I am currently using CSS3 to make an div with the left side angled like a trapezium using the following CSS adapted from this jsfiddle:
background:linear-gradient(75deg, transparent 75px, #35753f 76px);
I would like to combine the following CSS background with a radial one, to create the effect shown in the image below. However, when I do this, I lose the angled side. What is the best way to combine these two backgrounds?
Here is the radial background:
background:radial-gradient(circle closest-corner at right center, #337540 0%, #003832 100%);
Here is what it should look like:
Here is a jsfiddle of the below:
.container {
width: 1024px;
margin: 0 auto;
}
.clearfix:after {
content: ".";
display: block;
height: 0;
clear: both;
visibility: hidden;
}
#top-banner {
position: relative;
}
#top-banner .container {
height: 350px;
}
#top-banner #banner-right {
width: 350px;
height: 350px;
background: -moz-linear-gradient(75deg, transparent 75px, #35753f 76px);
background: -o-linear-gradient(75deg, transparent 75px, #35753f 76px);
background: -webkit-linear-gradient(75deg, transparent 75px, #35753f 76px);
background: linear-gradient(75deg, transparent 75px, #35753f 76px);
position: relative;
float: right;
}
#top-banner #banner-right:after {
content: ".";
display: block;
height: inherit;
width: 5000px;
left: 350px;
top: 0;
position: absolute;
/* IE10 Consumer Preview */
background-image: -ms-radial-gradient(left center, circle closest-corner, #337540 0%, #003832 100%);
/* Mozilla Firefox */
background-image: -moz-radial-gradient(left center, circle closest-corner, #337540 0%, #003832 100%);
/* Opera */
background-image: -o-radial-gradient(left center, circle closest-corner, #337540 0%, #003832 100%);
/* Webkit (Safari/Chrome 10) */
background-image: -webkit-gradient(radial, left center, 0, left center, 140, color-stop(0, #337540), color-stop(1, #003832));
/* Webkit (Chrome 11+) */
background-image: -webkit-radial-gradient(left center, circle closest-corner, #337540 0%, #003832 100%);
/* W3C Markup, IE10 Release Preview */
background-image: ;
z-index: -100;
}
/*#top-banner #banner-right {
width:350px;
height:350px;
background:black;
position:relative;
float: right;
}
#top-banner #banner-right:before {
content:"";
position:absolute;
top:0;
left:0;
width: 0;
height: 0;
border-bottom: 350px solid white;
border-right: 40px solid transparent;
}*/
#top-banner .slider {
float: left;
height: 350px;
width: 100px;
background-color: black;
background-size: cover;
shape-outside: polygon(0 0, 100% 0, 100% 100%, 0 100%);
}
<div id="top-banner">
<div class="container clearfix">
<div id="banner-right">
</div>
<div class="slider">
<img src="http://1.bp.blogspot.com/-9aQmrN3-xpQ/TuYsXHQygrI/AAAAAAAAAtw/cEmz4PgEQdQ/s1600/r-NEW-SPECIES-MEKONG-DELTA-huge.jpg" height="350" alt="banner-1" />
</div>
</div>
</div>
Angled div - 2 methods
The angle is created with transform: rotate and not the linear-gradient.
#1 - Rotated :before with translate 3d
In this example, translate3d(0px,0px,1px) is used to eliminate the jagged edge of the rotated element. More information here. I was reminded about this technique from this answer dealing with a similar rendering problem.
As this is a hack that should be used sparingly, their is an alternative way to mask this edge without it in the second example.
Rotate a pseudo element, :before, of the div. This will create our angled edge
The :before gets an appropriate percentage height, width: 100px and is positioned appropriately
The parent div is given overflow: hidden to cut off the background cleanly
Create a second pseudo element, :after, to extend the background to the edge of the viewport.
The gradient background is applied to :after
The :before pseudo element is given a solid background the same color as the edge of the gradient to blend
The :before and :after pseudo elements are given z-index: 1
Elements that will sit above the "background" will need position: relative and z-index: 2 to push them above it. (Like the paragraph in the example below)
Example
The linear-gradient on the body demonstrates that the div can be placed over any background.
