Following is the query which returns no of days, hrs, sec, and ns when a timestamp is subtracted from another date
to_timestamp(to_char(MR_REQ_T.LAST_UPDATE_DATE, 'yyyy-mm-dd hh:mi:ss am'), 'yyyy-mm-dd hh:mi:ss am')- MR_DETAILS.WO_CREATION_DATE M4_DETAILS
its given o/p is as follows
+00 00:04:32.000000
But I don't need nano sec.(000000)to be included in it. Is there any way to remove it.
Related
pdt.startTime is datetime
s_first.FromTimeOfDay is a time
I want to subtract the time drom the datetime. When i run the code below, Snowflake gives me this error invalid type [CAST(S_FIRST.FROMTIMEOFDAY AS TIMESTAMP_NTZ(9))] for parameter 'TO_TIMESTAMP_NTZ'
select (pdt.StartTime - (SELECT s_first.FromTimeOfDay::datetime FROM Shift s_first))
from RAW_CPMS_AAR.POWERBI_DowntimeTable AS PDT
When i try this:
select (pdt.StartTime::TIMESTAMP_NTZ(9) - (SELECT s_first.FromTimeOfDay::TIMESTAMP_NTZ(9) FROM Shift s_first))
from RAW_CPMS_AAR.POWERBI_DowntimeTable AS PDT
I get more or less the same error: invalid type [CAST(S_FIRST.FROMTIMEOFDAY AS TIMESTAMP_NTZ(9))] for parameter 'TO_TIMESTAMP_NTZ'
How do I convert the time into a datetime format so that I can subtract the two. It doesnt seem to me that there is a clear way to convert time into datetime in snowflake.
Is this what you're after?
select current_timestamp() as sample_timestamp
, time(sample_timestamp) as sample_time
, date(sample_timestamp) as sample_date;
A user pointed me in the right direction. i didnt realize i could use "dateadd" to also subtract time.
dateadd(HOUR, - (HOUR(current_timestamp())), temp.DateTime)
My demand is really so silly, so basically I need to go back in time 24 hours in a timestamp column in Hive.
So far, I have tried two different ways but it's not going thru:
select
recordDate, --original date
cast(date_sub(cast(recorddate as timestamp),1) as timestamp), -- going one day behind without hour
cast((cast(cast(recorddate as timestamp) AS bigint)-1*3600) as timestamp) -- crazy year
from mtmbuckets.servpro_agents_events limit 10;
My output looks:
I appreciate the support you can give me.
thanks
There is not straight forward function in hive .
1 Create UDF to do so .
or
Convert date in no of second and do you calculation( -24 *60*60) sec then change back int to data.
use from_unixtime and unix_timestamp to achieve below code.
select from_unixtime(unix_timestamp(recorddate) - 86400)
from mtmbuckets.servpro_agen ts_events limit 10;;
From_unixtime
Convert time string with given pattern to Unix time stamp (in seconds) The result of this function is in seconds.
Unix_timestamp
Converts time string in format yyyy-MM-dd HH:mm:ss to Unix timestamp (in seconds), using the default timezone and the default locale, return 0 if fail: unix_timestamp('2009-03-20 11:30:01') = 1237573801
there are multiple timestamps column in oracle Sql , Now in want to convert 12 hour format time into 24 hour format time like 01-FEB-18 01.00.21.645000000 PM should be 05-01-0018 13:12:44. but I need to convert hours into 24 hours time format , I am using the below statement.
SELECT TO_CHAR(TO_DATE(PERFORMED_TIMESTAMP,'DD-MON-YYYY hh:mi:ss AM'),'DD-MM-YYYY hh24:mi:ss')
FROM FACT_WORK_ITEM_ACTION
WHERE TRUNC(PERFORMED_TIMESTAMP)>= '05-JUN-18'
But still i am getting the below error .
Error Code....
ORA-01855: AM/A.M. or PM/P.M. required
01855. 00000 - "AM/A.M. or PM/P.M. required"
*Cause:
*Action:
SELECT to_char( TO_timestamp('01-FEB-18 01.21.01.645','dd-mon-yy hh12.mi.ss.ff'),'dd-mm-yyyy hh24:mi:ss')
from dual;
Your PERFORMED_TIMESTAMP is already a timestamp, which doesn't have any intrinsic human-readable format - Oracle uses its own internal representation when storing the values.
You are just seeing that timestamp displayed by your client with formatting taken from the session NLS settings (or, possibly, overridden by the client itself).
