XQuery switch testing node - xquery

Question

In XQuery 3.1 this (test) query checks for the presence of certain nodes by checking the name():
declare variable $doc :=
doc("/db/apps/deheresi/data/ms609_0013.xml"));
let $ele := $doc//tei:sic | $doc//tei:surplus
for $n in $ele
let $output := switch ($n/name())
case ("sic")
return ($n)
case ("surplus")
return ($n)
default return ""
return $output
Returns the following XML correctly:
<surplus reason="surplus">die</surplus>
<surplus reason="repeated">et Raimundum de las de Recaut</surplus>
Now, when I want to run my actual query againt the same document, to test for a node to produce HTML, it does not find the same tei:surplus:
declare variable $doc :=
doc("/db/apps/deheresi/data/ms609_0013.xml"));
let $ele := $doc//tei:sic | $doc//tei:surplus
for $n in $ele
let $output := switch ($n)
case ($n/self::tei:sic)
return (<span class="inter">
<i>ms. </i>
{$n/tei:orig/text()}
</span>,
<span class="diplo">
<i>corr. </i>
{$n/tei:corr/text()}
</span>)
case ($n/self::tei:surplus[#reason="surplus"])
return (<span><i>supp.</i>{$n/text()}</span>)
case ($n/self::tei:surplus[#reason="repeated"])
return (<span><i>supp. (dup.)</i>{$n/text()}</span>)
default return ""
return $output
Is there something wrong with the way I'm testing the node on case that it does not find tei:surplus in the very same document?
NB: when I do the same for a document that contains the first case (tei:sic), it outputs fine. Evidently the test in principle should work!
Thanks in advance.

Answer 1

The switch construct compares atomic values. You could use it like this:
switch (node-name($n))
case QName("http://tei-namespace/", "sic") return <something/>
Note the use of node-name() rather than name() to avoid any dependency on namespace prefixes.
But it's probably better to use typeswitch:
typeswitch ($n)
case element(tei:sic) return <something/>