I need to pull the students data who is inactive for more than 2 continuous years.
Maybe something like:
SELECT EMPLID
, INSTITUTION
, ACAD_CAREER
, STDNT_CAR_NBR
, EFFDT
, PROG_STATUS
FROM %Table(ACAD_PROG) A
WHERE PROG_STATUS <> 'AC'
AND %EffdtCheck(acad_prog A2, A, %currentdatein)
AND EFFSEQ = (
SELECT MAX(EFFSEQ)
FROM %Table(ACAD_PROG) A3
WHERE A3.EMPLID=A.EMPLID
AND A3.ACAD_CAREER=A.ACAD_CAREER
AND A3.STDNT_CAR_NBR=A.STDNT_CAR_NBR
AND A3.EFFDT = A.EFFDT)
AND %DateDiff (A.EFFDT, %currentdatein) > 730
You might need to update the PROG_STATUS criteria to meet your needs, but the key is AND %DateDiff (A.EFFDT, %currentdatein) > 730
We compare the MAX(EFFDT) to today's date
Related
I have to create population for the people who has only one product association (ABC) using qualify statement.
For example I have the data
Id Code Prod Date
101 202 ABC 2017-05-31
101 203 DEF 2017-04-30
102 302 ABC 2018-06-30
From the above data I need the data for Id=102 because this id has only one prod relation where as id 101 has both ABC and DEF which should be excluded.
I tried the following
Select id,prod from table1
Qualify row_number() over (partition by id order by Date)=1
Where prod=‘ABC’
With this, I get the two records in my data which I don’t want. Appreciate your help.
Select *
from table1
Qualify min(Prod) over (partition by id)='ABC'
and max(Prod) over (partition by id)='ABC'
Both MIN and MAX return the same value ABC, thus there's no other value
If you want to return the id's that have one prod value (ABC) in the table, you can do something like this:
SELECT id, prod
FROM (
SELECT id, prod
FROM table1
GROUP BY id, prod -- Get unique (id, prod) combinations
QUALIFY COUNT(prod) OVER(PARTITION BY id) = 1 -- Get id's with only one prod
) src
WHERE prod = 'ABC' -- Only get rows with "ABC" prod
The key here is the order in which Teradata processes the query:
Aggregate - GROUP BY
OLAP - COUNT(prod) OVER()
QUALIFY
You may be able to move the WHERE prod = 'ABC' into the QUALIFY clause and get rid of the outer SELECT, not 100% sure.
Just use having, instead of qualify. I don't see any need for window fuctions. Something like:
Select id,prod ,
count(prod)
from
table1
group by
id,
prod
having count(prod) = 1
can some one help me...
I have to create,for each "Costumer", a iterator for a non-sequential ID to update the "version" column.
I need a cursor or something else?
Can i get some help?
Example:
ID COSTUMER VERSION
12 ANNA 1
24 ANNA 4
25 ANNA 5
60 ANNA 11
I want to correct the version to be sequential
You could use code something like this:
begin
for r in ( select id, row_number() over (partition by name order by version) as rn
from costumer
)
loop
update costumer
set version = r.rn
where id = r.id;
end loop;
end;
/
The partition by is there because I have assumed you want to have the sequence start from 1 for 'ANNA', then start from 1 again for customer 'JANE' etc. If not you can remove that part.
