I created a triangle like so using css:
.box {
width: 0;
height: 0;
border-style: solid;
border-width: 540px 964px 540px 0;
border-color: transparent #007bff transparent transparent;
}
But I am trying to make my triangle look like this:
My question is how do I make the top and bottom more edge to edge?
You could use :after pseudo element to create one square and then use rotate and translate transforms.
.element {
display: inline-block;
background: lightgreen;
position: relative;
width: 200px;
height: 200px;
overflow: hidden;
}
.two {
margin-left: 30px;
width: 300px;
height: 300px;
}
.element:after {
content: "";
position: absolute;
width: 120%;
height: 120%;
background: #30373F;
transform: rotate(45deg) translate(10%, -20%);
}
<div class="element"></div>
<div class="element two"></div>
You can easily do this with gradient:
.box {
width:200px;
height:200px;
background:
linear-gradient(red,red) right/30% 100%,
linear-gradient(to top left,red 49.8%,transparent 50%) top left/70% 50%,
linear-gradient(to bottom left,red 49.8%,transparent 50%) bottom left/70% 50%,
url(https://picsum.photos/600/600?image=1069) center/cover;
background-repeat:no-repeat;
}
<div class="box">
</div>
Related
Hi i am trying to make the following:
They triangles should be about 40% in height of the container, and 50% in width, so they meet in the middle.
I have been trying to make something similar.. but unsuccessfull so far..
And looking around, i have found nothing i could use so far.
my code:
div {
height: 373px;
width: 0px;
margin: 26px;
display: inline-block;
}
.left {
border-bottom: 100px solid #ff0;
border-left: 320px solid transparent;
}
.right {
border-bottom: 100px solid #f00;
border-right: 320px solid transparent;
}
header {
border: 2px solid black;
width: 50%;
height: 500px;
}
<header>
<div class="right"></div>
<div class="left"></div>
</header>
hoping for someone smarter than me to see where i should go from here...
Use background coloration like below:
.box {
height:300px;
background:
/* Right bottom triangle*/
linear-gradient(to bottom right,transparent 49.5%,blue 50%) bottom right,
/* left bottom triangle*/
linear-gradient(to bottom left ,transparent 49.5%,red 50%) bottom left ,
yellow;
background-size:50% 40%; /* Width height*/
background-repeat:no-repeat;
}
<div class="box">
</div>
Related answer for more details: How do CSS triangles work?
Another idea with pseudo elements (that you can replace with common elements) in case you want to have different elements.
.box {
height: 300px;
background: yellow;
position: relative
}
.box:before,
.box:after {
content: "";
position: absolute;
height: 40%;
width: 50%;
bottom: 0;
}
.box:before {
left: 0;
background: linear-gradient(to bottom left, transparent 49.5%, red 50%);
}
.box:after {
right: 0;
background: linear-gradient(to bottom right, transparent 49.5%, blue 50%);
}
<div class="box">
</div>
Since you need percent values, you can use clip-path. Beware that it may not be supported fully on some browser https://caniuse.com/#feat=css-clip-path and for some you may need prefixes (e.g. -webkit-clip-path)
.wrap {
height: 200px;
width: 100%;
position: relative;
background: #333;
}
.triangle {
background: red;
clip-path: polygon(0 40%, 0% 100%, 100% 100%);
position: absolute;
left: 0;
bottom: 0;
top: 0;
width: 50%;
}
.triangle.tr-right {
left: auto;
right: 0;
clip-path: polygon(100% 40%, 0% 100%, 100% 100%);
}
<div class="wrap">
<div class="triangle tr-left"></div>
<div class="triangle tr-right"></div>
</div>
JSFiddle
Clip-path created with Clippy
* {
box-sizing: border-box;
}
.triangular-pointer-box {
display: flex;
align-items: center;
background: #161616;
padding: 20px;
padding-left: 120px;
height: 200px;
position: relative;
width: 80%;
}
.triangular-pointer-box > h3 {
color: #fff;
}
.triangular-pointer-box:after {
content: "";
width: 0;
height: 0;
border-top: 100px solid transparent;
border-bottom: 100px solid transparent;
border-left: 100px solid #161616;
position: absolute;
right: -100px;
top: 0;
}
.triangular-pointer-box:before {
content: "";
width: 0;
height: 0;
border-top: 100px solid transparent;
border-bottom: 100px solid transparent;
border-left: 100px solid #ffffff;
position: absolute;
left: 0;
top: 0;
}
<div class="triangular-pointer-box">
<h3>Title goes here</h3>
</div>
I ran into a little css problem. I'm trying to get skewed edges for a headline, which also workes for multiple lines (see in added screen). Important: The skewed edge should appear on every single line.
