I have a problem when, I try to open a Jar File with JD-GUI Decompiler, the error is the following.
This error don't let me decompile the jar.
To solve this problem, I did the following.
Change the extension jar file to RAR file or another compressed format.
Uncompresed the file.
Open some file class inside the folder mentioned above with JD-GUI
Finally in JD-GUI tool, choose the option File -> Save all Resources
Related
Recently I encountered a problem when using exe4j to package the jar into exe. My xml configuration file is placed in the same directory of the exe, but after the package is completed, the exe will look for the xml file from the temporary folder.
These are the instructions in the exe4j help documentation
For some applications (especially GUI applications) you might want to change >the working directory to a specific directory relative to the executable, for >example to read config files that are in a fixed location. To do so, please >select the Change working directory to: checkbox and enter a directory relative >to the executable in the adjacent text field. To change the current directory >to the same directory where the executable is located, please enter a single >dot.
The error when i running the exe :
[ERROR] In Log's init,cann't read config file, file=/C:/Users/**/AppData/Local/Temp/e4jEA8.tmp_dir1543543191//sys_log.xml
Why is the program not looking for this xml from the exe's sibling directory, and how can I find it from this directory?
If you are using the "JAR in EXE" mode, use
System.getPrpoerty("install4j.exeDir")
to get the parent directory of the executable.
I have one JAR named as abc.jar with 15 class files. In JAR file I need to modify xyz.class, so I decompiled to xyz.java and modified it.
How can I update that JAR with the modified Java file? While trying to create (compile) the JAR file I am getting errors.
You can add your newly compiled class to the jar and overwrite the old one, here is how to add xyz.class and xyz.java to the jar :
jar uf abc.jar xyz.class xyz.java
See here for more about updating a jar file.
Or simply you can use any archiving tool, like winrar to open and add files to the jar.
Compile the xyz.java and replace the xyz.class file directly in jar without building the jar again, if the single class has been modified.
Is it possible to create a jar file which contains the javadoc ?
For now, I'm creating a jar file & javadoc folder.
1. I want to create a jar file that contains the javadoc , can I ?
2. Can I do so without attaching the source code into the jar file ? (just the jar with javadoc) ?
Thanks
The short answer is yes. A jar file is just a zip with a manifest and additional features. You can put any type of file in it, including images, html files etc... All you have to do is jar your javadoc folder exactly as you would do for a classes folder.
I am using iexpress to make my .jar files into .exe files
for this I add the jar file(myjarfile.jar) and in run command box I type : java -jar myjarfile.jar
but after creating the .exe the cmd that is flashing says cannot find the jar file myjarfile.jar
can any body help me find what I am doing wrong
To test this, I built a simple HelloWorld.jar file (using these instructions) and tested it like so:
java -jar HelloWorld.jar
Then I made an IExpress package with it. The Install program was exactly the command I used above. This worked exactly as it should.
Two possible causes of the error:
In the IExpress wizard, there's a checkbox Store files using Long File Name inside Package. You should definitely select this option; ignore the warning that appears, as it applies to Windows 95/98. In the .sed file, this is:
UseLongFileName=1
Check that the .exe actually contains myjarfile.jar. 7-Zip will open the .exe and show you the archive contents. (IExpress .exe files are just a CAB file with a wrapper.) If the file is missing, then you'll need to check your .sed file to see what went wrong.
I have a problem regarding exporting my Java project into a jar file.
I have this file (application.properties) which contains some database information and located under the project root directory.
There is no problem when running this project on Eclipse. But after exporting into a jar(Runnable Jar file) file, application.properties will not be included in the packaging and that cause the error.
Any suggestion how to fix this problem?
Do you want to have the application.properties reside outside the jar (for writing), or is it read-only? When outside you can have an initial template file in the jar, and copy it to some location.
//String applicationWorkingDir = System.getProperty("user.dir"); // The current constellation.
String userHomeDir = System.getProperty("user.home");
File myApplicationDataDir = new File(userHomeDir + "/.MyApplication");
myApplicationDataDir.mkdir();
File propertiesFile = new File(myApplicationDataDir, "application.properties");
Also using the Preferences API instead of a properties would be a solution.