Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 4 years ago.
Improve this question
I would like to calculate Mann Attached imageKendall statistics in R. i have an excel sheet with rainfall and years. how would i best get it
Looking at the attached image you should not put Book1$Mean in quotes. Try using:
MannKendall(Book1$Mean)
Related
Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 6 days ago.
Improve this question
Code:
data(tips)
tips%>%
group_by(sex)%>%
summarize(variance=var(tip))
Output:
variance
1 1.914455
The output isn't the desired one. The result should be a tibble with variance computed against each group (in this case, sex). The summarize function is computing the variance of the entire tip column, rather than calculating the variance of each group.
Tried executing the code and restarting RStudio several times, but it didn't work.
Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 4 years ago.
Improve this question
I am doing an exercise to create a function. One of the questions is:
"We can estimate the cumulative risk of an certain event using the
exponential formula
1-exp(-1/10000*t) where t is the time to the event. Create a function ans(t), which returns the risk at time t.
and I am using this command:
function(t){ans(t)<-1-exp(-1/10000*t)return(ans(t))}
but it is giving wrong answer. Can someone help me to understand this please?
The proper format to define a function is this:
ans<-function(t){
answer<-1-exp(-1/10000*t)
return(answer)
}
ans(1)
#[1] 9.9995e-05
Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 5 years ago.
Improve this question
(USING R)
So I imported a data set by using
xcars <- read.csv(file.choose())
and then I chose my data set which was originally an excel file.
So, I have a column named dist (short for displacement) and I want to choose the first 25 entries underneath that column and then plot it on a histogram, so I attempted the following.
carsUpTo25 <- xcars(1:25,)
hist(carsUpTo25$dist)
Of course this didn't work. However, any help on how I would do this would be helpful.
Try this-
hist(xcars[,dist[1:10]])
Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 6 years ago.
Improve this question
Im taking an R programming class that is using the package "matplot" for a demo. I cant find "matplot" in CRAN so i'm assuming it has been replaced/deleted/changed. Is there another package that replaced it?
There is a matplot function within the graphics library. Here's an example from the documentation:
require(grDevices)
matplot((-4:5)^2, main = "Quadratic")
Also, matplot is a plotting library for PHP. Perhaps your instructor could help clarify what is expected.
Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 7 years ago.
Improve this question
I'm trying to do a simple calculation with my mean function. When I input mean(1, 10, 100), R returns 1, which is obviously not the correct average. It always returns the first entry of my vector. What went wrong?
You should use mean(c(1,10,100))
See http://www.rdocumentation.org/packages/base/functions/c