I already tried following solutions which didn't work 100%:
:after, :before Elements as Triangles or parallelogram (https://css-tricks.com/examples/ShapesOfCSS/)
.element {
background: red;
line-height: 30px;
width: 100px;
margin-right: 50px;
position: relative;
display: inline-block;
clear: both;
}
.element:after {
background: #f00;
content: "";
display: block;
height: 100%;
transform: skew(-20deg);
position: absolute;
right: -5px;
top: 0;
width: 30px;
}
<div class="element">Headline 1</div>
<div class="element">Headline 2 veeery long</div>
--> doesn't work for multiple line because it needs to meet the bottom-right top-left corner
Multi-Line Padded Text (https://css-tricks.com/multi-line-padded-text/) with skewed edges
--> doesn't work to make it skewed on the edges without pseudo-element. same problem like above.
Can you help me with a solution for this problem?
This should work with display inline:
body {
background: black;
}
div {
max-width: 300px;
}
h1 {
line-height: 46px;
color: #fff;
background-image: linear-gradient(110deg, transparent 50%, red 53%), linear-gradient(110deg, red 50%, transparent 53%), linear-gradient(to left, red, red);
background-size: 16px 100%, 16px 100%, calc(100% - 32px) 100%;
background-position: left, right, center;
background-repeat: no-repeat;
display: inline;
padding: 0 16px;
-webkit-box-decoration-break: clone;
box-decoration-break: clone;
}
<div><h1>Some dynamic text on several lines with no special meaning...</h1></div>
No Edge support for now as "box-decoration-break" is not supported (yet?).
Hope this helps you out. Here just applied linear gradient to in before and after element and positioned them absolute. Its height will increase according to the height of relative div.
In case you want to increase the curved area you just need to update width and position them left and right as per the amount of given width. As done in example.
.element {
line-height: 30px;
width: 100px;
margin-right: 50px;
position: relative;
display: inline-block;
clear: both;
psdding: 10px;
background: #f00;
padding: 10px;
}
.element:after, .element:before {
content: "";
width: 10px;
position:absolute;
height: 100%;
}
.element:before {
top: 0px; background: linear-gradient(to top left, #ff0000 50%, transparent 50%);
left: -10px;
}
.element:after {
top: 0px; background: linear-gradient(to bottom right, #ff0000 50%, transparent 50%);
right: -10px;
}
<div class="element">Headline 1</div>
<div class="element">Headline 2 veeery long</div>
Looking at you link provided,
This according to me is best answer... ( hope so )
Increasing the element width as I did in below code snippet ,
width: 200px;
Will work fine with the way you want Sample Here
View Code snippet in full screen
.element {
background: red;
line-height: 30px;
padding : 10px ;
width: 200px;
position: relative;
display: inline-block;
clear: both;
}
.element:after {
background: #f00;
content: "";
display: block;
height: 100%;
transform: skew(-10deg);
position: absolute;
right: -5px;
top: 0;
width: 50px;
}
.element:before {
background: #f00;
content: "";
display: block;
height: 100%;
transform: skew(-10deg);
position: absolute;
left: -5px;
top: 0;
width: 10px;
}
<div class="element">Headline 1</div>
<div class="element">Headline 2 veeery long</div>
<div class="element">Headline</div>
<div class="element">Another Headline</div>
You can use multiple background and rely on the repeat:
.element {
background: red;
margin:10px;
line-height: 30px;
width: 100px;
padding:0 30px;
display: inline-block;
position:relative;
background:
linear-gradient(to bottom right,red 50%,transparent 0)100% 0/30px 30px repeat-y,
linear-gradient(to top left,red 50%,transparent 0)0 0/30px 30px repeat-y,
linear-gradient(red,red)30px 0/calc(100% - 60px) 100% no-repeat;
}
<div class="element">Headline 1</div>
<div class="element">Headline 2 veeery long</div>
<div class="element">Headline 2 veeery long veeery long veeery long</div>
I want to cut left top corner of a box using CSS like this.
keep in mind that background is transparent.
