Hello i have a data frame with more than 3632200+ obs, and I'm trying to find some useful information out of it. I have cleaned it a bit so now this is what the data looks like
Order Lane Days
18852324 796005 - Ahmedabad 2
232313 796008 - Delhi 5
63963231 796005 - Ahmedabad 5
23501231 788152 - Chennai 1
2498732 796008 - Delhi 2
231413 796005 - Ahmedabad 3
75876876 796012 - Chennai 4
14598676 796008 - Delhi 4
Order are different Order Id's, they all are unique, Lane are different paths on which the order was delivered(Lanes can repeat for various orders) & Days is calculated using difftime function in R by differentiating Order delivered and created date.
Now What I'm trying to achieve is something like this
Now I can calculate 98.% order achieved date by using quantile function in R across various lane.
But how do I achieve % of orders fulfilled by day 1 to 5 across various lanes?
Any help would be highly appreciated.
Thank You
Hard to tell without the data, but maybe something like this:
library(purrr)
#df = your data
max_days = max(df$days)
aggregate_fun = function(x){
days = factor(x$days,levels=c(1:max_days))
prop.table(table(days))
}
df = split(df,df$lane)
results = reduce(lapply(df,aggregate_fun),rbind)
Related
I am working on a project for school in R that is looking at swimming data compiled up of 8 different teams looking at each of the 13 events, over 6 years. I have over 8700 rows of data that I have appended and am trying to find out how to draw the specific means that I am looking for. For example, I would like to look at the progression of mean times for team 1 for event 3 for men. Thanks!
You can subset your data-frame to only include those variables, e.g.
ss = subset(df, team == 1 & event == 3)
mean(ss$times)
just earlier today I received a very helpful answer for a problem I was running into that allowed me to move onto the next step of one of my projects. However, I got stuck again later on in the project, and I'm wondering if any of you can help me move forward.
Context
Currently, I have a list of data frames that are full of soccer matches called wc_match_dataframes. Here is what one of the data frames looks like:
type_id tourn_id day month year team_A score_A score_B team_B win loss
f wc_1934 27 5 1934 Germany 5 2 Belgium Germany Belgium
I wasn't able to fit the data for the final three columns, draw, drawA, and drawB but basically the draw column is TRUE if the match is a draw, if not, it is FALSE. In the case of a draw, the win and loss columns are just filled by Draw. The drawA column is filled by team_A if the match was a draw, and likewise, the drawB column is filled by team_B.
The type_id is either f or q depending on if the match was a World Cup qualifier or a World Cup finals match. The tourn_id refers to the tournament the match was for, whether it was a qualifier or finals.
There are a total of 39 of these data frames, with a "finals" data frame for each of the 20 World Cup tournaments, and a "qualifiers" data frame for 19 tournaments (the first World Cup did not have qualifying).
What I Want To Do
I'm trying to populate a different list of data frames wc_dataframes with data for each of the 20 World Cups at the country level as opposed to the match level. Each of these twenty data frames will have the countries that made it to the finals of said tournament and their data like so:
Country
Wins in qualifying
Wins in finals
Losses in qualifying
Losses in finals
... and so on.
I have been able to populate the first country column for every World Cup no problem, but I'm running into issues for the rest of the columns.
Here is what I'm doing
This is the unlooped (only works for one World Cup) version of my code that works successfully:
wc_dataframes$wc_1930$fw <- apply(wc_dataframes$wc_1930, MARGIN = 1, function(country)
sum(wc_match_dataframes$`wc_1930 f`$w == country, na.rm = TRUE))
This is successfully populating the finals win column in the wc_dataframes$wc_1930 data frame by counting the number of wins.
Now, when I try and nest this under lapply to do it across all World Cup years like so:
lapply(names(wc_dataframes), function(year)
wc_dataframes$year$fw <- apply(wc_dataframes$year, MARGIN = 1, function(country)
sum(wc_match_dataframes$`year f`$w == country, na.rm = TRUE)))
It does not work for me. I suspect that the issue has to do with defining the year function and running into issues in the sum portion of my code. I come from a background in STATA so I am more used to running for loops and what not. I'm still getting used to R and lists and everything so I really appreciate the help.
Thank you!
Thank you so much in advance for the help, and happy holidays! :)
What you need is to output whatever you have replaced:
lapply(names(wc_dataframes), function(year){
wc_dataframes[[year]]$fw <- apply(wc_dataframes[[year]], MARGIN = 1, function(country)
sum(wc_match_dataframes[[paste(year,'f')]]$w == country, na.rm = TRUE));
wc_dataframes}
)
I'm quite a newbie in R so I was interested in the optimality of my solution. Even if it works it could be (a bit) long and I wanted your advice to see if the "way I solved it" is "the best" and it could help me to learn new techniques and functions in R.
I have a dataset on students identified by their id and I have the school where they are matched and the score they obtained at a specific test (so for short: 3 variables id,match and score).
I need to construct the following table: for students in between two percentiles of score, I need to calculate the average score (between students) of the average score of the students of the school they are matched to (so for each school I take the average score of the students matched to it and then I calculate the average of this average for percentile classes, yes average of a school could appear twice in this calculation). In English it allows me to answer: "A student belonging to the x-th percentile in terms of score will be in average matched to a school with this average quality".
Here is an example in the picture:
So in that case, if I take the median (15) for the split (rather than percentiles) I would like to obtain:
[0,15] : 9.5
(15,24] : 20.25
So for students having a score between 0 and 15 I take the average of the average score of the school they are matched to (note that b average will appears twice but that's ok).
