I have one JAR named as abc.jar with 15 class files. In JAR file I need to modify xyz.class, so I decompiled to xyz.java and modified it.
How can I update that JAR with the modified Java file? While trying to create (compile) the JAR file I am getting errors.
You can add your newly compiled class to the jar and overwrite the old one, here is how to add xyz.class and xyz.java to the jar :
jar uf abc.jar xyz.class xyz.java
See here for more about updating a jar file.
Or simply you can use any archiving tool, like winrar to open and add files to the jar.
Compile the xyz.java and replace the xyz.class file directly in jar without building the jar again, if the single class has been modified.
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I created one jar file and in that i have class files, .classpath file, .project file In sample on github, i see apiproxy, callout and lib folder. when i deploy it, i getting error that traffic can't flow , i get error like traffic.How to upload dependencies jar in lib folder However when i upload my main jar file in resources folder, i don't see any lib folder for dependencies jars. Should i place all jars in one resources folder. in my .classpath file, i can see all lib jars like message-flow-1.0.0.jar, expressions-1.0.0.jar and itextpdf-5.5.6.jar. However in documentation, its given to deploy by maven but i don't know maven, from UI how should i create lib folder and upload jars there.
Okay, in my understanding of your point.
You can upload jar file into apigee from Scripts > import file > in file type choose "JAR" > select jar file from your work space > and finally, define your jar name and then use policy Java Callout to call your jar.
If you have to modified your jar and want to deploy it, delete your existing jar in apigee and upload the new jar by following 1. In case of new jar has the same name of existing jar, you do not need to do anything with Java Callout policy. But the new jar has the different name, don't forget to modified Java Callout for refer to your new jar.
Please create the single jar file which contains jars like message-flow-1.0.0.jar, expressions-1.0.0.jar and itextpdf-5.5.6.jar. As per the apigee doc in create a Java Callout policy and make sure you have mentioned the package name & class name in Java Callout Poliy
<ClassName>package.ClassName</ClassName
<ResourceURL>java://SingleJar.jar</ResourceURL>
I want to convert my jar file to eclipse project, so that i can make changes in the existing code. Can anyone help me with this. I tried extracting jar using jar xf myjar.jar command through command prompt but it gave me only .class files and i want to generate .java files of my project through it.
I wanted to convert .java file to executable jar file,i did so in the command prompt. But everytime i double click (open) it nothing happens.
jar cf Calculate.jar Calculator.java
This is what i typed in the cmd. How to get an executable file? I use windows
That's not how it works, that way you are creating a jar archive with that .java file in it.
If you want to create the jar manually (if you want to do it one time, instead of using a build tool like ant or maven, it could have some educational value), you have to compile your .java file to a .class with javac, add it to the jar and then modify the META-INF/MANIFEST.MF manifest file to specify Calculator as value for the Main-Class attribute.
See this old guide from Sun.
I want to create one executable JAR file which contains other JAR libraries. But when I execute the JAR, it gives an error of class path problem.
How do I solve the class-path problem?
I think you can try it like this;
Here is a simple example for you question. First, we assume we have a project directory like D:\javademo. In this working directory we then create a main class HelloWorld.java and thtat contains our other JAR files, like commons-lang.jar. Now, we must archive our main classes HelloWorld and commons-lang.jar into test.jar file.
First we must edit our manifest file so that we can specify our class-path and main-class
like this:
Manifest-Version: 1.0
Created-By: tony example
Class-Path: test.jar commons-lang.jar
Main-Class: org.tony.java.HelloWorld
We named this file test.mf. Now we use the jar command to generate our JAR file like this:
jar -cvfm test.jar test.mf -C ./ .
Then it will generate the JAR file test.jar. You can use this command to run this main class using java command:
java -jar test.jar
That is my solution. I hope it give you something helpful...
You should use third-party libraries for it. For example, OneJar. You'll have to build the final JAR file using the OneJar tool (like Ant task) instead of standard JRE's tools.
On running such a JAR file, OneJar's service class is launched instead of yours. This class then loads JAR files packed inside, as well as your classes, and run your main class.
There are similar questions and answers already. For example: Stack Overflow question Easiest way to merge a release into one JAR file.
I am using jar -uf to update my MANIFEST.MF file like this:
a. jar xf jarfile.jar META-INF\MANIFEST.MF
b. edit the file
c. jar uf jarfile.jar META-INF\MANIFEST.MF
But the 'uf' command is removing MANIFEST.MF from within my jar.
What is the right way to change a file inside a jar (windows 7, jdk 1.6)?
You can always use winrar (or any equivalent) to open the jar, and drag/drop the files. worked for me.
For updating the manifest file the jar command provides different option -
jar umf manifest jar-file
The m option indicates that you want to update the JAR file's manifest.
manifest is the manifest whose contents you want to merge into the manifest of the existing JAR file.
examples # http://java.sun.com/developer/Books/javaprogramming/JAR/basics/update.html
There is a special option (m) for the manifest file: http://download.oracle.com/javase/1.4.2/docs/tooldocs/windows/jar.html
Could you try with
jar um jarfile.jar META-INF/MANIFEST.MF