body {
background: linear-gradient(#000 0%, #FFF 100%) no-repeat;
margin: 0;
}
div {
position: relative;
height: 350px;
overflow: hidden;
padding-left: 100px;
min-width: 500px;
}
div:before {
content: '';
display: block;
position: absolute;
height: 120%;
width: 90px;
top: -10%;
left: 90px;
background: #003832;
transform: translate3d(0px,0px,1px) rotate(-15deg);
z-index: 1;
}
div:after {
content: '';
display: block;
position: absolute;
height: 120%;
width: 100%;
top: -10%;
left: 135px;
background: radial-gradient(circle closest-corner at 50% 50%, #33753E 0%, #003832 80%);
z-index: 1;
}
p {
color: #FFF;
left: 10px;
position: relative;
z-index: 2;
}
<div>
<p>This is some text</p>
</div>
#2 - Rotated :before and :after without translate 3d
Rotate a pseudo element, :before, of the div
Apply the background to the pseudo element
The pseudo element gets height: 200% and width: 200% and is positioned appropriately
The parent div is given overflow: hidden to cut off the gradient cleanly and the rotated pseudo element becomes the background
A second pseudo element, :after, is used to help mask the jagged edge with a box-shadow (the left edge is jagged at all rotations that are not 45deg increments)
The :before and :after pseudo elements are given z-index: 1
Elements that will sit above the "background" will need position: relative and z-index: 2 to push them above it. (Like the paragraph in the example below)
Example 1
body {
background: linear-gradient(#000 0%, #FFF 100%) no-repeat;
}
div {
position: relative;
width: 500px;
height: 350px;
overflow: hidden;
padding-left: 100px;
}
div:before,
div:after {
content: '';
display: block;
position: absolute;
height: 200%;
width: 200%;
top: -220px;
left: 90px;
background: radial-gradient(circle closest-corner at 20% 50%, #33753E 0%, #003832 100%);
transform: rotate(-15deg);
z-index: 1;
}
div:after {
top: -220px;
left: 92px;
box-shadow: 0 0 2px 2px #003832;
}
p {
color: #FFF;
z-index: 2;
position: relative;
}
<div>
<p>This is some text</p>
</div>
Example 2 - extended
body {
background: linear-gradient(#000 0%, #FFF 100%) no-repeat;
margin: 0;
}
div {
position: relative;
height: 350px;
overflow: hidden;
padding-left: 100px;
max-width: 1600px;
}
div:before,
div:after {
content: '';
display: block;
position: absolute;
height: 300%;
width: 300%;
top: -200%;
left: 90px;
background: radial-gradient(circle closest-corner at 20% 50%, #33753E 0%, #003832 100%);
transform: rotate(-15deg);
z-index: 1;
}
div:after {
left: 92px;
box-shadow: 0 0 2px 2px #003832;
}
p {
color: #FFF;
z-index: 2;
position: relative;
left: 80px;
}
<div>
<p>This is some text</p>
</div>
If you want it to be exactly as you shown on a picture - try :before pseudoclass.
#div_with_background{
position: relative;
background: radial-gradient(circle closest-corner at 60% 50%, #33753E 0%, #003832 100%);
width: 567px;
height: 356px;
}
#div_with_background:before{
content: "";
position: absolute;
top: 0px;
left: 0px;
width: 0;
height: 0;
border-style: solid;
border-width: 356px 0 0px 130px;
border-color: transparent transparent transparent #FFFFFF;
z-index: 1;
}
<div id="div_with_background"></div>
Related
I created a triangle like so using css:
.box {
width: 0;
height: 0;
border-style: solid;
border-width: 540px 964px 540px 0;
border-color: transparent #007bff transparent transparent;
}
But I am trying to make my triangle look like this:
My question is how do I make the top and bottom more edge to edge?
You could use :after pseudo element to create one square and then use rotate and translate transforms.
.element {
display: inline-block;
background: lightgreen;
position: relative;
width: 200px;
height: 200px;
overflow: hidden;
}
.two {
margin-left: 30px;
width: 300px;
height: 300px;
}
.element:after {
content: "";
position: absolute;
width: 120%;
height: 120%;
background: #30373F;
transform: rotate(45deg) translate(10%, -20%);
}
<div class="element"></div>
<div class="element two"></div>
You can easily do this with gradient:
.box {
width:200px;
height:200px;
background:
linear-gradient(red,red) right/30% 100%,
linear-gradient(to top left,red 49.8%,transparent 50%) top left/70% 50%,
linear-gradient(to bottom left,red 49.8%,transparent 50%) bottom left/70% 50%,
url(https://picsum.photos/600/600?image=1069) center/cover;
background-repeat:no-repeat;
}
<div class="box">
</div>
I want to cut left top corner of a box using CSS like this.
keep in mind that background is transparent.
Nearly the same solution as OriDrori's answer but more flexible (if you need fixed-width cutted corner).