Here how I did it:
match <- c(a,b,a,b,c)
score <- c(18,4,15,8,24)
scoreQuant <- cut(score,quantile(score,probs=seq(0,1,0.1),na.rm=TRUE))
AvgeSchScore <- tapply(score,match,mean,na.rm=TRUE)
AvgScore <- 0
for(i in 1:length(score)) {
AvgScore[i] <- AvgeSchScore[match[i]]
}
results <- tapply(AvgScore,scoreQuant,mean,na.rm = TRUE)
If you have a more direct way of doing it.. Or I think the bad point is 3) using a loop, maybe apply() is better ? But I'm not sure how to use it here (I tried to code my own function but it crashed so I "bruted force it").
Thanks :)
The main fix is to eliminate the for loop with:
AvgScore <- AvgeSchScore[match]
R allows you to subset in ways that you cannot in other languages. The tapply function outputs the names of the factor that you grouped by. We are using those names for match to subset AvgeScore.
data.table
If you would like to try data.table you may see speed improvements.
library(data.table)
match <- c("a","b","a","b","c")
score <- c(18,4,15,8,24)
dt <- data.table(id=1:5, match, score)
scoreQuant <- cut(dt$score,quantile(dt$score,probs=seq(0,1,0.1),na.rm=TRUE))
dt[, AvgeScore := mean(score), match][, mean(AvgeScore), scoreQuant]
# scoreQuant V1
#1: (17.4,19.2] 16.5
#2: NA 6.0
#3: (12.2,15] 16.5
#4: (7.2,9.4] 6.0
#5: (21.6,24] 24.0
It may be faster than base R. If the value in the NA row bothers you, you can delete it after.
First of all, I apologize for the title. I really don't know how to succinctly explain this issue in one sentence.
I have a dataframe where each row represents some aspect of a hospital visit by a patient. A single patient might have thousands of rows for dozens of hospital visits, and each hospital visit could account for several rows.
One column is Medical.Record.Number, which corresponds to Patient IDs, and the other is Patient.ID.Visit, which corresponds to an ID for an individual hospital visit. I am trying to calculate the number of hospital visits each each patient has had.
For example:
Medical.Record.Number Patient.ID.Visit
AAAXXX 1111
AAAXXX 1112
AAAXXX 1113
AAAZZZ 1114
AAAZZZ 1114
AAABBB 1115
AAABBB 1116
would produce the following:
Medical.Record.Number Number.Of.Visits
AAAXXX 3
AAAZZZ 1
AAABBB 2
The solution I am currently using is the following, where "data" is my dataframe:
#this function returns the number of unique hospital visits associated with the
#supplied record number
countVisits <- function(record.number){
visits.by.number <- data$Patient.ID.Visit[which(data$Medical.Record.Number
== record.number)]
return(length(unique(visits.by.number)))
}
recordNumbers <- unique(data$Medical.Record.Number)
visits <- integer()
for (record in recordNumbers){
visits <- c(visits, countVisits(record))
}
visit.counts <- data.frame(recordNumbers, visits)
This works, but it is pretty slow. I am dealing with potentially millions of rows of data, so I'd like something efficient. From what little I know about R, I know there's usually a faster way to do things without using a for-loop.
This essentially looks like a table() operation after you take out duplicates. First, some sample data
#sample data
dd<-read.table(text="Medical.Record.Number Patient.ID.Visit
AAAXXX 1111
AAAXXX 1112
AAAXXX 1113
AAAZZZ 1114
AAAZZZ 1114
AAABBB 1115
AAABBB 1116", header=T)
then you could do
tt <- table(Medical.Record.Number=unique(dd)$Medical.Record.Number)
as.data.frame(tt, responseName="Number.Of.Visits") #to get a data.frame rather than named vector (table)
# Medical.Record.Number Number.Of.Visits
# 1 AAABBB 2
# 2 AAAXXX 3
# 3 AAAZZZ 1
Or you could also think of this as an aggregation problem
aggregate(Patient.ID.Visit~Medical.Record.Number, dd, function(x) length(unique(x)))
# Medical.Record.Number Patient.ID.Visit
# 1 AAABBB 2
# 2 AAAXXX 3
# 3 AAAZZZ 1
There are many ways to do this, #MrFlick provided handful of perfectly valid approaches. Personally I'm fond of the data.table package. Its faster on large data frames and I find the logic to be more intuitive than the base functions. I'd check it out if you are having problems with execution time.
library(data.table)
med.dt <- data.table(med_tbl)
num.visits.dt <- med.dt[ , num_visits = length(unique(Patient.ID.Visit)),
by = Medical.Record.Number]
data.Table should be much faster than data.frame on a large tables.
I have a rather large dataframe with 13 variables. Here is the first line just to give an idea:
prov_code nuts1 nuts1name nuts2 nuts2name prov_geoorder prov_name NUTS_ID EDAD year ORDER graphs value prov_geo
1. 15 1 NW 11 Galicia 1 La Corunna ES111 11 1975 1 1 0.000000000 La Corunna
I would like to obtain the maximum for a certain set of variables according to a combination of variables year ORDER and prov_code (ie, f_all being my data.frame: f_all[(f_all$year==1975)&(f_all$ORDER==1)&(f_all$prov_code=="1"),] ). The goal is to repeat the operation in order to obtain a new data frame containing all the maximum values for each year, ORDER, prov_code.
Is there a simple and quick way to do this?
Thanks for any suggestion on the matter,
There are several way of doing this, for example the one #James mentions. I want to suggest using plyr:
library(ply)
ddply(f_all, .(year, ORDER, prov_code), summarise, mx_value = max(value))
Alternatively, if you have a lot of data, data.table provides similar functionality, but is much much faster in that case.