How to choose the first "n" elements in R [closed] - r

Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 5 years ago.
Improve this question
(USING R)
So I imported a data set by using
xcars <- read.csv(file.choose())
and then I chose my data set which was originally an excel file.
So, I have a column named dist (short for displacement) and I want to choose the first 25 entries underneath that column and then plot it on a histogram, so I attempted the following.
carsUpTo25 <- xcars(1:25,)
hist(carsUpTo25$dist)
Of course this didn't work. However, any help on how I would do this would be helpful.

Try this-
hist(xcars[,dist[1:10]])

Related

The length() function is not returning the right number [closed]

Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 7 months ago.
Improve this question
I working with a csv that has 234 rows. I thought the length() function was supposed to return the number of rows in my csv, but it returns a much larger number. It gives me 1046860. Does the length function not do what I think it does? What is going on?
I just wanted to double check the length and haven't run any other code yet other than setting up my working directory and attaching a file (Cat6 <- read.csv("Category6.csv")).

Countryref to dataframe [closed]

Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 3 years ago.
Improve this question
I came across the R countryref package: https://www.rdocumentation.org/packages/CoordinateCleaner/versions/2.0-11/topics/countryref
A data.frame with coordinates of country and province centroids and
country capitals as reference for the clean_coordinates, cc_cen and
cc_cap functions. Coordinates are based on the Central Intelligence
Agency World Factbook
https://www.cia.gov/library/publications/the-world-factbook/ and
http://thematicmapping.org/downloads/world_borders.php.
Apparently, I can display part of the data via
data(countryref)
head(countryref)
However, my question is: How can I send the data into a new dataframe and export it as CSV?
You can export a data frame as csv using write.csv (for example write.csv(x, "filename.csv").

How to fix this function? [closed]

Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 4 years ago.
Improve this question
I am doing an exercise to create a function. One of the questions is:
"We can estimate the cumulative risk of an certain event using the
exponential formula
1-exp(-1/10000*t) where t is the time to the event. Create a function ans(t), which returns the risk at time t.
and I am using this command:
function(t){ans(t)<-1-exp(-1/10000*t)return(ans(t))}
but it is giving wrong answer. Can someone help me to understand this please?
The proper format to define a function is this:
ans<-function(t){
answer<-1-exp(-1/10000*t)
return(answer)
}
ans(1)
#[1] 9.9995e-05

How to calculate Mann Kendall Statistics in R [closed]

Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 4 years ago.
Improve this question
I would like to calculate Mann Attached imageKendall statistics in R. i have an excel sheet with rainfall and years. how would i best get it
Looking at the attached image you should not put Book1$Mean in quotes. Try using:
MannKendall(Book1$Mean)

for loop in data frame in R [closed]

Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 5 years ago.
Improve this question
I am new in R and I would like to ask what is wrong in the following simple command. When i try:
for (k in 1:1){
logdata= logDataset[1:74+k,k]}
logdata collects the values from rows 2:75 of column 1 of the logDataset data frame. But when I use:
logdata=logDataset[1:75,1]
logdata collects correctly the first 75 values of the first column. Why the first command does not work as the second one? How can I use the "for" command for collecting the first 75 values of the first column? Many thanks.

Resources