Is it possible to programmatically create a Grid that has 3 rows and 2 columns, but the last row only has 1 column instead of 2?
public class MyGrid : Grid
{
public void DefineRowsAndColumns()
{
// I know you can add RowDefinitions and ColumnDefinitions here, but how to make them uneven?
}
}
I'm not trying to get someone to do my homework here...I just want to know how I can get a grid to have rows with different number of columns.
you can use the ColumnSpan property to make content span multiple columns
var label = new Label { Text = "Row 1" };
myGrid.Children.Add(label,0,0);
Grid.SetColumnSpan(label,2);
the Label will span 2 columns, effectively making that row contain only a single column
Related
This question already has answers here:
One flex/grid item sets the size limit for siblings
(6 answers)
Closed 3 years ago.
There a ton of answers on SO on how to make columns equal height based upon the content of the largest column, however I am looking to make all columns equal height based upon the smallest column.
In this example, I want all columns to have the same height as the middle column and the content within the two larger columns to scroll. I am using Bootstrap 4 but am open to any other solutions.
You might have to use javascript.
Store all the column heights into an array.
Loop through and pick the smallest height.
Set the height of the other divs based on the smallest height.
// Get all the columns
const columns = document.querySelectorAll('.column');
// Array for storing height values for columns
var columnHeights= [];
// Add Column Heights to array
for(index=0; index<columns.length; index++) {
column= columns[index];
columnHeights.push(column.getBoundingClientRect().height);
}
// Get the minimum column height
Array.min = function(heightsArray){
return Math.min.apply( Math, heightsArray );
};
var minimumHeight = Array.min(columnHeights);
// Set the height of the other columns based on the minimum height
columns.forEach(col => {
col.style.height = minimumHeight+'px';
});
A working pen is here
I have a grid using this store:
MyStore = Ext.create('Ext.data.ArrayStore',{
data : [
['field1'],
['field2'],
['field3']
],
fields : [{name:'title'}]
});
So i get a grid with 3 rows and 1 column.
I create an event that when i select a row in another grid the content of row 1 in this grid change (for example 'field1' becomes 'field4').
This code makes me get the content of the row: MyStore.data.items[0].data.title
But i don't know how to change it in the grid
I hope my question is clear and thank you for helping.
Try this:
MyStore.getAt(0).set('title', 'field4');
i would like to have one list select that will have more than one style, i put two kinds of object's one is a group of users (bold), rest are users (italic or regular) is it possible to add style that will be added to part of added obj?
My code looks like this:
for(Usr usr: userSearchResult){
listSelect.addItem(usr);
}
listSelect.addStyleName("bold");
for (Gr gr : groupSearchResult) {
searchList.addItem(gr);
}
and also have style set in css correct similar to this
.v-select-bold .v-select-select {
font-weight:bold;}
i would be glad to solve this by myself but that was two days ago now i'm in a dot ;)
Thanks in advance for help!
You can store your row as a label with style. In the container there will be a label instance. There you can simply add the style.
Container container = new IndexedContainer();
container.addContainerProperty(NAME_PROPERTY, Label.class , "");
for (int i = 0; i <= 50 ; i++) {
Item item = container.addItem(i);
Label label = new Label(HashUtils.getRandomSalt());
label.addStyleName(style)
item.getItemProperty(NAME_PROPERTY).setValue();
}
return container;
You can't style rows of a ListSelect. You can use a Table component with one column to achieve a similar result. Table.setCellStyleGenerator method is used for differentiating styles for each cell (each row in your case).
I have a clustered chart with 2 column series. The problem is that sometimes one column's values are so large, the other column is dwarfed. So I added checkboxes to show/hide a given column, and set the visibility of the ColumnSeries as such:
visible="{checkbox.selected}" includeInLayout="{checkbox.selected}"
This shows/hides the given column correctly, the problem is that it does not reset the Y-Axis, so the other column never actually grows in height (when the column with the larger values is hidden). I've tried resetting the data provider, validating/invalidating the chart, and nothing seems to work.
Anyone have any ideas?
Thanks!
I would imagine from your description that you actually need to remove the series from the chart. So
public function onToggle(){
var newSeries:Array = [];
if(bigSeries.selected) {
newSeries.push(bigSeries);
}
if(smallSeries.selected) {
newSeries.push(smallSeries);
}
chart.series = newSeries;
}
HI,
In flex, I have a datagrid with 22 columns. I initially display all the columns. The width of each column right is uniform.
Now when i change the visiblity of a few columns, the width of each column varies. How do i maintain a uniform column width for each column whether or not there are any invisible columns?...
Also how do i get the count of number of visible columns. the ColumnCount property returns total number of columns and not the number of visible ones.
The columns are an array, so you can append code to whatever function makes them invisible and loop through that array setting each ones width. You will just need to keep tabs on your Datagrids width, and the number of visible columns, which you can also do with a loop. Here's some untested code that should put you close to your goal:
function makeAColInvisible():void{
//code you use to set col invisible
var visColCount:number = 0;
for each (var item:DataGridColumn in myDataGrid.columns){
if(item.visible == true){
visColCount++;
}
}
for each (var item2:DataGridColumn in myDataGrid.columns){
item2.width = myDataGrid.width / visColCount;
}
}