Here's the way to do it via a single MERGE statement:
MERGE INTO costumer tgt
USING (SELECT ID,
costumer,
VERSION,
ROWID row_id,
row_number() OVER (PARTITION BY costumer ORDER BY VERSION) new_version
FROM costumer) src
ON (tgt.rowid = src.rowid)
WHEN MATCHED THEN
UPDATE SET tgt.version = src.new_version;
The PROD_AMT I'd like to get is when ACCT_NBR, PROD_NBR And PROD_AMT are the same, I only need one PROD_AMT which is 100 (from distinct), and when ACCT_NBR are the same but PROD_NBR are different, then the PROD_AMT I need is 90 (30+60)
SELECT ACCT_NBR
,COUNT(DISTINCT CASE WHEN PROD_NBR = 1 THEN SUM(DISTINCT PROD_AMT)
WHEN PROD_NBR > 1 THEN SUM(PROD_AMT)
END) AS AMT
FROM TABLE
ACCT_NBR PROD_NBR PROD_AMT
3007 001 30
3007 002 60
1000 003 100
1000 003 100
There's probably a few ways to solve this. Using a subquery to determine which records should be summed vs which ones should be distinct, you could use:
SELECT
acct_nbr,
CASE WHEN sumflag = 'X' THEN SUM(prod_amt) ELSE MAX(prod_amt) END as amt
FROM
(
SELECT
acct_nbr,
prod_nbr,
prod_amt,
CASE WHEN COUNT(*) OVER (PARTITION BY Acct_nbr, prod_nbr, prod_amt) = 1 THEN 'X' ELSE NULL END AS sumflag
FROM
table
)t1
GROUP BY acct_nbr, sumflag
I'm just using MAX() here since it doesn't matter... all the values that will be aggregated with max() we know are duplicates, so it's a wash.
You could get similar results with a UNION query where one query would do the summing in the event that the records are distinct, and the other would just return distinct prod_amt's where the records are duplicates.
While the above example is nice if you truly have different aggregation needs depending on complex logic, for your question there's a simpler way of doing the same thing that doesn't use window functions:
SELECT
acct_nbr,
sum(prod_amt) AS amt
FROM
(
SELECT DISTINCT
acct_nbr,
prod_amt
FROM
table
)t1
GROUP BY 1
If you need to adapt this to a complex statement you could just sling your complex statement in as subquery where table is above like:
SELECT
acct_nbr,
sum(prod_amt) AS amt
FROM
(
SELECT DISTINCT
acct_nbr,
prod_amt
FROM
(
YOUR REALLY COMPLEX QUERY GOES IN HERE
)t2
)t1
GROUP BY 1
I have query that runs as part of a function which produces a one row table full of counts, and averages, and comma separated lists like this:
select
(select
count(*)
from vw_disp_details
where round = 2013
and rating = 1) applicants,
(select
count(*)
from vw_disp_details
where round = 2013
and rating = 1
and applied != 'yes') s_applicants,
(select
LISTAGG(discipline, ',')
WITHIN GROUP (ORDER BY discipline)
from (select discipline,
count(*) discipline_number
from vw_disp_details
where round = 2013
and rating = 1
group by discipline)) disciplines,
(select
LISTAGG(discipline_count, ',')
WITHIN GROUP (ORDER BY discipline)
from (select discipline,
count(*) discipline_count
from vw_disp_details
where round = 2013
and rating = 1
group by discipline)) disciplines_count,
(select
round(avg(util.getawardstocols(application_id,'1','AWARD_NAME')), 2)
from vw_disp_details
where round = 2013
and rating = 1) average_award_score,
(select
round(avg(age))
from vw_disp_details
where round = 2013
and rating = 1) average_age
from dual;
Except that instead of 6 main sub-queries there are 23.
This returns something like this (if it were a CSV):
applicants | s_applicants | disciplines | disciplines_count | average_award_score | average_age
107 | 67 | "speed,accuracy,strength" | 3 | 97 | 23
Now I am programmatically swapping out the "rating = 1" part of the where clauses for other expressions. They all work rather quickly except for the "rating = 1" one which takes about 90 seconds to run and that is because the rating column in the vw_disp_details view is itself compiled by a sub-query:
(SELECT score
FROM read r,
eval_criteria_lookup ecl
WHERE r.criteria_id = ecl.criteria_id
AND r.application_id = a.lgo_application_id
AND criteria_description = 'Overall Score'
AND type = 'ABC'
) reader_rank
So when the function runs this extra query seems to slow everything down dramatically.
My question is, is there a better (more efficient) way to run a query like this that is basically just a series of counts and averages, and how can I refactor to optimize the speed so that the rating = 1 query doesn't take 90 seconds to run.
You could choose to MATERIALIZE the vw_disp_details VIEW. That would pre-calculate the value of the rating column. There are various options for how up-to-date a materialized view is kept, you would probably want to use the ON COMMIT clause so that vw_disp_details is always correct.
