Why does this doesnt work for transposing a matrix - pointers

Question

For some reason the element b[m][n] is a random number instead of being 1. The same thing happens if I try to printf a[n][m]. Please I need some help on this!
#include <stdio.h>
#include <stdlib.h>
void **alloc(int n,int m)
{
int **x=(int**)malloc(n*sizeof(int*));
for(int i=1; i<=n; i++)
x[i] =(int*)malloc(m*sizeof(int*));
return x ;
}
void read(int **a,int n,int m,FILE *f)
{
for(int i=1; i<=n; i++)
for(int j=1; j<=m; j++)
fscanf(f,"%d",&a[i][j]);
}
void print(int **a,int n,int m)
{
for(int i=1; i<=n; i++)
{
for(int j=1; j<=m; j++)
printf("%d ",a[i][j]);
printf("\n");
}
}
void transpose(int **a,int n,int m,int ***b)
{
for(int i=1; i<=n; i++)
for(int j=1; j<=m; j++)
b[j][i]=a[i][j];
}
int main()
{
int n,m;
FILE *f;
f=fopen("in.txt","r");
if(f==NULL)
printf("Error");
fscanf(f,"%d %d",&n,&m);
int **a=alloc(n,m);
read(a,n,m,f);
int **b=alloc(m,n);
transpose(a,n,m,b);
print(b,m,n);
return 0;
}
This is the input and output, everything works except the b[m][n] element

Answer 1

There are several issues:
If this is C code, casting the result of malloc is at best pointless and at worst dangerous, as it might hide bugs. (This does not apply for C++ code.)
Your "inner" malloc uses sizeof(int*), when it should be using sizeof(int).
Your alloc function returns void**, which is not wrong as such, but why not let it return int** instead?
This is the most important one: C array indexing starts at zero, so if you have an array of N elements, they are numbered 0 though N-1.