This gradient will look the same regardless of .card width and height.
body {
background: purple;
}
.card {
width: 200px;
height: 200px;
background: linear-gradient(135deg, transparent 20px, white 20px);
}
<div class="card"></div>
You can use a simple linear gradient for that:
body {
background: purple;
}
.card {
width: 200px;
height: 200px;
background: linear-gradient(to bottom right, transparent 5%, white 5%);
}
<div class="card"></div>
You can use clip-path
https://developer.mozilla.org/en/docs/Web/CSS/clip-path
and use something like this:
div#test{
background:red;
width:200px;
height: 200px;
-webkit-clip-path: polygon(22% 0, 100% 0, 100% 100%, 0 100%, 0 20%);
clip-path: polygon(22% 0, 100% 0, 100% 100%, 0 100%, 0 20%);
}
<div id="test"></div>
With a pseudo and transform you can do that, and it has good browser support (from IE9)
body {
background: url(https://picsum.photos/400/300) center / cover;
}
div {
position: relative;
width: 200px;
height: 200px;
overflow: hidden;
}
div::before {
content: '';
position: absolute;
left: calc(50% + 25px); /* 25px is height/width of the cut */
top: calc(50% + 25px);
width: 141.5%;
height: 141.5%;
transform: translate(-50%,-50%) rotate(45deg);
background: #eee;
opacity: 0.8;
}
<div></div>
As pointed out, if you need it to scale on different aspect ratio's, use this
body {
background: url(https://picsum.photos/400/300) center / cover;
}
div {
position: relative;
width: 80vw;
height: 80vh;
overflow: hidden;
}
div::before {
content: '';
position: absolute;
left: 0;
top: 0;
width: 1000%;
height: 5000%;
transform: rotate(45deg) translate(25px,-50%); /* 25px for the cut height/width */
transform-origin: left top;
background: #eee;
opacity: 0.8;
}
<div></div>
I am trying to achieve this effect in CSS:
This is my code:
#test {position: relative;margin: 100px;}
#test::after {
background-color: maroon;
box-shadow: 0 -50px 10px 7px gray;
height: 45px;
left: -15px;
position: absolute;
top: 40px;
transform: perspective(150px) rotateX(-45deg);
transform-origin: center bottom 0;
width: 60px;
content: "";
}
<div id="test"></div>
but I am not achieving the expected result with the cast shadow. I wonder if its even possible to do this with CSS only?
Fiddle Demo
Maybe something like this? I added another element representing the shadow:
#shadow {
height: 90px;
left: -15px;
position: absolute;
top: 30px;
background: rgba(0, 0, 0, 0);
width: 60px;
transform: perspective(50px) rotateX(25deg);
box-shadow: 0 -106px 20px 17px #808080;
}
https://jsfiddle.net/zcyy09mp/4/
As mentioned in my comment, I would generally recommend the approach used in my fiddle (which is, use another pseudo-element) or the one in Martin's answer (which is, to use an extra element) but as you've mentioned that the other pseudo-element is already used and you are trying to avoid any extra elements, the other approach is to use gradients as background for the parent element. By using the appropriate side-to-side gradients with background-position, background-size, we can not only get the shape but also an effect very similar to the blurred nature of the shadow.
Below is a sample snippet: (the output is also reasonably responsive as you can see by hovering it)
#test {
position: relative;
height: 100px;
width: 100px;
margin: 100px;
background: linear-gradient(to bottom right, transparent 45%, gray 55%), linear-gradient(to bottom left, transparent 45%, gray 55%), linear-gradient(to bottom, transparent, gray), linear-gradient(gray, gray);
background-repeat: no-repeat;
background-size: 30px 95%, 30px 95%, calc(100% - 60px) 8px, calc(100% - 60px) calc(100% - 8px);
background-position: 0% 100%, 100% 100%, 50% 4px, 50% 100%;
}
#test::after {
position: absolute;
content: "";
background-color: maroon;
width: 100%;
height: 45%;
left: 0px;
top: 100%;
transform: perspective(150px) rotateX(-45deg);
transform-origin: center top 0;
}
/* just for demo */
#test {
transition: all 1s;
}
#test:hover {
height: 200px;
width: 200px;
}
<div id="test"></div>
In the below snippet, I have given a different color for each of the gradient just to visually show how it is achieved.
