Multiple sorting on tables - google-app-maker

I have 2 tables, which has one - many relation ship. The child table has 4 columns (Let say, A, B, C, D)
A - Table column
B - Foreign key column
C - Foreign key column
D - Table column
Requirement is to sort the data by A, B,then by C when displaying records
I tried with query script but not working. (Relation data source doesn't load)
I tried with specifying the sort field on Relations tab (Sorting work only for table column, fk columns are not displayed)
Is there a way to do this?

Related

How to make a dynamic, calculated column? (Swift, SQLite)

How i can to make a dynamic, calculated column? Which is calculated using other columns and not stored in the database.
Which can be used for data output and sorting.
Library: stephencelis/SQLite.swift (https://github.com/stephencelis/SQLite.swift)
Example:
SELECT a+b as c from test ORDER BY c ASC;
Thanks.
With sqlite 3.31.0 and newer, you can use a generated column.
CREATE TABLE test(a INTEGER, b INTEGER,
c INTEGER GENERATED ALWAYS AS (a + b) VIRTUAL);
Or use a view:
CREATE TABLE real_test(a INTEGER, b INTEGER);
CREATE VIEW test AS
SELECT a, b, a + b AS c FROM real_test;

Copy record from one table to another which has one more column

TABLE one:
A B C
TABLE two:
A B D C
As you can see column D was added to the middle.
How to copy record from table one to table two setting value D to default.
Don't use D in the list of columns of Table2:
INSERT INTO Table2(A, B, C)
SELECT A, B, C FROM Table1
Maybe you need a WHERE clause also if you want to copy a specific row only.
D will get its default value, if there is one defined in the CREATE statement of Table2, or null if there isn't a default value.

Group by ranges in SQLite

I have a SQLite table which contains a numeric field field_name. I need to group by ranges of this column, something like this: SELECT CAST(field_name/100 AS INT), COUNT(*) FROM table GROUP BY CAST(field_name/100 AS INT), but including ranges which have no value (COUNT for them should be 0). And I can't get how to perform such a query?
You can do this by using a join and (though kludgy) an extra table.
The extra table would contain each of the values you want a row for in the response to your query (this would not only fill in missing CAST(field_name/100 AS INT) values between your returned values, but also let you expand it such that if your current groups were 5, 6, 7 you could include 0 through 10.
In other flavors of SQL you'd be able to right join or full outer join, and you'd be on your way. Alas, SQLite doesn't offer these.
Accordingly, we'll use a cross join (join everything to everything) and then filter. If you've got a relatively small database or a small number of groups, you're in good shape. If you have large numbers of both, this will be a very intensive way to go about this (the cross join result will have #ofRowsOfData * #ofGroups rows, so watch out).
Example:
TABLE: groups_for_report
desired_group
-------------
0
1
2
3
4
5
6
Table: data
fieldname other_field
--------- -----------
250 somestuff
230 someotherstuff
600 stuff
you would use a query like
select groups_for_report.desired_group, count(data.fieldname)
from data
cross join groups_for_report
where CAST(fieldname/100.0 AS INT)=desired_group
group by desired_group;

Advanced SQLite Update table query

I am trying to update Table B of a database looking like this:
Table A:
id, amount, date, b_id
1,200,6/31/2012,1
2,300,6/31/2012,1
3,400,6/29/2012,2
4,200,6/31/2012,1
5,200,6/31/2012,2
6,200,6/31/2012,1
7,200,6/31/2012,2
8,200,6/31/2012,2
Table B:
id, b_amount, b_date
1,0,0
2,0,0
3,0,0
Now with this query I get all the data I need in one select:
SELECT A.*,B.* FROM A LEFT JOIN B ON B.id=A.b_id WHERE A.b_id>0 GROUP BY B.id
id, amount, date, b_id, id, b_amount, b_date
1,200,6/31/2012,1,1,0,0
3,400,6/29/2012,1,1,0,0
Now, I just want to copy the selected column amount to b_amount and date to b_date
b_amount=amount, b_date=date
resulting in
id, amount, date, b_id, id, b_amount, b_date
1,200,6/31/2012,1,1,200,6/31/2012
3,400,6/29/2012,1,1,400,6/29/2012
I've tried COALESCE() without success.
Does someone experienced have a solution for this?
Solution:
Thanks to the answers below, I managed to come up with this. It is probably not the most efficient way but it is fine for a one time only update. This will insert for you the first corresponding entry of each group.
REPLACE INTO A SELECT id, amount, date FROM
(SELECT A.id, A.amount, B.id as Bid FROM A INNER JOIN B ON (B.id=A.B_id)
ORDER BY A.id DESC)
GROUP BY Bid;
So what you are looking for seems to be a JOIN inside of an UPDATE query. In mySQL you would use
UPDATE B INNER JOIN A ON B.id=A.b_id SET B.amount=A.amount, B.date=A.date;
but this is not supported by sqlite as this probably related question points out. However, there is a workaround using REPLACE:
REPLACE INTO B
SELECT B.id, A.amount, A.date FROM A
LEFT JOIN B ON B.id=A.b_id
WHERE A.b_id>0 GROUP BY B.id;
The query will simply fill in the values of table B for all columns which should keep their state and fill in the values of table A for the copied values. Make sure the order of the columns in the SELECT statement meet your column order of table B and all columns are mentioned or you will loose these field's data. This is probably dangerous for future changes on table B. So keep in mind to change the column order/presence of this query when changing table B.
Something a bit off topic, because you did not ask for that: A.b_id is obviously a foreign key to B.id. It seems you are using the value 0 for the foreign key to express that there is no corresponding entry in B. (Inferred from your SELECT with WHERE A.b_id>0.) You should consider using the null value for that. When you are using INNER JOIN then instead of LEFT JOIN you can drop the WHERE clause entirely. The DBS will then sort out all unsatisfied relations.
WARNING Some RDBMS will return 2 rows as you show above. Others will return the Cartesian product of the rows i.e. A rows times B rows.
One tricky method is to generate SQL that is then executed
SELECT "update B set b.b_amount = ", a.amount, ", b.b_date = ", a.date,
" where b.id = ", a.b_id
FROM A LEFT JOIN B ON B.id=A.b_id WHERE A.b_id>0 GROUP BY B.id
Now add the batch terminator and execute this SQL. The query result should look like this
update B set b.b_amount = 200, b.b_date = 6/31/2012 where b.id = 1
update B set b.b_amount = 400, b.b_date = 6/29/2012 where b.id = 3
NOTE: Some RDBMS will handle dates differently. Some require quotes.

How do I write a query that bridges two tables?

I have two tables, two differently name columns in these tables match up.
Table A:
a
b
c
d
e
Table B:
f
g
h
I need to display a grid view of e, g and h, Joining the tables together based on the f and b matching up. I know how to fill a grid view based on a query, its just the query itself I'm after.
Since all of your columns are uniquely named, and you are joining two different tables, no aliasing is necessary, and you don't need to fully qualify the column names.
The SQL term you are looking for is a JOIN. In this case, it sounds like you want an inner join (there are many ways to write them).
SELECT
e,g,h
FROM
TableA
INNER JOIN TableB
ON b = f
You used the very words in your question: "joining the tables together based on the f and b matching up".
SELECT e,g,h FROM `Table A` JOIN `Table B` ON f=b
I think it might be:
SELECT e,g,h FROM Table A, Table B WHERE Table A.b == Table B.f
That's the JOIN I would use. It may need tweaked depending on what your variables are.
Sorry, this works for SQL not MYSQL.

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