test ./script.sh doit test dont show true output - zsh

Question

#!/usr/bin/env zsh
doit() {
if [[ "$1" = "start" ]]; then
for loc in $(cat all-doc); do
if ! screen -list | grep -q My-$loc; then
screen -dmS My-$loc /home/Server -f /home/$loc.cfg
fi
done
elif [[ "$1" = "stop" ]]; then
for loc in $(cat all-doc); do
if screen -list | grep -q My-$loc; then
pkill -f My-$loc;
fi
done
else
echo "Option: ERROR..."
fi
}
nothing() {
if [[ "$1" = "start" ]]; then
echo "Option: 1"
elif [[ "$1" = "stop" ]]; then
echo "Option: 2"
else
echo "Option: 3"
fi
}
case "$2" in
start)
"$1" "$2";
;;
stop)
"$1" "$2";
;;
restart)
restart;
;;
*)
echo "Usage: $0 {doit|nothing} {start|stop|restart}"
exit 1
;;
esac
exit 0
Output:
./script.sh:34> case test (start)
./script.sh:34> case test (stop)
./script.sh:34> case test (restart)
./script.sh:34> case test (*)
./script.sh:45> echo 'Usage: ./script.sh {start|stop|restart}'
sage: ./script.sh {start|stop|restart}
./script.sh:46> exit 1
this script for start and stop and restart my servers.
If $2 not match with "start" "stop" "restart" in both function must call else but not work.
Ok question is why ./script.sh doit test did not call
else
echo "Option: ERROR..."
whats the sulotion ? Is there better way to do somthing for ./script.sh $1 $2 i mean $1 get function and $2 get start|stop|restart ?