#test {
position: relative;
height: 100px;
width: 100px;
margin: 100px;
background: linear-gradient(to bottom right, transparent 45%, red 55%), linear-gradient(to bottom left, transparent 45%, blue 55%), linear-gradient(to bottom, transparent, green), linear-gradient(rebeccapurple, rebeccapurple);
background-repeat: no-repeat;
background-size: 30px 95%, 30px 95%, calc(100% - 60px) 8px, calc(100% - 60px) calc(100% - 8px);
background-position: 0% 100%, 100% 100%, 50% 4px, 50% 100%;
}
#test::after {
position: absolute;
content: "";
background-color: maroon;
width: 100%;
height: 45%;
left: 0px;
top: 100%;
transform: perspective(150px) rotateX(-45deg);
transform-origin: center top 0;
}
/* just for demo */
#test {
transition: all 1s;
}
#test:hover {
height: 200px;
width: 200px;
}
<div id="test"></div>
According to the W3 spec, "the 'box-shadow' property attaches one or more drop-shadows to the box". The shadow you want to create is not a drop shadow so there is no CSS that would make the shadow in the picture.
The closest you could achieve is pushing the shadow off one edge by using a negative spread radius:
body {
padding-top: 50px;
}
#test {
margin: 0 auto;
background-color: maroon;
box-shadow: 0 -20px 7px -6px black;
height: 45px;
width: 60px;
transform: perspective(150px) rotateX(-45deg);
transform-origin: center bottom 0;
}
<div id="test"></div>
So I have a div, content of which should always be crossed out diagonally.
I've tried few solutions with few elements that had absolute positions but it wasn't good enough, because content and size of the div that should be crossed out can vary, so crossing out should be adaptive as well.
Basically I need to make something like this: http://www.awesomescreenshot.com/0515d31j22
This should work for you.
.strike {
position: relative;
display: inline-block;
}
.strike:before {
content: "";
position: absolute;
height: 1px;
width: 120%;
background: red;
top: 50%;
left: 50%;
transform: translate(-50%, -50%) rotate(25deg);
}
<div class="strike">$55.55</div>
<br><br>
<div class="strike">$555.55</div>
<br><br>
<div class="strike">$5555.55</div>
A couple of linear gradients can do this and it will auto-size to the dimensions of the element and no degree notation is required.
div {
width: 25%;
height: 250px;
margin: 1em auto;
border:1px solid grey;
position: relative;
}
div:after {
content: '';
position: absolute;
width: 100%;
height: 100%;
top:0;
left: 0;
background:
linear-gradient(to bottom left, transparent 0%, transparent 50%, red 51%, transparent 51%, transparent 100%),
linear-gradient(to bottom right, transparent 0%, transparent 50%, red 51%, transparent 51%, transparent 100%);
}
<div></div>
I'm trying to figure out if there's a way to do this with CSS: I have a container div with a border-radius of 50% (circular). Inside of that is a rectangular div with a height of 30% positioned at the bottom of the container, and I want to be able to mask that off so that anything outside of the container's rounded border radius doesn't show. How do I accomplish this? Attached is a screenshot of what's currently happening, and this is my code:
<div id="coupon_container">
<div id="meter_container">50c off</div>
</div>
#coupon_container {
position: fixed; right:0; top:0; z-index: 100; color: #fff; width:170px; height: 120px;
#meter_container {
position: absolute; width: 110px; height:110px; .round; background: #greenDk; border:5px solid #fff; left: 60px; overflow: hidden;
.meter_level { width: 100%; height:30%; position: absolute; bottom:0; text-align: center; font-size: 1.6em; background: #limeLt; }
}
}
I really like the gradient solution that bookcasey has posted. However, compatibility may be a drawback as IE9 doesn't support CSS gradients. So another solution would be this one:
demo
The idea is to use a top padding of 70% instead of absolute positioning.
HTML:
<div id="coupon_container">
<div id="meter_container">50c off</div>
</div>
CSS:
#coupon_container {
overflow: hidden;
width: 8em; height: 8em;
border-radius: 50%;
background: green;
}
#meter_container {
margin: 70% 0;
height: 30%;
text-align: center;
background: lime;
}
You can achieve the effect you want using CSS3 gradients:
#coupon_container {
width: 100px;
height: 100px;
border-radius: 100px;
background: -webkit-gradient(linear, 50% 0%, 50% 70, color-stop(100%, #fa8072), color-stop(100%, #ff0000));
background: -webkit-linear-gradient(top, #fa8072 70px, #ff0000 70px);
background: -moz-linear-gradient(top, #fa8072 70px, #ff0000 70px);
background: -o-linear-gradient(top, #fa8072 70px, #ff0000 70px);
background: linear-gradient(top, #fa8072 70px, #ff0000 70px);
position: relative;
}
#meter_container {
width: 100px;
text-align: center;
position: absolute;
bottom: 10px;
}
Demo
I could be totally missing something, but couldn't you just add "overflow: hidden;" to the round element, #coupon_container?