Nearly the same solution as OriDrori's answer but more flexible (if you need fixed-width cutted corner).
This gradient will look the same regardless of .card width and height.
body {
background: purple;
}
.card {
width: 200px;
height: 200px;
background: linear-gradient(135deg, transparent 20px, white 20px);
}
<div class="card"></div>
You can use a simple linear gradient for that:
body {
background: purple;
}
.card {
width: 200px;
height: 200px;
background: linear-gradient(to bottom right, transparent 5%, white 5%);
}
<div class="card"></div>
You can use clip-path
https://developer.mozilla.org/en/docs/Web/CSS/clip-path
and use something like this:
div#test{
background:red;
width:200px;
height: 200px;
-webkit-clip-path: polygon(22% 0, 100% 0, 100% 100%, 0 100%, 0 20%);
clip-path: polygon(22% 0, 100% 0, 100% 100%, 0 100%, 0 20%);
}
<div id="test"></div>
With a pseudo and transform you can do that, and it has good browser support (from IE9)
body {
background: url(https://picsum.photos/400/300) center / cover;
}
div {
position: relative;
width: 200px;
height: 200px;
overflow: hidden;
}
div::before {
content: '';
position: absolute;
left: calc(50% + 25px); /* 25px is height/width of the cut */
top: calc(50% + 25px);
width: 141.5%;
height: 141.5%;
transform: translate(-50%,-50%) rotate(45deg);
background: #eee;
opacity: 0.8;
}
<div></div>
As pointed out, if you need it to scale on different aspect ratio's, use this
body {
background: url(https://picsum.photos/400/300) center / cover;
}
div {
position: relative;
width: 80vw;
height: 80vh;
overflow: hidden;
}
div::before {
content: '';
position: absolute;
left: 0;
top: 0;
width: 1000%;
height: 5000%;
transform: rotate(45deg) translate(25px,-50%); /* 25px for the cut height/width */
transform-origin: left top;
background: #eee;
opacity: 0.8;
}
<div></div>
I am currently using CSS3 to make an div with the left side angled like a trapezium using the following CSS adapted from this jsfiddle:
background:linear-gradient(75deg, transparent 75px, #35753f 76px);
I would like to combine the following CSS background with a radial one, to create the effect shown in the image below. However, when I do this, I lose the angled side. What is the best way to combine these two backgrounds?
Here is the radial background:
background:radial-gradient(circle closest-corner at right center, #337540 0%, #003832 100%);
Here is what it should look like:
Here is a jsfiddle of the below:
.container {
width: 1024px;
margin: 0 auto;
}
.clearfix:after {
content: ".";
display: block;
height: 0;
clear: both;
visibility: hidden;
}
#top-banner {
position: relative;
}
#top-banner .container {
height: 350px;
}
#top-banner #banner-right {
width: 350px;
height: 350px;
background: -moz-linear-gradient(75deg, transparent 75px, #35753f 76px);
background: -o-linear-gradient(75deg, transparent 75px, #35753f 76px);
background: -webkit-linear-gradient(75deg, transparent 75px, #35753f 76px);
background: linear-gradient(75deg, transparent 75px, #35753f 76px);
position: relative;
float: right;
}
#top-banner #banner-right:after {
content: ".";
display: block;
height: inherit;
width: 5000px;
left: 350px;
top: 0;
position: absolute;
/* IE10 Consumer Preview */
background-image: -ms-radial-gradient(left center, circle closest-corner, #337540 0%, #003832 100%);
/* Mozilla Firefox */
background-image: -moz-radial-gradient(left center, circle closest-corner, #337540 0%, #003832 100%);
/* Opera */
background-image: -o-radial-gradient(left center, circle closest-corner, #337540 0%, #003832 100%);
/* Webkit (Safari/Chrome 10) */
background-image: -webkit-gradient(radial, left center, 0, left center, 140, color-stop(0, #337540), color-stop(1, #003832));
/* Webkit (Chrome 11+) */
