Using rpmbuild when source tar directory doesn't correspond to name-version - rpmbuild

Question

I'm trying to build an rpm from source-1.4.3-linux.tgz (that is downloaded so I don't control the name) and the file untars into the directory source-1.4.3-linux. In my source.spec file, I have
Name: source
Version: 1.4.3
So it is probably quite logical that I am getting an error:
cd: source-1.4.3: No such file or directory.
I tried tacking -linux onto the version, but rpmbuild wants only a number there. What do I have to do to tell rpmbuild that the source files are untarred into source-1.4.3-linux?

Answer 1

Just use the setup macro.
setup -n %{name}-%{version}.linux

Answer 2

Here is a simple.spec file that would help you understand the issue. Source tarball contains the following:
$ tar tzf simple-0.tar.gz
simple-0/
simple-0/simple.txt
Spec file:
Summary: Simple SPEC
Name: simple
Version: 0
Release: 1
License: NONE
Group: NONE
URL: NONE
Source0: %{name}-%{version}.tar.gz
BuildRoot: %{_tmppath}/%{name}-%{version}-%{release}-root
%description
" This is Simple "
%prep
%setup -q
%build
%install
rm -rf $RPM_BUILD_ROOT
mkdir -p $RPM_BUILD_ROOT/tmp/
install -m 0644 simple.txt %{buildroot}/tmp/simple.txt
%clean
rm -rf $RPM_BUILD_ROOT
%post
echo "In the Post section of Simple"
%files
%defattr(-,root,root,-)
%doc
/tmp/simple.txt
%changelog
* Wed Sep 12 2018 <iamauser#localdomain> -
- Initial build.

Answer 3

ok I got this working. Maybe a hack but it is working. As per the question my tarball is unconventionally named.
$ tar tzf source-1.4.3-linux-amd64.tar.gz
source-1.4.3-linux-amd64/
source-1.4.3-linux-amd64/simple.txt
in the specfile %prep section instead of using %setup or %autosetup, I unpacked manually and renamed the untarred directory.
Name: source
Version: 1.4.3
Release: 0
Source0: https://example.com/%{name}-%{version}-linux-amd64.tar.bz2
%prep
rm -fr %{name}-%{version}
tar -xjf %{SOURCE0}
mv %{name}-%{version}-linux-amd64 %{name}-%{version}