Have a look at the official documentation and see if that would work for you.
http://docs.oracle.com/cd/B28359_01/server.111/b28286/statements_6002.htm
Do all most of your queries in only one. Instead of doing:
select
(select (count(*) from my_tab) as count_all,
(select avg(age) from my_tab) as avg_age,
(select avg(mypkg.get_award(application_id) from my_tab) as_avg-app_id
from dual;
Just do:
select count(*), avg(age),avg(mypkg.get_award(application_id)) from my_tab;
And then, maybe you can do some union all for the other results. But this step all by itself should help.
I was able to solve this issue by doing two things: creating a new view that displayed only the results I needed, which gave me marginal gains in speed, and in that view moving the where clause of the sub-query that caused the lag into the where clause of the view and tacking on the result of the sub-query as column in the view. This still returns the same results thanks to the fact that there are always going to be records in the table the sub-query accessed for each row of the view query.
SELECT
a.application_id,
util.getstatus (a.application_id) status,
(SELECT score
FROM applicant_read ar,
eval_criteria_lookup ecl
WHERE ar.criteria_id = ecl.criteria_id
AND ar.application_id = a.application_id
AND criteria_description = 'Overall Score' //THESE TWO FIELDS
AND type = 'ABC' //ARE CRITERIA_ID = 15
) score
as.test_total test_total
FROM application a,
applicant_scores as
WHERE a.application_id = as.application_id(+);
Became
SELECT
a.application_id,
util.getstatus (a.application_id) status,
ar.score,
as.test_total test_total
FROM application a,
applicant_scores as,
applicant_read ar
WHERE a.application_id = as.application_id(+)
AND ar.application_id = a.application_id(+)
AND ar.criteria_id = 15;
I need some help to build SQL Query. I have table having data like:
ID Date Name
1 1/1/2009 a
2 1/2/2009 b
3 1/3/2009 c
I need to get result something like...
1 1/1/2009 a
2 1/2/2009 b
3 1/3/2009 c
4 1/4/2009 Null
5 1/5/2009 Null
6 1/6/2009 Null
7 1/7/2009 Null
8 1/8/2009 Null
............................
............................
............................
30 1/30/2009 Null
31 1/31/2009 Null
I want query something like..
Select * from tbl **where month(Date)=1 AND year(Date)=2010**
Above is not completed query.
I need to get all the record of particular month, even if some date missing..
I guess there must be equi Join in the query, I am trying to build this query using Equi join
Thanks
BIG EDIT
Now understand the OPs question.
Use a common table expression and a left join to get this effect.
DECLARE #FirstDay DATETIME;
-- Set start time
SELECT #FirstDay = '2009-01-01';
WITH Days AS
(
SELECT #FirstDay as CalendarDay
UNION ALL
SELECT DATEADD(d, 1, CalendarDay) as CalendarDay
FROM Days
WHERE DATEADD(d, 1, CalendarDay) < DATEADD(m, 1, #FirstDay)
)
SELECT DATEPART(d,d.CalendarDay), **t.date should be (d.CalendarDay)**, t.Name FROM Days d
LEFT JOIN tbl t
ON
d.CalendarDay = t.Date
ORDER BY
d.CalendarDay;
Left this original answer at bottom
You need DATEPART, sir.
SELECT * FROM tbl WHERE DATEPART(m,Date) = 1
If you want to choose month and year, then you can use DATEPART twice or go for a range.
SELECT * FROM tbl WHERE DATEPART(m,Date) = 1 AND DATEPART(yyyy,Date) = 2009
Range :-
SELECT * FROM tbl WHERE Date >= '2009-01-01' AND Date < '2009-02-01'
See this link for more info on DATEPART.
http://msdn.microsoft.com/en-us/library/ms174420.aspx
You can use less or equal to.
Like so:
select * from tbl where date > '2009-01-01' and date < '2009-02-01'
However, it is unclear if you want month 1 from all years?
You can check more examples and functions on "Date and Time Functions" from MSDN
Create a temporary table containing all days of that certain month,
Do left outer join between that table and your data table on tempTable.month = #month.
now you have a big table with all days of the desired month and all the records matching the proper dates + empty records for those dates who have no data.
i hope that's what you want.