background-image: -webkit-radial-gradient(left center, circle closest-corner, #337540 0%, #003832 100%);
/* W3C Markup, IE10 Release Preview */
background-image: ;
z-index: -100;
}
/*#top-banner #banner-right {
width:350px;
height:350px;
background:black;
position:relative;
float: right;
}
#top-banner #banner-right:before {
content:"";
position:absolute;
top:0;
left:0;
width: 0;
height: 0;
border-bottom: 350px solid white;
border-right: 40px solid transparent;
}*/
#top-banner .slider {
float: left;
height: 350px;
width: 100px;
background-color: black;
background-size: cover;
shape-outside: polygon(0 0, 100% 0, 100% 100%, 0 100%);
}
<div id="top-banner">
<div class="container clearfix">
<div id="banner-right">
</div>
<div class="slider">
<img src="http://1.bp.blogspot.com/-9aQmrN3-xpQ/TuYsXHQygrI/AAAAAAAAAtw/cEmz4PgEQdQ/s1600/r-NEW-SPECIES-MEKONG-DELTA-huge.jpg" height="350" alt="banner-1" />
</div>
</div>
</div>
Angled div - 2 methods
The angle is created with transform: rotate and not the linear-gradient.
#1 - Rotated :before with translate 3d
In this example, translate3d(0px,0px,1px) is used to eliminate the jagged edge of the rotated element. More information here. I was reminded about this technique from this answer dealing with a similar rendering problem.
As this is a hack that should be used sparingly, their is an alternative way to mask this edge without it in the second example.
Rotate a pseudo element, :before, of the div. This will create our angled edge
The :before gets an appropriate percentage height, width: 100px and is positioned appropriately
The parent div is given overflow: hidden to cut off the background cleanly
Create a second pseudo element, :after, to extend the background to the edge of the viewport.
The gradient background is applied to :after
The :before pseudo element is given a solid background the same color as the edge of the gradient to blend
The :before and :after pseudo elements are given z-index: 1
Elements that will sit above the "background" will need position: relative and z-index: 2 to push them above it. (Like the paragraph in the example below)
Example
The linear-gradient on the body demonstrates that the div can be placed over any background.
body {
background: linear-gradient(#000 0%, #FFF 100%) no-repeat;
margin: 0;
}
div {
position: relative;
height: 350px;
overflow: hidden;
padding-left: 100px;
min-width: 500px;
}
div:before {
content: '';
display: block;
position: absolute;
height: 120%;
width: 90px;
top: -10%;
left: 90px;
background: #003832;
transform: translate3d(0px,0px,1px) rotate(-15deg);
z-index: 1;
}
div:after {
content: '';
display: block;
position: absolute;
height: 120%;
width: 100%;
top: -10%;
left: 135px;
background: radial-gradient(circle closest-corner at 50% 50%, #33753E 0%, #003832 80%);
z-index: 1;
}
p {
color: #FFF;
left: 10px;
position: relative;
z-index: 2;
}
<div>
<p>This is some text</p>
</div>
#2 - Rotated :before and :after without translate 3d
Rotate a pseudo element, :before, of the div
Apply the background to the pseudo element
The pseudo element gets height: 200% and width: 200% and is positioned appropriately
The parent div is given overflow: hidden to cut off the gradient cleanly and the rotated pseudo element becomes the background
A second pseudo element, :after, is used to help mask the jagged edge with a box-shadow (the left edge is jagged at all rotations that are not 45deg increments)
The :before and :after pseudo elements are given z-index: 1
Elements that will sit above the "background" will need position: relative and z-index: 2 to push them above it. (Like the paragraph in the example below)
Example 1
body {
background: linear-gradient(#000 0%, #FFF 100%) no-repeat;
}
div {
position: relative;
width: 500px;
height: 350px;
overflow: hidden;
