwer"
Especially if var comes from a file :
var=`cat var.txt`
This is the simplest :
if [ "$var" -eq "$var" ] 2> /dev/null
then echo yes
else echo no
fi
Here is the test without any regular expressions (tcsh code):
Create a file checknumber:
#! /usr/bin/env tcsh
if ( "$*" == "0" ) then
exit 0 # number
else
((echo "$*" | bc) > /tmp/tmp.txt) >& /dev/null
set tmp = `cat /tmp/tmp.txt`
rm -f /tmp/tmp/txt
if ( "$tmp" == "" || $tmp == 0 ) then
exit 1 # not a number
else
exit 0 # number
endif
endif
and run
chmod +x checknumber
Use
checknumber -3.45
and you'll got the result as errorlevel ($?).
You can optimise it easily.
( test ! -z "$num" && test "$num" -eq "$num" 2> /dev/null ) && {
# $num is a number
}
You can do that with simple test command.
$ test ab -eq 1 >/dev/null 2>&1
$ echo $?
2
$ test 21 -eq 1 >/dev/null 2>&1
$ echo $?
1
$ test 1 -eq 1 >/dev/null 2>&1
$ echo $?
0
So if the exit status is either 0 or 1 then it is a integer , but if the exis status is 2 then it is not a number.
a=123
if [ `echo $a | tr -d [:digit:] | wc -w` -eq 0 ]
then
echo numeric
else
echo ng
fi
numeric
a=12s3
if [ `echo $a | tr -d [:digit:] | wc -w` -eq 0 ]
then
echo numeric
else
echo ng
fi
ng
Taking the value from Command line and showing THE INPUT IS DECIMAL/NON-DECIMAL and NUMBER or not:
NUMBER=$1
IsDecimal=`echo "$NUMBER" | grep "\."`
if [ -n "$IsDecimal" ]
then
echo "$NUMBER is Decimal"
var1=`echo "$NUMBER" | cut -d"." -f1`
var2=`echo "$NUMBER" | cut -d"." -f2`
Digit1=`echo "$var1" | egrep '^-[0-9]+$'`
Digit2=`echo "$var1" | egrep '^[0-9]+$'`
Digit3=`echo "$var2" | egrep '^[0-9]+$'`
if [ -n "$Digit1" ] && [ -n "$Digit3" ]
then
echo "$NUMBER is a number"
elif [ -n "$Digit2" ] && [ -n "$Digit3" ]
then
echo "$NUMBER is a number"
else
echo "$NUMBER is not a number"
fi
else
echo "$NUMBER is not Decimal"
Digit1=`echo "$NUMBER" | egrep '^-[0-9]+$'`
Digit2=`echo "$NUMBER" | egrep '^[0-9]+$'`
if [ -n "$Digit1" ] || [ -n "$Digit2" ]; then
echo "$NUMBER is a number"
else
echo "$NUMBER is not a number"
fi
fi