The error is because you are doing unnecessary data type conversions and relying on implicit conversion and NLS session settings. When you do
TO_DATE(PERFORMED_TIMESTAMP,'DD-MON-YYYY hh:mi:ss AM')
you are first implicitly converting the PERFORMED_TIMESTAMP to a string, again using your session NLS settings, so you're effectively doing:
TO_DATE(TO_CHAR(PERFORMED_TIMESTAMP),'DD-MON-YYYY hh:mi:ss AM')
which given the string values in your question is actually:
TO_DATE(TO_CHAR(PERFORMED_TIMESTAMP, 'DD-MON-RR HH.MI.SS.FF AM'),'DD-MON-YYYY hh:mi:ss AM')
The inner part of that will give a string like "01-FEB-18 01.00.21.645000000 PM" which is what you see when you query the table and the client does its own formatting. Passing that string back into to_date() gives the error you see, because the fractional seconds are appearing in the string where it's expecting to see the AM/PM marker:
SELECT TO_DATE('01-FEB-18 01.00.21.645000000 PM','DD-MON-YYYY hh:mi:ss AM')
FROM DUAL;
Error report -
ORA-01855: AM/A.M. or PM/P.M. required
You could replace the implcit conversion and session values with explicit conversion and format masks:
TO_CHAR(TO_DATE(TO_CHAR(PERFORMED_TIMESTAMP, 'DD-MON-YYYY hh:mi:ss AM'),'DD-MON-YYYY hh:mi:ss AM'), 'DD-MM-YYYY hh24:mi:ss')
But hopefully you can tell that is doing a lot more work than it needs to -and having to use the same format mask twice is also a sign that you're doing something wrong.
The real solution is just to simplify it. You don't need to convert to a string and back to a date at all. Just do:
SELECT TO_CHAR(PERFORMED_TIMESTAMP, 'DD-MM-YYYY HH24:MI:SS')
FROM FACT_WORK_ITEM_ACTION
WHERE PERFORMED_TIMESTAMP >= TIMESTAMP '2018-06-05 00:00:00';
Notice that I've also removed the trunc() and the comparison with a string; this now compares your timestamp column as a timestamp, which will make any index on that happier too.
Quick demo with a CTE to provide dummy data:
with FACT_WORK_ITEM_ACTION(PERFORMED_TIMESTAMP) as (
select timestamp '2018-06-01 13:00:21.645000000' from dual
union all select timestamp '2018-06-06 13:00:21.645000000' from dual
)
SELECT TO_CHAR(PERFORMED_TIMESTAMP, 'DD-MM-YYYY HH24:MI:SS')
FROM FACT_WORK_ITEM_ACTION
WHERE PERFORMED_TIMESTAMP >= TIMESTAMP '2018-06-05 00:00:00';
TO_CHAR(PERFORMED_T
-------------------
06-06-2018 13:00:21
I'm storing my dates in SQLite in a column of data type INTEGER. I'm storing the milliseconds since 1970.
Eg:
date (long) other columns ...
-----------------------------------------
1407297600000 ...
1407211200000 ...
1407124800000 ...
My question is: how can I use strftime() under this circumstances?
If not, I should use TEXT as the column type??
Running this:
select strftime('%Y-%m', date) from my_table;
Is throwing nonesense stuff:
strftime('%Y-%m', date)
-----------------------------------------
1968-19
1968-19
1968-19
Unless you tell it otherwise, strftime() thinks those numbers are Julian day values - very different from Unix epoch milliseconds.
You'll want to convert to seconds, and tell strftime() these are Unix epoch numbers:
select strftime('%Y-%m', date / 1000, 'unixepoch');
See the Modifiers section in the SQLite Date and Time Functions docs.
I am having a column in my sql server database table with datatype bigint.
Now i need to convert this column into HH:MM:SS formate.
For this i use this command
SELECT cast(CONVERT(VARCHAR,DATEADD(MS,SUM(mFld),0),8) as Time) FROM tblm
But this command doesn't show right time duration.
For right time duration i use this command
SELECT rtrim(LTRIM(cast((mFld/(60*60)) as char)))+':' +rtrim(LTRIM(cast((mFld%(60*60))/(60)as char)))+':'+rtrim(LTRIM(cast(((mFld%(60*60))%(60)) as char))) FROM tblm
This command shows right result.But resulted data type is varchar.How can i convert this column in to time column with same result.
Example
DECLARE #minites bigint;
SET #minites = 5200020;
SELECT rtrim(LTRIM(cast((#minites/(60*60)) as char)))+':' +rtrim(LTRIM(cast((#minites%(60*60))/(60)as char)))+':'+rtrim(LTRIM(cast(((#minites%(60*60))%(60)) as char)))
SELECT cast(CONVERT(VARCHAR,DATEADD(MS,SUM(#minites),0),8) as Time)
How can i convert this column in to time column with same result.
You can't. Time has the range 00:00:00.0000000 to 23:59:59.9999999.
time (Transact-SQL)