padding-left: 100px;
}
div:before,
div:after {
content: '';
display: block;
position: absolute;
height: 200%;
width: 200%;
top: -220px;
left: 90px;
background: radial-gradient(circle closest-corner at 20% 50%, #33753E 0%, #003832 100%);
transform: rotate(-15deg);
z-index: 1;
}
div:after {
top: -220px;
left: 92px;
box-shadow: 0 0 2px 2px #003832;
}
p {
color: #FFF;
z-index: 2;
position: relative;
}
<div>
<p>This is some text</p>
</div>
Example 2 - extended
body {
background: linear-gradient(#000 0%, #FFF 100%) no-repeat;
margin: 0;
}
div {
position: relative;
height: 350px;
overflow: hidden;
padding-left: 100px;
max-width: 1600px;
}
div:before,
div:after {
content: '';
display: block;
position: absolute;
height: 300%;
width: 300%;
top: -200%;
left: 90px;
background: radial-gradient(circle closest-corner at 20% 50%, #33753E 0%, #003832 100%);
transform: rotate(-15deg);
z-index: 1;
}
div:after {
left: 92px;
box-shadow: 0 0 2px 2px #003832;
}
p {
color: #FFF;
z-index: 2;
position: relative;
left: 80px;
}
<div>
<p>This is some text</p>
</div>
If you want it to be exactly as you shown on a picture - try :before pseudoclass.
#div_with_background{
position: relative;
background: radial-gradient(circle closest-corner at 60% 50%, #33753E 0%, #003832 100%);
width: 567px;
height: 356px;
}
#div_with_background:before{
content: "";
position: absolute;
top: 0px;
left: 0px;
width: 0;
height: 0;
border-style: solid;
border-width: 356px 0 0px 130px;
border-color: transparent transparent transparent #FFFFFF;
z-index: 1;
}
<div id="div_with_background"></div>
I'm trying to figure out if there's a way to do this with CSS: I have a container div with a border-radius of 50% (circular). Inside of that is a rectangular div with a height of 30% positioned at the bottom of the container, and I want to be able to mask that off so that anything outside of the container's rounded border radius doesn't show. How do I accomplish this? Attached is a screenshot of what's currently happening, and this is my code:
<div id="coupon_container">
<div id="meter_container">50c off</div>
</div>
#coupon_container {
position: fixed; right:0; top:0; z-index: 100; color: #fff; width:170px; height: 120px;
#meter_container {
position: absolute; width: 110px; height:110px; .round; background: #greenDk; border:5px solid #fff; left: 60px; overflow: hidden;
.meter_level { width: 100%; height:30%; position: absolute; bottom:0; text-align: center; font-size: 1.6em; background: #limeLt; }
}
}
I really like the gradient solution that bookcasey has posted. However, compatibility may be a drawback as IE9 doesn't support CSS gradients. So another solution would be this one:
demo
The idea is to use a top padding of 70% instead of absolute positioning.
HTML:
<div id="coupon_container">
<div id="meter_container">50c off</div>
</div>
CSS:
#coupon_container {
overflow: hidden;
width: 8em; height: 8em;
border-radius: 50%;
background: green;
}
#meter_container {
margin: 70% 0;
height: 30%;
text-align: center;
background: lime;
}
You can achieve the effect you want using CSS3 gradients:
#coupon_container {
width: 100px;
height: 100px;
border-radius: 100px;
background: -webkit-gradient(linear, 50% 0%, 50% 70, color-stop(100%, #fa8072), color-stop(100%, #ff0000));
background: -webkit-linear-gradient(top, #fa8072 70px, #ff0000 70px);
background: -moz-linear-gradient(top, #fa8072 70px, #ff0000 70px);
background: -o-linear-gradient(top, #fa8072 70px, #ff0000 70px);
background: linear-gradient(top, #fa8072 70px, #ff0000 70px);
position: relative;
}
#meter_container {
width: 100px;
text-align: center;
position: absolute;
bottom: 10px;
}
Demo
I could be totally missing something, but couldn't you just add "overflow: hidden;" to the round element, #coupon_container?